AP Biology Practice Test 12 – 60 Questions with Answers (College Board)
Work through all 60 AP Biology questions, checking each answer as you go to build confidence for your AP Biology exam.
Chemistry of Life
Q1. Ice floats on water, water has high specific heat, and water molecules cohere strongly. Which of these properties most directly allows a large lake to resist rapid temperature change?
- (A) Low density of ice, because it insulates the surface
- (B) Cohesion, because it pulls water molecules apart
- (C) Adhesion, because water sticks to the lake bed
- (D) High specific heat, because much energy is needed to change the temperature
Show Answer
Answer: D – Specific heat determines how much energy changes temperature; water’s high value buffers temperature swings.
Q2. A buffer solution resists pH change when acid is added. What does the buffer contain that makes this possible?
- (A) A strong acid and a strong base in equal amounts
- (B) Only water molecules with no dissolved ions
- (C) A weak acid and its conjugate base, which can absorb added H+ or OH–
- (D) An enzyme that destroys hydrogen ions
Show Answer
Answer: C – The conjugate pair neutralises small additions of acid or base.
Q3. Which molecule is a monomer of a nucleic acid?
- (A) An amino acid joined by a peptide bond
- (B) A glycerol molecule with three fatty acids
- (C) A nucleotide, composed of a sugar, a phosphate and a nitrogenous base
- (D) A glucose molecule with a hydroxyl group
Show Answer
Answer: C – Nucleotides polymerise through phosphodiester bonds to form DNA and RNA.
Q4. Sucrose is formed from glucose and fructose. What type of reaction joins them, and what is released?
- (A) Hydrolysis, releasing a water molecule
- (B) Dehydration synthesis, releasing carbon dioxide
- (C) Dehydration synthesis, releasing a water molecule
- (D) Hydrolysis, releasing oxygen
Show Answer
Answer: C – Joining monomers by dehydration synthesis removes water; hydrolysis adds water to break the bond.
Q5. Which lipid is the main component of cell membranes and has both a hydrophilic head and hydrophobic tails?
- (A) A triglyceride used only for energy storage
- (B) A wax that waterproofs leaves
- (C) A steroid that stores genetic information
- (D) A phospholipid
Show Answer
Answer: D – Phospholipids are amphipathic and form bilayers.
Q6. A protein’s function depends on its shape. Which interaction is most important in stabilising the tertiary structure of a protein in water?
- (A) Peptide bonds between amino acids in the backbone
- (B) Hydrogen bonds between complementary base pairs
- (C) Hydrophobic interactions that bury nonpolar side chains in the interior
- (D) Ionic bonds between phosphate groups
Show Answer
Answer: C – Folding buries hydrophobic residues away from water, stabilising the tertiary structure.
Q7. DNA and RNA differ in several ways. Which statement correctly distinguishes them?
- (A) DNA is single-stranded and RNA is double-stranded
- (B) DNA contains ribose and RNA contains deoxyribose
- (C) DNA uses uracil and RNA uses thymine
- (D) DNA contains deoxyribose and thymine; RNA contains ribose and uracil
Show Answer
Answer: D – The sugar and one base differ between the two nucleic acids.
Cell Structure and Function
Q8. Which organelle modifies, sorts and packages proteins for secretion?
- (A) The Golgi apparatus
- (B) The smooth endoplasmic reticulum
- (C) The mitochondrion
- (D) The lysosome
Show Answer
Answer: A – Proteins pass through the Golgi, where they are modified and shipped in vesicles.
Q9. A cell with a large surface area relative to its volume is best suited to which function?
- (A) Long-term storage of glycogen
- (B) Protection from mechanical damage
- (C) Rapid exchange of materials with its environment
- (D) Production of large amounts of DNA
Show Answer
Answer: C – A high SA/V ratio favours diffusion and exchange.
Q10. Red blood cells placed in distilled water swell and burst, while plant cells in distilled water become turgid but do not burst. What explains the difference?
- (A) Plant cells lack a plasma membrane
- (B) The plant cell wall resists the turgor pressure
- (C) Red blood cells actively pump water out
- (D) Plant cells have no vacuole to fill
Show Answer
Answer: B – The rigid wall prevents lysis even as water enters by osmosis.
Q11. Which process requires ATP and moves ions against their concentration gradient?
- (A) Facilitated diffusion through a channel protein
- (B) Simple diffusion across the bilayer
- (C) Active transport by a pump protein
- (D) Osmosis through an aquaporin
Show Answer
Answer: C – Active transport uses energy to move substances against a gradient.
Q12. A researcher labels a membrane protein and finds it moves laterally within the membrane. This supports which model?
- (A) The lock-and-key model of enzymes
- (B) The cell theory of Schleiden and Schwann
- (C) The fluid mosaic model
- (D) The endosymbiotic theory
Show Answer
Answer: C – The fluid mosaic model describes a fluid bilayer with proteins that can move within it.
Q13. Which structure is found in both prokaryotic and eukaryotic cells?
- (A) A membrane-bound nucleus
- (B) Mitochondria
- (C) A Golgi apparatus
- (D) Ribosomes
Show Answer
Answer: D – All cells have ribosomes for protein synthesis; only eukaryotes have membrane-bound organelles.
Q14. Cholesterol in an animal cell membrane primarily functions to
- (A) transport glucose across the membrane
- (B) store energy for the cell
- (C) catalyse the synthesis of phospholipids
- (D) modulate membrane fluidity, stiffening it at high temperatures and preventing solidification at low temperatures
Show Answer
Answer: D – Cholesterol buffers fluidity across temperatures.
Cellular Energetics
Q15. ATP hydrolysis releases energy that cells use for work. What happens to the ATP molecule itself?
- (A) It gains a phosphate group, forming AMP
- (B) It is broken down into glucose and oxygen
- (C) It is converted directly into DNA
- (D) It loses a phosphate group, forming ADP and inorganic phosphate
Show Answer
Answer: D – Hydrolysis of the terminal phosphate bond releases energy and yields ADP + Pi.
Q16. An enzyme works best at pH 7 but loses activity at pH 2. What is the most likely explanation?
- (A) The acidic conditions alter the enzyme’s shape, including its active site
- (B) The substrate is destroyed by the enzyme at low pH
- (C) The enzyme gains extra active sites at pH 2
- (D) The reaction becomes exergonic only at pH 7
Show Answer
Answer: A – Extreme pH disrupts hydrogen bonds and ionic interactions, denaturing the enzyme.
Q17. In an experiment, adding a competitive inhibitor to an enzyme reaction increases the apparent Km but does not change Vmax. Why can Vmax still be reached?
- (A) High substrate concentration can outcompete the inhibitor for the active site
- (B) The inhibitor is destroyed by the substrate
- (C) The enzyme makes more active sites in response
- (D) Competitive inhibitors bind only to the product
Show Answer
Answer: A – Competitive inhibition is overcome by excess substrate, so Vmax is unchanged.
Q18. During the Calvin cycle, how many turns are needed to produce one molecule of glucose (C6H12O6)?
- (A) One turn, fixing one CO2
- (B) Three turns, fixing three CO2
- (C) Twelve turns, fixing twelve CO2
- (D) Six turns, fixing six CO2 molecules
Show Answer
Answer: D – Each turn fixes one carbon, so six turns provide the six carbons of glucose.
Q19. A leaf is exposed to light of only green wavelengths. What is the expected rate of photosynthesis compared with white light?
- (A) Lower, because chlorophyll absorbs green light poorly
- (B) Higher, because green light carries the most energy
- (C) The same, because all wavelengths are absorbed equally
- (D) Zero, because green light destroys chlorophyll
Show Answer
Answer: A – Chlorophyll reflects green light, so it is the least effective wavelength for photosynthesis.
Q20. In glycolysis, glucose is broken down to pyruvate. What is the net ATP yield per glucose?
- (A) 2 ATP
- (B) 4 ATP
- (C) 0 ATP
- (D) 36 ATP
Show Answer
Answer: A – Glycolysis makes 4 ATP but uses 2, giving a net gain of 2 ATP per glucose.
Q21. Acetyl-CoA enters the Krebs cycle. For each glucose molecule, how many CO2 molecules are released by the Krebs cycle in total?
- (A) 4 CO2
- (B) 2 CO2
- (C) 6 CO2
- (D) 1 CO2
Show Answer
Answer: A – Each pyruvate yields one CO2 in the link reaction and the cycle releases two more per acetyl-CoA, totalling six overall; the Krebs cycle itself releases four per glucose.
Cell Communication and Cell Cycle
Q22. A steroid hormone such as testosterone can enter a target cell and bind an intracellular receptor. Why can it cross the membrane?
- (A) It is carried by aquaporins
- (B) It is small enough to pass through ion channels
- (C) It is lipid-soluble and diffuses through the phospholipid bilayer
- (D) It binds a surface receptor that pulls it inside
Show Answer
Answer: C – Hydrophobic steroid hormones diffuse directly across the membrane.
Q23. A mutation makes a G protein unable to hydrolyse GTP to GDP. What is the expected effect on the signalling pathway?
- (A) The pathway never activates
- (B) The receptor is destroyed
- (C) Second messengers are never produced at all
- (D) The pathway stays switched on, because the G protein remains active
Show Answer
Answer: D – GTP hydrolysis normally switches the G protein off; without it, signalling persists.
Q24. In quorum sensing, bacteria release autoinducer molecules. When the concentration reaches a threshold, gene expression changes. What is the main purpose of this system?
- (A) To attract predators to the colony
- (B) To coordinate behaviour based on population density
- (C) To prevent any cell division
- (D) To block all signal transduction
Show Answer
Answer: B – Quorum sensing lets bacteria sense density and act collectively, for example in biofilm formation.
Q25. Apoptosis differs from necrosis in that apoptosis is
- (A) an uncontrolled bursting of the cell
- (B) a controlled, programmed process that does not damage neighbouring cells
- (C) caused only by external injury
- (D) a process that releases cell contents into tissue
Show Answer
Answer: B – Apoptosis dismantles the cell neatly, with fragments taken up by phagocytes.
Q26. During the cell cycle, DNA is replicated in which phase?
- (A) S phase
- (B) G1 phase
- (C) M phase
- (D) G0 phase
Show Answer
Answer: A – S phase is the synthesis phase, when the genome is duplicated.
Q27. A cancer cell is found to divide even when growth factors are absent. Which defect best explains this?
- (A) A mutation that increases apoptosis
- (B) A mutation in a proto-oncogene creates a permanently active growth signal
- (C) A loss of ribosomes in the cytoplasm
- (D) An increase in the number of mitochondria
Show Answer
Answer: B – Oncogenes drive uncontrolled division when mutated to a constitutively active form.
Q28. Which checkpoint ensures that DNA has been replicated correctly and checks for damage before mitosis?
- (A) The G1 checkpoint
- (B) The spindle checkpoint
- (C) The G2 checkpoint
- (D) The cytokinesis checkpoint
Show Answer
Answer: C – The G2 checkpoint verifies DNA replication and damage before M phase.
Q29. A cell is exposed to a signal that raises intracellular calcium. Calcium ions in this context act as
- (A) the primary signal that binds the receptor
- (B) enzymes that degrade the signal
- (C) second messengers that activate target proteins
- (D) structural components of the membrane
Show Answer
Answer: C – Calcium is a common second messenger released from the endoplasmic reticulum.
Heredity
Q30. A woman who is a carrier for an X-linked recessive disorder has children with an unaffected man. What is the probability that a son will be affected?
- (A) 1/4
- (B) 0
- (C) 1
- (D) 1/2
Show Answer
Answer: D – Sons receive their X chromosome from their mother, who passes the affected allele half the time.
Q31. In a cross between two heterozygotes for a recessive trait, a chi-square test is used. What is the null hypothesis?
- (A) The trait is sex-linked
- (B) The observed offspring ratio does not differ significantly from the expected 3:1 ratio
- (C) The genes are linked
- (D) The parents are homozygous
Show Answer
Answer: B – The null hypothesis states that any deviation is due to chance alone.
Q32. A fruit fly with red eyes and normal wings is crossed with a white-eyed, vestigial-winged fly. The offspring show mostly parental phenotypes. What does this suggest?
- (A) The genes assort independently
- (B) The traits are controlled by the same allele
- (C) The cross involves codominance
- (D) The genes for eye colour and wing shape are linked
Show Answer
Answer: D – A high proportion of parental types and few recombinants indicates linkage.
Q33. Which event in meiosis produces genetically different gametes even without crossing over?
- (A) DNA replication in S phase
- (B) Cytokinesis after meiosis II
- (C) Formation of the spindle
- (D) Independent assortment of homologous chromosomes
Show Answer
Answer: D – Random orientation of homologues at metaphase I creates different chromosome combinations.
Q34. A couple has three children, all with blood type O. Both parents have blood type A. What are the parents’ genotypes?
- (A) Both are homozygous IAIA
- (B) Both are heterozygous (IAi)
- (C) One is IAIA and one is ii
- (D) Both are ii
Show Answer
Answer: B – Only heterozygous A parents can each pass an i allele to produce type O children.
Q35. A plant with genotype AaBb self-fertilises. What proportion of offspring are expected to be aabb?
- (A) 1/4
- (B) 1/8
- (C) 9/16
- (D) 1/16
Show Answer
Answer: D – Each locus gives a 1/4 chance of the recessive homozygote, and 1/4 x 1/4 = 1/16.
Q36. Down syndrome is most commonly caused by
- (A) a deletion on chromosome 5
- (B) trisomy 21 due to nondisjunction
- (C) a dominant mutation on chromosome 21
- (D) an extra copy of the X chromosome
Show Answer
Answer: B – An extra chromosome 21 results from failure of chromosomes to separate.
Q37. In a test cross, an individual of unknown genotype is crossed with a homozygous recessive individual. What is the purpose?
- (A) To determine whether the unknown individual is homozygous or heterozygous
- (B) To produce only homozygous offspring
- (C) To test for linkage between two genes
- (D) To create a new species
Show Answer
Answer: A – The recessive tester reveals the gametes of the unknown parent.
Gene Expression and Regulation
Q38. Which enzyme unwinds DNA and separates the strands during replication?
- (A) DNA ligase
- (B) RNA polymerase
- (C) Helicase
- (D) DNA polymerase
Show Answer
Answer: C – Helicase breaks hydrogen bonds between bases to open the replication fork.
Q39. In transcription, RNA polymerase binds to which DNA region to begin synthesis?
- (A) The promoter
- (B) The terminator only
- (C) The origin of replication
- (D) The anticodon
Show Answer
Answer: A – The promoter is the binding site that initiates transcription.
Q40. A tRNA molecule has the anticodon 3′-UAC-5′. Which mRNA codon does it pair with, and which amino acid does it carry?
- (A) 5′-UAC-3′, tyrosine
- (B) 5′-AUG-3′, methionine
- (C) 5′-TAC-3′, methionine
- (D) 3′-AUG-5′, leucine
Show Answer
Answer: B – The anticodon pairs with AUG, the start codon for methionine.
Q41. A gene is transcribed but its mRNA is rapidly degraded before translation. How is gene expression affected?
- (A) The protein is produced in larger amounts
- (B) The DNA sequence is permanently changed
- (C) Transcription is increased to compensate
- (D) No protein is produced, despite transcription occurring
Show Answer
Answer: D – Regulation can occur after transcription, including mRNA degradation.
Q42. In eukaryotic cells, transcription factors bind to enhancers. What is the effect?
- (A) They increase the rate of transcription of a gene, even from a distance
- (B) They block DNA replication
- (C) They splice introns from the mRNA
- (D) They translate mRNA into protein
Show Answer
Answer: A – Enhancers are regulatory DNA sequences that boost transcription when bound.
Q43. A frameshift mutation is caused by
- (A) substitution of one nucleotide for another
- (B) insertion or deletion of nucleotides not in multiples of three
- (C) duplication of an entire chromosome
- (D) methylation of a promoter
Show Answer
Answer: B – Adding or removing bases shifts the reading frame, changing all downstream codons.
Q44. Gel electrophoresis separates DNA fragments mainly by
- (A) base composition, with AT-rich fragments moving fastest
- (B) size, with smaller fragments moving farther toward the positive electrode
- (C) charge, with larger fragments carrying more charge
- (D) shape, with circular fragments moving slowest
Show Answer
Answer: B – DNA is negatively charged and migrates through the gel; smaller fragments move farther.
Q45. A bacterial plasmid is cut with a restriction enzyme and a human gene is inserted. This is an example of
- (A) natural selection
- (B) PCR amplification only
- (C) gel electrophoresis
- (D) recombinant DNA technology
Show Answer
Answer: D – Joining DNA from different sources creates recombinant DNA.
Natural Selection
Q46. Stabilising selection is most likely when
- (A) one extreme phenotype is favoured
- (B) both extremes are favoured over intermediates
- (C) allele frequencies change by chance alone
- (D) intermediate phenotypes have the highest fitness and extremes are selected against
Show Answer
Answer: D – Stabilising selection narrows variation around the optimum.
Q47. In a large population, the frequency of allele A is 0.6. Assuming Hardy-Weinberg equilibrium, what is the frequency of genotype AA?
- (A) 0.36
- (B) 0.60
- (C) 0.48
- (D) 0.24
Show Answer
Answer: A – p2 = 0.62 = 0.36.
Q48. A new allele arises by mutation in a single individual. In a very large population, what is its most likely fate?
- (A) It will immediately spread to the whole population
- (B) It will be removed by stabilising selection
- (C) It is likely to be lost by chance or remain rare unless it confers an advantage
- (D) It will double in frequency every generation
Show Answer
Answer: C – A rare new allele is vulnerable to loss by drift and spreads only if favoured by selection.
Q49. Two species share a similar wing structure that evolved independently for flight. This is an example of
- (A) homologous structures from a common ancestor
- (B) vestigial structures with no function
- (C) convergent evolution producing analogous structures
- (D) divergent evolution from one ancestor
Show Answer
Answer: C – Analogous structures evolve independently in response to similar pressures.
Q50. A cladogram places birds and crocodiles in the same clade, separate from lizards. What does this imply?
- (A) Birds evolved directly from lizards
- (B) Birds and crocodiles share a more recent common ancestor than either shares with lizards
- (C) Crocodiles are more closely related to lizards
- (D) Birds and lizards are the same species
Show Answer
Answer: B – Clades group organisms by shared derived characters and recent ancestry.
Q51. Which evidence provides the strongest support for common ancestry of all living organisms?
- (A) The fact that all organisms live on Earth
- (B) Similarities in habitat preferences
- (C) The near-universality of the genetic code
- (D) Differences in body size
Show Answer
Answer: C – A shared genetic code across life is powerful evidence of a common origin.
Q52. A population of lizards colonises a new island with few predators. Over time, body size increases. What is the most likely explanation?
- (A) Genetic drift with no change in fitness
- (B) Directional selection favouring larger size in the new environment
- (C) Stabilising selection maintaining the original size
- (D) Gene flow from the mainland
Show Answer
Answer: B – A new environment can shift the optimum, favouring larger individuals.
Q53. The fossil record shows a sudden appearance of many new animal body plans in the Cambrian period. What does this suggest?
- (A) All animal phyla appeared simultaneously with no ancestors
- (B) A rapid diversification of animal life occurred at that time
- (C) Evolution stopped after the Cambrian
- (D) Fossils from earlier periods were destroyed by humans
Show Answer
Answer: B – The Cambrian explosion records rapid diversification, though earlier ancestors also existed.
Ecology
Q54. A caterpillar eats leaves and is eaten by a bird. In a food chain, the caterpillar is a
- (A) primary consumer
- (B) producer
- (C) secondary consumer
- (D) decomposer
Show Answer
Answer: A – Primary consumers eat producers; the bird is the secondary consumer.
Q55. Why is the total biomass at each trophic level usually less than at the level below it?
- (A) Producers make less energy than consumers
- (B) Decomposers add biomass at higher levels
- (C) Energy is lost as heat and in waste at each transfer
- (D) Photosynthesis is more efficient in animals
Show Answer
Answer: C – Only about 10 percent of energy is transferred, so biomass declines up the chain.
Q56. A population of deer grows rapidly after wolves are removed, then crashes when food runs out. This pattern is best explained by
- (A) overshoot of carrying capacity followed by a crash
- (B) logistic growth with a stable equilibrium
- (C) density-independent regulation by weather only
- (D) exponential growth with unlimited resources
Show Answer
Answer: A – Without predators, the population exceeds K, depletes resources and crashes.
Q57. Which factor is density-dependent?
- (A) A severe frost killing individuals regardless of density
- (B) Competition for food within a population
- (C) A flood destroying nests at random
- (D) A volcanic eruption
Show Answer
Answer: B – Density-dependent factors intensify as population density rises.
Q58. A forest is cleared and abandoned. Grasses appear first, then shrubs, then trees. This is an example of
- (A) secondary succession
- (B) primary succession on bare rock
- (C) climax community formation with no change
- (D) competitive exclusion
Show Answer
Answer: A – Succession on soil that retains a seed bank after disturbance is secondary succession.
Q59. Which ecosystem service is provided by wetlands?
- (A) Water filtration and flood control
- (B) Production of fossil fuels
- (C) Increased soil erosion
- (D) Removal of all nitrogen from soil
Show Answer
Answer: A – Wetlands filter pollutants and absorb floodwater.
Q60. A species is introduced to a new area, spreads rapidly and reduces native biodiversity. This species is best described as
- (A) endemic
- (B) invasive
- (C) keystone
- (D) mutualistic
Show Answer
Answer: B – Invasive species spread aggressively and harm native communities.
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