AP Biology Practice Test 13 – 60 Questions with Answers (College Board)

Work through all 60 AP Biology questions, checking each answer as you go to build confidence for your AP Biology exam.

Chemistry of Life

Q1. Water molecules stick to each other and to the walls of xylem vessels. Which pair of properties allows water to rise in tall trees?

  • (A) Hydrophobic exclusion and surface tension only
  • (B) High heat of vaporisation and low density
  • (C) Capillary action of oils and waxes
  • (D) Cohesion and adhesion
Show Answer

Answer: D – Cohesion holds water molecules together and adhesion holds them to vessel walls, supporting transpiration pull.

Q2. At 25 degrees C, a solution has a pH of 4. What is its hydroxide ion concentration?

  • (A) 10-10 M
  • (B) 10-4 M
  • (C) 10-7 M
  • (D) 104 M
Show Answer

Answer: A – pOH = 14 – 4 = 10, so [OH–] = 10-10 M.

Q3. Which functional group is found in amino acids and gives them their ability to act as both acids and bases?

  • (A) Only a phosphate group
  • (B) Both an amino group and a carboxyl group
  • (C) Only a hydroxyl group
  • (D) Only a methyl group
Show Answer

Answer: B – The amino group can accept a proton and the carboxyl group can donate one.

Q4. Cellulose is indigestible by most animals. What structural feature explains this?

  • (A) Alpha 1-6 branches that block digestion
  • (B) The presence of nitrogen in every glucose unit
  • (C) Beta 1-4 glycosidic bonds that most animals lack enzymes to break
  • (D) Covalent bonds between cellulose and DNA
Show Answer

Answer: C – Human and most animal enzymes hydrolyse alpha linkages, not the beta linkages of cellulose.

Q5. A fat is described as unsaturated. What does this mean?

  • (A) It contains no carbon atoms
  • (B) It is solid at room temperature because of tight packing
  • (C) Its fatty-acid chains contain one or more double bonds
  • (D) It has three phosphate groups
Show Answer

Answer: C – Double bonds create kinks that prevent tight packing, so unsaturated fats are usually liquid oils.

Q6. Which level of protein structure is determined by hydrogen bonding between backbone atoms to form alpha helices and beta sheets?

  • (A) Primary structure
  • (B) Tertiary structure
  • (C) Secondary structure
  • (D) Quaternary structure
Show Answer

Answer: C – Secondary structure is the local folding of the polypeptide backbone.

Q7. A DNA molecule is found to contain 22 percent adenine. What percentage of its bases are guanine?

  • (A) 28 percent
  • (B) 22 percent
  • (C) 44 percent
  • (D) 56 percent
Show Answer

Answer: A – A pairs with T, so T is also 22 percent; the remaining 56 percent is G plus C, so G is 28 percent.

Cell Structure and Function

Q8. Which cell structure is responsible for producing most of the cell’s ATP in eukaryotes?

  • (A) The mitochondrion
  • (B) The chloroplast in animal cells
  • (C) The nucleus
  • (D) The smooth endoplasmic reticulum
Show Answer

Answer: A – Mitochondria carry out oxidative phosphorylation.

Q9. A cell is observed to have many ribosomes attached to membranes and a large Golgi apparatus. What is this cell most likely specialised for?

  • (A) Secreting proteins
  • (B) Storing lipids
  • (C) Photosynthesis
  • (D) Contracting as a muscle
Show Answer

Answer: A – Abundant rough ER and Golgi indicate high protein secretion.

Q10. Oxygen diffuses from the alveoli into the blood. Which factor increases the rate of this diffusion?

  • (A) A thick membrane and a small surface area
  • (B) A large surface area and a short diffusion distance
  • (C) A low concentration gradient
  • (D) A decrease in temperature to freezing
Show Answer

Answer: B – Fick’s law: rate rises with surface area and gradient, and falls with distance.

Q11. A marine fish drinks seawater and excretes excess salt through its gills. This is an example of

  • (A) thermoregulation to maintain body temperature
  • (B) photosynthesis to make food
  • (C) osmoregulation to maintain internal salt balance
  • (D) fermentation to produce ATP
Show Answer

Answer: C – Osmoregulation controls water and solute balance against the environment.

Q12. Which molecule can pass directly through the lipid bilayer without a transport protein?

  • (A) Glucose
  • (B) Sodium ions
  • (C) Amino acids
  • (D) Oxygen
Show Answer

Answer: D – Small nonpolar molecules such as O2 diffuse directly through the bilayer.

Q13. The cytoskeleton includes microtubules, microfilaments and intermediate filaments. Which function is primarily associated with microtubules?

  • (A) Forming the spindle and moving organelles along tracks
  • (B) Producing ATP by chemiosmosis
  • (C) Synthesising proteins
  • (D) Storing calcium ions
Show Answer

Answer: A – Microtubules organise the spindle and serve as tracks for vesicle transport.

Q14. A prokaryotic cell is distinguished from a eukaryotic cell by the absence of

  • (A) a plasma membrane
  • (B) a membrane-bound nucleus and other membrane-bound organelles
  • (C) ribosomes
  • (D) a cell wall
Show Answer

Answer: B – Prokaryotes lack a true nucleus and membrane-bound organelles.

Cellular Energetics

Q15. A reaction has a positive delta G. How can a cell drive this reaction forward?

  • (A) By coupling it to ATP hydrolysis, which releases energy
  • (B) By lowering the temperature to absolute zero
  • (C) By removing all enzymes from the cell
  • (D) By increasing the concentration of products
Show Answer

Answer: A – Endergonic reactions are driven by coupling to exergonic ATP hydrolysis.

Q16. An enzyme’s activity is highest at 37 degrees C and falls sharply at 60 degrees C. The most likely cause of the fall is

  • (A) increased substrate concentration at high temperature
  • (B) competitive inhibition by heat
  • (C) denaturation of the enzyme at high temperature
  • (D) activation of the enzyme by heat
Show Answer

Answer: C – High temperature disrupts the weak bonds maintaining enzyme shape.

Q17. In mitochondria, protons are pumped into the intermembrane space during electron transport. How is the energy stored in this proton gradient used to make ATP?

  • (A) Protons donate electrons directly to ADP to form ATP
  • (B) Protons flow back through ATP synthase, driving the phosphorylation of ADP
  • (C) The gradient splits water molecules, releasing ATP
  • (D) Protons are reduced by NADH to form ATP in the matrix
Show Answer

Answer: B – Chemiosmosis: the proton-motive force drives protons through ATP synthase, which couples the flow to ATP synthesis.

Q18. In photosynthesis, ATP is made by photophosphorylation. Where does this occur?

  • (A) In the stroma, by substrate-level phosphorylation
  • (B) In the thylakoid membrane, using a proton gradient
  • (C) In the cytoplasm during glycolysis
  • (D) In the mitochondrial matrix
Show Answer

Answer: B – Light-driven electron transport creates a proton gradient that drives ATP synthase in the thylakoid.

Q19. A plant is grown in an atmosphere with a very high oxygen concentration and low carbon dioxide. What is the expected effect on photosynthesis?

  • (A) The Calvin cycle fixes carbon faster
  • (B) Oxygen replaces water as the electron donor
  • (C) Photorespiration increases, reducing the efficiency of carbon fixation
  • (D) Stomata close permanently and photosynthesis stops
Show Answer

Answer: C – Rubisco can bind oxygen instead of CO2, leading to photorespiration.

Q20. During fermentation in human muscle cells, pyruvate is converted to lactate. What is the net ATP yield per glucose in this process?

  • (A) 38 ATP
  • (B) 2 ATP
  • (C) 0 ATP
  • (D) 4 ATP
Show Answer

Answer: B – Anaerobic glycolysis yields a net 2 ATP per glucose; lactate formation regenerates NAD+.

Q21. How many ATP molecules are produced by substrate-level phosphorylation per glucose in aerobic respiration?

  • (A) 2 ATP
  • (B) 32 ATP
  • (C) 4 ATP
  • (D) 6 ATP
Show Answer

Answer: C – Glycolysis and the Krebs cycle together produce 4 ATP by substrate-level phosphorylation per glucose.

Cell Communication and Cell Cycle

Q22. A ligand binds to a receptor tyrosine kinase. What typically happens next?

  • (A) The ligand enters the nucleus and binds DNA
  • (B) The receptor is destroyed immediately
  • (C) The receptor dimerises and phosphorylates itself and target proteins
  • (D) Cyclic AMP is released from the receptor
Show Answer

Answer: C – Receptor tyrosine kinases activate by dimerisation and autophosphorylation.

Q23. In the fight-or-flight response, adrenaline increases heart rate within seconds. Why is the response so rapid?

  • (A) Adrenaline is stored in the heart muscle itself
  • (B) The signal is relayed through the nervous system and fast second-messenger cascades
  • (C) The response relies on slow gene transcription
  • (D) Adrenaline diffuses directly into heart cells and binds DNA
Show Answer

Answer: B – Neural signals and amplified cascades produce responses in seconds.

Q24. A bacterial cell detects a chemical gradient and moves toward food. This behaviour depends on

  • (A) meiosis and crossing over
  • (B) photosynthesis in the bacterial cytoplasm
  • (C) apoptosis of neighbouring cells
  • (D) a two-component signalling system with a sensor kinase and a response regulator
Show Answer

Answer: D – Two-component systems let bacteria sense and respond to environmental signals.

Q25. Negative feedback in the control of blood glucose involves insulin and glucagon. When blood glucose falls, what happens?

  • (A) Glucagon is released and stimulates glycogen breakdown in the liver
  • (B) Insulin release increases
  • (C) Glucose is stored as glycogen
  • (D) The pancreas stops producing hormones
Show Answer

Answer: A – Glucagon raises blood glucose by promoting glycogenolysis.

Q26. A cell that is not dividing enters G0. Which cells commonly remain in G0?

  • (A) Embryonic stem cells
  • (B) Mature nerve cells
  • (C) Cancer cells
  • (D) Bone marrow stem cells
Show Answer

Answer: B – Differentiated neurons rarely divide and remain in G0.

Q27. Which protein complex is responsible for separating sister chromatids during anaphase?

  • (A) DNA polymerase, which replicates the chromatids
  • (B) Cyclin, which activates the spindle
  • (C) Actin, which forms the cleavage furrow
  • (D) Separase, which cleaves cohesin holding the chromatids together
Show Answer

Answer: D – Separase removes cohesin, allowing chromatids to move to opposite poles.

Q28. A tumour suppressor gene is mutated so that it no longer functions. What is the likely consequence?

  • (A) Cells divide more slowly
  • (B) Cells may divide without normal checks, increasing cancer risk
  • (C) Apoptosis increases in all cells
  • (D) DNA replication stops entirely
Show Answer

Answer: B – Loss of tumour suppressors such as p53 removes brakes on the cell cycle.

Heredity

Q29. A man with haemophilia (X-linked recessive) has children with a woman who is homozygous normal. What is the probability that a daughter is a carrier?

  • (A) 50 percent
  • (B) 25 percent
  • (C) 0 percent
  • (D) 100 percent
Show Answer

Answer: D – Daughters receive the affected X from their father and a normal X from their mother, so all are carriers.

Q30. A dihybrid cross AaBb x AaBb is performed. What proportion of offspring are expected to show both dominant phenotypes?

  • (A) 3/16
  • (B) 1/16
  • (C) 1/4
  • (D) 9/16
Show Answer

Answer: D – Each trait shows a 3/4 dominant ratio, and 3/4 x 3/4 = 9/16.


Q31. In a pedigree, a trait appears in every generation and affected individuals have at least one affected parent. What is the most likely pattern?

  • (A) Autosomal dominant
  • (B) Autosomal recessive
  • (C) X-linked recessive
  • (D) Mitochondrial
Show Answer

Answer: A – Dominant traits appear in every generation and do not skip generations.

Q32. A chromosome has the gene order ABCDE. A crossover occurs between B and C in a heterozygote. Which gametes are recombinant?

  • (A) Those with a new combination of alleles on either side of the crossover point
  • (B) Those identical to the parental chromosomes
  • (C) Those with no genes at all
  • (D) Those with a doubled chromosome number
Show Answer

Answer: A – Recombinant gametes carry allele combinations not present in either parent chromosome.

Q33. A woman is heterozygous for a gene on chromosome 7. During meiosis, nondisjunction of chromosome 7 occurs in meiosis II. What gametes result?

  • (A) Four gametes each with an extra copy
  • (B) Two normal gametes, one with an extra copy and one missing a copy
  • (C) Four normal gametes
  • (D) Two gametes with an extra copy and two missing a copy
Show Answer

Answer: B – Nondisjunction in meiosis II affects only one of the two cells, giving two normal, one disomic and one nullisomic gamete.

Q34. A test of a 9:3:3:1 dihybrid ratio gives a chi-square value of 1.8 with 3 degrees of freedom. The critical value is 7.81. What is the conclusion?

  • (A) The genes are definitely linked
  • (B) The null hypothesis must be rejected
  • (C) The data are consistent with independent assortment; do not reject the null hypothesis
  • (D) The sample size was too small to calculate
Show Answer

Answer: C – A value below the critical value means the deviation is not significant.

Q35. Which process creates new allele combinations by exchanging segments between non-sister chromatids?

  • (A) Crossing over in prophase I
  • (B) Independent assortment in metaphase II
  • (C) DNA replication in S phase
  • (D) Cytokinesis after meiosis I
Show Answer

Answer: A – Crossing over exchanges DNA between homologous chromosomes in prophase I.

Q36. A gene for seed shape and a gene for seed colour are 5 map units apart. In a test cross, what percentage of offspring are expected to show a recombinant phenotype?

  • (A) 50 percent
  • (B) 25 percent
  • (C) 5 percent
  • (D) 95 percent
Show Answer

Answer: C – Recombination frequency equals map distance, so 5 percent of offspring are recombinant.

Gene Expression and Regulation

Q37. DNA polymerase adds nucleotides to a growing strand. In which direction does it synthesise, and what does it require?

  • (A) 3′ to 5′, requiring no primer
  • (B) 5′ to 3′, requiring a terminator
  • (C) 5′ to 3′, requiring a primer with a free 3′ hydroxyl group
  • (D) 3′ to 5′, requiring a ligase
Show Answer

Answer: C – DNA polymerase can only add to a 3′ end, so it needs a primer.

Q38. The coding strand of a gene has the sequence 5′-ATG GCT-3′. What is the mRNA sequence (ignoring the 5′ cap)?

  • (A) 5′-UAC CGA-3′
  • (B) 5′-AUG GCU-3′
  • (C) 5′-ATG GCT-3′
  • (D) 3′-AUG GCU-5′
Show Answer

Answer: B – mRNA matches the coding strand, with uracil in place of thymine.

Q39. A ribosome encounters a stop codon during translation. What happens?

  • (A) A release factor binds and the polypeptide is released
  • (B) A new tRNA brings another amino acid
  • (C) The ribosome reverses direction
  • (D) The mRNA is replicated
Show Answer

Answer: A – Stop codons recruit release factors that terminate translation.

Q40. In the trp operon, tryptophan is abundant. What is the expected state of the operon?

  • (A) Transcription is high because the repressor is inactive
  • (B) Transcription is repressed because tryptophan activates the repressor
  • (C) Transcription is high because tryptophan is an inducer
  • (D) The operon is deleted from the chromosome
Show Answer

Answer: B – Tryptophan is a corepressor that activates the trp repressor, switching the operon off.

Q41. A eukaryotic cell produces a protein only in liver cells, although the gene is present in all cells. What best explains this?

  • (A) The gene is deleted in other tissues
  • (B) Liver cells have a different genetic code
  • (C) Differential gene expression controlled by transcription factors and chromatin state
  • (D) The gene is mutated only in liver cells
Show Answer

Answer: C – Cell specialisation arises from regulating which genes are expressed, not from different genomes.

Q42. A mutation in a promoter region reduces transcription of a gene. What is this type of mutation best described as?

  • (A) A regulatory mutation affecting expression, not the protein sequence
  • (B) A frameshift mutation in the coding region
  • (C) A chromosomal deletion of the whole gene
  • (D) A silent mutation in an exon
Show Answer

Answer: A – Promoter mutations change how much mRNA is made, not the amino-acid sequence.

Q43. CRISPR-Cas9 is used to edit a gene. What does the guide RNA do?

  • (A) It cuts the DNA at a random location
  • (B) It translates the gene into protein
  • (C) It copies the gene by PCR
  • (D) It directs Cas9 to a specific DNA sequence by complementary base pairing
Show Answer

Answer: D – The guide RNA targets Cas9 to the sequence to be cut.

Q44. A DNA sample is analysed by gel electrophoresis. Two fragments are 500 bp and 2,000 bp. Which migrates farther?

  • (A) The 2,000 bp fragment
  • (B) The 500 bp fragment
  • (C) Both migrate the same distance
  • (D) Neither migrates because DNA is uncharged
Show Answer

Answer: B – Smaller fragments pass through the gel matrix more easily and travel farther.

Natural Selection

Q45. Disruptive selection is most likely to lead to

  • (A) a decrease in variation around the mean
  • (B) no change in allele frequencies
  • (C) immediate speciation in one generation
  • (D) an increase in variation, with both extremes favoured over intermediates
Show Answer

Answer: D – Disruptive selection favours both extremes, which can increase variation and sometimes drive divergence.

Q46. A population has allele frequencies p = 0.8 and q = 0.2. What is the expected frequency of homozygous recessive individuals?

  • (A) 0.04
  • (B) 0.20
  • (C) 0.32
  • (D) 0.64
Show Answer

Answer: A – q2 = 0.22 = 0.04.

Q47. Which factor is most likely to increase genetic variation within a population?

  • (A) A severe bottleneck
  • (B) Mutation and sexual reproduction
  • (C) Inbreeding
  • (D) A founder event
Show Answer

Answer: B – Mutation creates new alleles and recombination shuffles them into new combinations.

Q48. A population of finches on an island is founded by a few individuals. Over time, allele frequencies differ markedly from the mainland population. This is best explained by

  • (A) the founder effect, a form of genetic drift
  • (B) natural selection for the same traits
  • (C) high gene flow from the mainland
  • (D) a large population size
Show Answer

Answer: A – A small founding group carries only a sample of the original gene pool.

Q49. Homologous structures in different species provide evidence for

  • (A) convergent evolution
  • (B) analogous functions only
  • (C) independent origins of life
  • (D) divergence from a common ancestor
Show Answer

Answer: D – Homologous structures share an underlying plan inherited from a common ancestor.

Q50. A phylogenetic tree is built using DNA sequences. Which group is the outgroup used for?

  • (A) To show the most recently evolved species
  • (B) To replace the common ancestor
  • (C) To root the tree and determine the direction of evolutionary change
  • (D) To measure the mutation rate directly
Show Answer

Answer: C – An outgroup outside the group of interest helps root the tree.

Q51. Which reproductive barrier prevents two species from mating because they breed at different times of year?

  • (A) Temporal isolation
  • (B) Mechanical isolation
  • (C) Gametic isolation
  • (D) Hybrid breakdown
Show Answer

Answer: A – Temporal isolation is a prezygotic barrier based on timing.

Q52. The Miller-Urey experiment demonstrated that

  • (A) life was created in a laboratory
  • (B) DNA was the first molecule on Earth
  • (C) oxygen was abundant in the early atmosphere
  • (D) organic molecules could form from inorganic precursors under early Earth conditions
Show Answer

Answer: D – The experiment produced amino acids from simple gases and energy, supporting chemical evolution.

Ecology

Q53. A lizard basks in the sun to raise its body temperature. This is an example of

  • (A) endothermy using metabolic heat
  • (B) hibernation to avoid heat
  • (C) photosynthesis to generate heat
  • (D) behavioural thermoregulation in an ectotherm
Show Answer

Answer: D – Ectotherms use behaviour to regulate body temperature.

Q54. In an ecosystem, 10,000 kJ of energy is available at the producer level. Approximately how much is available to secondary consumers?

  • (A) About 10,000 kJ
  • (B) About 1,000 kJ
  • (C) About 10 kJ
  • (D) About 100 kJ
Show Answer

Answer: D – About 10 percent transfers at each level: 1,000 kJ to primary consumers and 100 kJ to secondary consumers.

Q55. A population shows exponential growth with r = 0.2 per year and N = 500. What is the approximate growth rate dN/dt?

  • (A) 500 individuals per year
  • (B) 0.2 individuals per year
  • (C) 2,500 individuals per year
  • (D) 100 individuals per year
Show Answer

Answer: D – dN/dt = rN = 0.2 x 500 = 100.

Q56. In a community, two species compete for the same food. According to competitive exclusion, what is expected if their niches overlap completely?

  • (A) Both species will increase indefinitely
  • (B) The species will interbreed
  • (C) One species will outcompete and exclude the other
  • (D) Competition will have no effect
Show Answer

Answer: C – Complete niche overlap leads to exclusion of the weaker competitor.

Q57. A keystone species is removed from a community. What is the most likely result?

  • (A) No change, because keystone species are rare
  • (B) A large change in community structure, with some species increasing and others declining
  • (C) An increase in biodiversity in all cases
  • (D) The community becomes a climax community
Show Answer

Answer: B – Keystone species have a disproportionate effect on community structure.

Q58. Which process returns nitrogen to the atmosphere?

  • (A) Nitrogen fixation by Rhizobium
  • (B) Nitrification by soil bacteria
  • (C) Assimilation by plants
  • (D) Denitrification by bacteria
Show Answer

Answer: D – Denitrifying bacteria convert nitrate to nitrogen gas.

Q59. A coral reef is damaged by rising sea temperatures, causing coral bleaching. This is an example of

  • (A) a biotic factor increasing biodiversity
  • (B) primary succession on bare rock
  • (C) an abiotic disruption affecting a community
  • (D) competitive exclusion between corals
Show Answer

Answer: C – Temperature is an abiotic factor; bleaching disrupts the reef community.

Q60. A national park protects a large area of forest. Which conservation benefit is most directly provided?

  • (A) Increased timber harvesting
  • (B) Elimination of all predators
  • (C) Prevention of all natural disturbances
  • (D) Preservation of habitat and biodiversity in a large, connected area
Show Answer

Answer: D – Protected areas preserve habitat, species and ecological processes.

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