AP Biology Practice Test 14 – 60 Questions with Answers (College Board)
Work through all 60 AP Biology questions, checking each answer as you go to build confidence for your AP Biology exam.
Chemistry of Life
Q1. Water has a high heat of vaporisation. How does this benefit a human who sweats on a hot day?
- (A) Sweat raises body temperature quickly
- (B) Evaporation of sweat removes a large amount of heat from the skin
- (C) Water vapour condenses and warms the body
- (D) Sweating prevents all water loss
Show Answer
Answer: B – Each gram of water evaporated carries away substantial heat, cooling the body.
Q2. A solution has [H+] = 1 x 10-9 M. What is its pH and is it acidic or basic?
- (A) pH 9, basic
- (B) pH 9, acidic
- (C) pH 5, basic
- (D) pH 3, acidic
Show Answer
Answer: A – pH = -log[H+] = 9, which is above 7 and therefore basic.
Q3. Which pair of molecules are isomers?
- (A) Glucose and sucrose, which have the same formula
- (B) Water and carbon dioxide
- (C) Glucose and fructose, which share the formula C6H12O6 but differ in structure
- (D) Starch and cellulose, which are identical
Show Answer
Answer: C – Isomers have the same molecular formula but different arrangements of atoms.
Q4. Amino acids are joined by peptide bonds. What is removed when a peptide bond forms?
- (A) A water molecule
- (B) A carbon dioxide molecule
- (C) An oxygen molecule
- (D) A nitrogen atom
Show Answer
Answer: A – Condensation joins amino acids, releasing water.
Q5. Which carbohydrate is the main energy storage molecule in animals?
- (A) Cellulose
- (B) Chitin
- (C) Starch
- (D) Glycogen
Show Answer
Answer: D – Animals store glucose as glycogen, mainly in liver and muscle.
Q6. A protein contains several polypeptide chains. What level of structure describes how these chains are arranged together?
- (A) Primary structure
- (B) Secondary structure
- (C) Tertiary structure
- (D) Quaternary structure
Show Answer
Answer: D – Quaternary structure is the arrangement of multiple polypeptide subunits.
Q7. In DNA, the two strands are antiparallel. What does this mean?
- (A) They have identical sequences
- (B) They run in opposite 5′ to 3′ directions
- (C) They are joined by covalent bonds between bases
- (D) They run in the same direction
Show Answer
Answer: B – One strand runs 5′ to 3′ while the other runs 3′ to 5′.
Q8. Chitin is a structural polysaccharide found in fungal cell walls and arthropod exoskeletons. What is its monomer?
- (A) Fructose
- (B) A nitrogen-containing derivative of glucose (N-acetylglucosamine)
- (C) Amino acids
- (D) Fatty acids
Show Answer
Answer: B – Chitin is a polymer of N-acetylglucosamine, a modified glucose.
Cell Structure and Function
Q9. Which organelle is the site of lipid synthesis and detoxification in liver cells?
- (A) The smooth endoplasmic reticulum
- (B) The rough endoplasmic reticulum
- (C) The Golgi apparatus
- (D) The ribosome
Show Answer
Answer: A – Smooth ER synthesises lipids and detoxifies drugs and poisons.
Q10. A cell takes in large droplets of fat by endocytosis. Which type of endocytosis is most likely?
- (A) Osmosis
- (B) Phagocytosis
- (C) Facilitated diffusion
- (D) Active transport through a pump
Show Answer
Answer: B – Phagocytosis engulfs large particles or droplets.
Q11. The plasma membrane is selectively permeable. What does this mean?
- (A) It allows all substances through equally
- (B) It allows some substances through but not others
- (C) It blocks all substances
- (D) It only allows water through
Show Answer
Answer: B – Selective permeability regulates which molecules cross the membrane.
Q12. A plant cell in a hypotonic solution gains water. What prevents it from bursting?
- (A) The vacuole pumps water out
- (B) The chloroplasts absorb the extra water
- (C) The cell wall provides mechanical resistance
- (D) The nucleus expands to absorb pressure
Show Answer
Answer: C – Turgor pressure is resisted by the rigid cell wall.
Q13. Which component of the cell membrane is responsible for cell recognition and signalling?
- (A) Phospholipid tails in the interior
- (B) Cholesterol buried in the bilayer
- (C) Integral proteins that span the membrane only for transport
- (D) Glycoproteins and glycolipids on the outer surface
Show Answer
Answer: D – Carbohydrate markers on membrane proteins and lipids identify the cell.
Q14. A eukaryotic cell is 20 micrometres across. Which microscope is needed to see its internal organelles in detail?
- (A) A transmission electron microscope
- (B) A light microscope at low power only
- (C) A magnifying glass
- (D) No microscope, because organelles are visible to the eye
Show Answer
Answer: A – Electron microscopy provides the resolution needed for organelle ultrastructure.
Q15. Which process moves vesicles from the Golgi apparatus to the plasma membrane for secretion?
- (A) Endocytosis
- (B) Phagocytosis
- (C) Osmosis
- (D) Exocytosis
Show Answer
Answer: D – Vesicles fuse with the plasma membrane and release their contents outside the cell.
Cellular Energetics
Q16. Which statement best describes the role of enzymes in a reaction?
- (A) They increase activation energy to slow the reaction
- (B) They are consumed and must be replaced after each reaction
- (C) They change the equilibrium position of the reaction
- (D) They lower activation energy and speed the reaction without being consumed
Show Answer
Answer: D – Enzymes provide an alternative pathway with lower activation energy.
Q17. A metabolic pathway is regulated by feedback inhibition. What happens when the end product accumulates?
- (A) It activates the first enzyme in the pathway
- (B) It is converted back to the starting substrate
- (C) It destroys the pathway enzymes
- (D) It binds to an allosteric site on an early enzyme and slows the pathway
Show Answer
Answer: D – Feedback inhibition prevents overproduction by shutting down the pathway.
Q18. In the light reactions, which photosystem is responsible for splitting water?
- (A) Photosystem I only
- (B) The Calvin cycle
- (C) Photosystem II
- (D) The Krebs cycle
Show Answer
Answer: C – Photosystem II oxidises water, releasing oxygen, protons and electrons.
Q19. A C4 plant fixes carbon dioxide into a four-carbon compound in mesophyll cells, then releases it in bundle-sheath cells. What is the advantage?
- (A) It allows photosynthesis in the dark
- (B) It eliminates the need for water
- (C) It concentrates CO2 around Rubisco, reducing photorespiration in hot conditions
- (D) It produces more oxygen than C3 plants
Show Answer
Answer: C – The CO2 concentrating mechanism minimises photorespiration.
Q20. During aerobic respiration, NADH from glycolysis is shuttled into the mitochondria. What is the main purpose of this?
- (A) To make glucose in the cytoplasm
- (B) To release carbon dioxide
- (C) To synthesise ATP by substrate-level phosphorylation
- (D) To deliver electrons to the electron transport chain for ATP production
Show Answer
Answer: D – NADH carries electrons to the chain, where their energy drives ATP synthesis.
Q21. A yeast culture is grown with oxygen and then switched to anaerobic conditions. What change in glucose consumption is expected?
- (A) Glucose consumption falls to zero
- (B) Glucose consumption stays the same
- (C) Glucose consumption rises because fermentation yields far less ATP per glucose
- (D) Glucose is no longer needed
Show Answer
Answer: C – The Pasteur effect: cells consume more glucose to meet ATP demand when respiration is unavailable.
Q22. The proton gradient across the inner mitochondrial membrane stores energy. What happens if the membrane becomes leaky to protons?
- (A) ATP synthesis increases
- (B) ATP synthesis falls because the gradient that drives ATP synthase is lost
- (C) The electron transport chain stops producing NADH
- (D) Glycolysis produces more ATP
Show Answer
Answer: B – Chemiosmosis depends on the gradient; leaking protons uncouples electron transport from ATP synthesis.
Cell Communication and Cell Cycle
Q23. A cell responds to a signal by changing gene expression. Which step in the pathway is most likely to be the slowest?
- (A) Transcription and translation of new proteins
- (B) Binding of the ligand to its receptor
- (C) Activation of a second messenger
- (D) Phosphorylation of a target protein
Show Answer
Answer: A – Changes in gene expression take minutes to hours, while earlier steps take seconds.
Q24. In a signal transduction pathway, a protein phosphatase removes phosphate groups from target proteins. What is its role?
- (A) To turn off the signal by reversing phosphorylation
- (B) To amplify the signal by adding phosphates
- (C) To bind the ligand at the receptor
- (D) To synthesise second messengers
Show Answer
Answer: A – Phosphatases terminate signalling by dephosphorylating targets.
Q25. A plant responds to a pathogen attack by producing defensive chemicals throughout the plant. This systemic response is an example of
- (A) long-distance cell communication
- (B) cell division only
- (C) apoptosis in all cells
- (D) photosynthesis
Show Answer
Answer: A – Plants use chemical signals to coordinate defence across tissues.
Q26. Which of the following is a correct sequence of events in the cell cycle?
- (A) S, G1, M, G2
- (B) M, G1, G2, S
- (C) G2, G1, S, M
- (D) G1, S, G2, M
Show Answer
Answer: D – Interphase (G1, S, G2) precedes mitosis (M).
Q27. A cell is treated with a drug that prevents microtubules from depolymerising, so chromosomes cannot move toward the poles. Which mitotic stage is directly blocked?
- (A) Anaphase, when sister chromatids are pulled to opposite poles
- (B) Prophase, when chromosomes condense and the spindle forms
- (C) Metaphase, when chromosomes align at the cell equator
- (D) Telophase, when nuclear envelopes re-form around the two sets of chromosomes
Show Answer
Answer: A – Anaphase is the stage in which sister chromatids move to opposite poles; if microtubules cannot shorten, this movement cannot happen.
Q28. A drug that prevents microtubule formation would most directly block which process?
- (A) Separation of chromosomes during mitosis
- (B) DNA replication
- (C) Protein synthesis
- (D) Glycolysis
Show Answer
Answer: A – Microtubules form the spindle that moves chromosomes.
Q29. In a multicellular organism, cell division is controlled by growth factors. What happens when a cell loses its response to growth factors?
- (A) It always divides faster
- (B) It may stop dividing or divide inappropriately, depending on the mutation
- (C) It always undergoes apoptosis
- (D) It becomes a stem cell
Show Answer
Answer: B – Growth factor signalling regulates division; loss can disrupt normal control in either direction.
Heredity
Q30. A pea plant with purple flowers (dominant) is crossed with a white-flowered plant. Half the offspring have white flowers. What is the genotype of the purple parent?
- (A) Homozygous dominant (PP)
- (B) Heterozygous (Pp)
- (C) Homozygous recessive (pp)
- (D) Hemizygous
Show Answer
Answer: B – A 1:1 ratio in a cross with a recessive parent indicates the dominant parent is heterozygous.
Q31. Two genes are located on different chromosomes. What is the expected phenotypic ratio in the offspring of AaBb x aabb?
- (A) 9:3:3:1
- (B) 3:1
- (C) 1:2:1
- (D) 1:1:1:1
Show Answer
Answer: D – A test cross with independent assortment gives equal proportions of the four phenotypes.
Q32. A geneticist observes that a trait is passed from father to son and appears in all male descendants. What is the most likely mode of inheritance?
- (A) X-linked recessive
- (B) Y-linked
- (C) Autosomal dominant
- (D) Mitochondrial
Show Answer
Answer: B – Y-linked traits pass only from father to son.
Q33. In humans, the ABO blood group system shows codominance between IA and IB. What blood type results from genotype IAIB?
- (A) Type A
- (B) Type AB
- (C) Type B
- (D) Type O
Show Answer
Answer: B – Both alleles are expressed, producing both A and B antigens.
Q34. A woman with blood type O has a child with blood type AB. What can be concluded about the father?
- (A) He must be type O
- (B) He must be type A
- (C) He must carry both IA and IB alleles
- (D) He must be type B
Show Answer
Answer: C – The child needs IA and IB; the mother can only give i, so the father must provide both.
Q35. A cross between two heterozygous parents for a single gene gives 200 offspring. How many are expected to be homozygous recessive?
- (A) 100
- (B) 25
- (C) 50
- (D) 150
Show Answer
Answer: C – One quarter of 200 is 50.
Q36. Which statement about linked genes is correct?
- (A) They are always on different chromosomes
- (B) They always assort independently
- (C) They cannot be separated by crossing over
- (D) They are on the same chromosome and tend to be inherited together
Show Answer
Answer: D – Linked genes are physically close on a chromosome, though crossing over can separate them.
Gene Expression and Regulation
Q37. Which molecule carries the genetic information from the nucleus to the ribosome?
- (A) Messenger RNA
- (B) Transfer RNA
- (C) Ribosomal RNA alone
- (D) DNA polymerase
Show Answer
Answer: A – mRNA is transcribed in the nucleus and translated at ribosomes.
Q38. A DNA fragment is replicated in vitro. Which enzyme is used in PCR to withstand high temperatures?
- (A) DNA ligase
- (B) Helicase
- (C) Taq polymerase
- (D) RNA polymerase
Show Answer
Answer: C – Taq polymerase from a thermophilic bacterium survives the heating cycles of PCR.
Q39. A mutation deletes three nucleotides from a coding region. What is the most likely effect?
- (A) Loss of one amino acid, with the rest of the protein unchanged
- (B) A frameshift changing all downstream amino acids
- (C) No change in the protein
- (D) A premature stop codon
Show Answer
Answer: A – Deleting a whole codon removes one amino acid without shifting the reading frame.
Q40. In a eukaryotic cell, the 5′ cap and poly-A tail are added to mRNA. What is their main function?
- (A) To code for amino acids
- (B) To splice out introns
- (C) To replicate the DNA
- (D) To protect the mRNA from degradation and aid export and translation
Show Answer
Answer: D – The cap and tail stabilise mRNA and promote its translation.
Q41. A gene is regulated by a repressor protein that binds to an operator. When the repressor is bound, what happens?
- (A) Transcription is blocked
- (B) Transcription is increased
- (C) Translation is increased
- (D) DNA replication is blocked
Show Answer
Answer: A – Repressor binding prevents RNA polymerase from transcribing the gene.
Q42. A researcher wants to determine the sequence of a DNA fragment. Which technique is most appropriate?
- (A) Gel electrophoresis alone
- (B) PCR alone, without sequencing
- (C) DNA sequencing (e.g. Sanger or next-generation sequencing)
- (D) Southern blotting alone
Show Answer
Answer: C – Sequencing reads the order of nucleotides directly.
Q43. A plasmid containing a gene for insulin is inserted into bacteria, which then produce human insulin. What is this an example of?
- (A) Natural selection
- (B) Meiosis
- (C) Genetic engineering using recombinant DNA
- (D) Cloning by cell division only
Show Answer
Answer: C – Recombinant DNA technology allows bacteria to express a human gene.
Q44. A point mutation in a gene changes the amino acid from leucine to proline in the middle of an alpha helix. What is the most likely effect on the protein?
- (A) No effect, because all amino acids are identical
- (B) The helix is disrupted, potentially altering protein function
- (C) The protein becomes longer
- (D) The DNA is repaired automatically
Show Answer
Answer: B – Proline introduces a kink that disrupts alpha-helical structure.
Natural Selection
Q45. A population of moths has light and dark forms. After industrial soot darkens tree trunks, dark moths become more common. This is an example of
- (A) mutation creating new alleles in response to soot
- (B) genetic drift with no selection
- (C) natural selection acting on existing variation
- (D) artificial selection by humans
Show Answer
Answer: C – Selection favours the better-camouflaged dark form that already existed in the population.
Q46. In a population in Hardy-Weinberg equilibrium, the frequency of the dominant allele is 0.7. What is the frequency of carriers (heterozygotes)?
- (A) 0.49
- (B) 0.09
- (C) 0.70
- (D) 0.42
Show Answer
Answer: D – 2pq = 2 x 0.7 x 0.3 = 0.42.
Q47. Which situation would most increase the chance of speciation?
- (A) High gene flow between populations
- (B) A very large, well-mixed population
- (C) Geographic isolation of a population in a new environment
- (D) Random mating with no selection
Show Answer
Answer: C – Isolation reduces gene flow, allowing populations to diverge.
Q48. A trait that is no longer used, such as the pelvic bones in whales, is called
- (A) homologous
- (B) analogous
- (C) adaptive
- (D) vestigial
Show Answer
Answer: D – Vestigial structures are remnants of features that were functional in ancestors.
Q49. Which of the following is a prezygotic reproductive barrier?
- (A) Hybrid offspring that are sterile
- (B) Different mating seasons preventing fertilisation
- (C) Hybrid offspring that die before reproducing
- (D) A zygote that fails to develop
Show Answer
Answer: B – Prezygotic barriers act before fertilisation; hybrid sterility is postzygotic.
Q50. A scientist compares the amino-acid sequence of haemoglobin in several species. Species with the most similar sequences are most likely to be
- (A) most closely related evolutionarily
- (B) most distantly related
- (C) unrelated to each other
- (D) the same species
Show Answer
Answer: A – Molecular similarity reflects recent common ancestry.
Q51. The first cells on Earth were most likely
- (A) eukaryotic, photosynthetic autotrophs
- (B) multicellular animals
- (C) viruses with DNA genomes
- (D) prokaryotic, anaerobic heterotrophs
Show Answer
Answer: D – Early Earth had little oxygen, and the first cells were simple prokaryotes.
Q52. A population of bacteria is exposed to an antibiotic. A few resistant cells survive and reproduce. What has happened?
- (A) The antibiotic caused mutations for resistance in every cell
- (B) The bacteria learned to resist the antibiotic
- (C) Natural selection has favoured resistant variants already present in the population
- (D) The antibiotic created a new species immediately
Show Answer
Answer: C – Selection acts on pre-existing variation; resistant mutants were already present at low frequency.
Ecology
Q53. A plant closes its stomata during a drought. What is the main benefit and the main cost?
- (A) Increased water loss and increased photosynthesis
- (B) Reduced water loss and increased CO2 uptake
- (C) Reduced water loss, but reduced CO2 uptake for photosynthesis
- (D) No benefit and no cost
Show Answer
Answer: C – Closed stomata conserve water but limit carbon dioxide entry.
Q54. A food web includes grass, rabbits, foxes and eagles. If rabbits are removed, what is the most likely immediate effect?
- (A) Eagles increase in number immediately
- (B) Grass biomass decreases
- (C) Foxes switch to eating eagles
- (D) Foxes lose a food source and grass biomass increases
Show Answer
Answer: D – Removing primary consumers releases producers and deprives their predators of food.
Q55. A population of bacteria doubles every 20 minutes. Starting from 100 cells, how many cells are there after 1 hour?
- (A) 300 cells
- (B) 800 cells
- (C) 400 cells
- (D) 1,600 cells
Show Answer
Answer: B – Three doublings in one hour: 100 x 23 = 800.
Q56. Which factor is density-independent?
- (A) A hurricane destroying nests regardless of population size
- (B) Competition for nesting sites
- (C) Spread of disease in a crowded population
- (D) Predation that increases with prey density
Show Answer
Answer: A – Density-independent factors affect a population regardless of its size.
Q57. In primary succession, the first organisms to colonise bare rock are usually
- (A) large trees
- (B) lichens and mosses
- (C) shrubs
- (D) mammals
Show Answer
Answer: B – Pioneer species such as lichens can grow on bare rock and begin soil formation.
Q58. Which biome has the highest net primary productivity per unit area?
- (A) Desert
- (B) Tropical rainforest
- (C) Tundra
- (D) Open ocean per unit area
Show Answer
Answer: B – Warm, wet tropical rainforests have very high productivity.
Q59. A lake is polluted with heavy metals that accumulate in fish. Top predators have the highest concentrations. This is an example of
- (A) biomagnification
- (B) bioaccumulation only in producers
- (C) eutrophication
- (D) competitive exclusion
Show Answer
Answer: A – Biomagnification is the increase in toxin concentration up the food chain.
Q60. Which human activity most directly contributes to the loss of biodiversity in rainforests?
- (A) Establishing nature reserves
- (B) Reducing fossil fuel use
- (C) Deforestation for agriculture and logging
- (D) Replanting native trees
Show Answer
Answer: C – Habitat destruction is the leading cause of biodiversity loss.
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