A-Level Biology Practice Test 19 – 60 Questions with Answers (Cambridge 9700)
This test emphasises regulation and integration, from gene control to whole-organism coordination, alongside the core syllabus topics.
Cell structure
Q1. The cytoskeleton in eukaryotic cells is important because it does what?
- (A) Provides structural support, organelle positioning and tracks for vesicle movement
- (B) Synthesises ATP for the cell
- (C) Stores genetic information in the cytoplasm
- (D) Forms the outer cell wall in animal cells
Show Answer
Answer: A – Microtubules and microfilaments maintain cell shape and move organelles and chromosomes during division.
Q2. Which structure is the site of ribosome production in a eukaryotic cell?
- (A) Smooth endoplasmic reticulum
- (B) Nucleolus within the nucleus
- (C) Golgi apparatus
- (D) Lysosome
Show Answer
Answer: B – The nucleolus synthesises ribosomal RNA and assembles ribosomal subunits.
Q3. Lysosomes are important in phagocytes because they contain what?
- (A) Chlorophyll for photosynthesis
- (B) DNA for protein synthesis
- (C) Hydrolytic enzymes that digest ingested material
- (D) ATP synthase for energy production
Show Answer
Answer: C – Lysosomes fuse with phagosomes, and their enzymes break down bacteria and worn-out organelles.
Biological molecules
Q4. Cellulose is a structural polysaccharide in plant cell walls. Which feature makes it strong?
- (A) Alpha-glucose units joined by 1,4-glycosidic bonds into a helix
- (B) Beta-glucose units joined by 1,4-glycosidic bonds into straight chains held together by hydrogen bonds
- (C) Branched chains with many 1,6-glycosidic bonds
- (D) Alternating glucose and fructose units
Show Answer
Answer: B – Straight beta-glucose chains pack into microfibrils, giving great tensile strength.
Q5. Phospholipids are suited to forming cell membranes because they are what?
- (A) Completely hydrophobic molecules
- (B) Completely hydrophilic molecules
- (C) Amphipathic, with hydrophilic heads and hydrophobic tails that form a bilayer in water
- (D) Large proteins that span the membrane
Show Answer
Answer: C – The bilayer arrangement hides hydrophobic tails from water while heads face aqueous environments on both sides.
Q6. A heat-denatured enzyme is cooled slowly, but its catalytic activity does not return. Which explanation best fits this result?
- (A) The sequence of amino acids in the enzyme has been rearranged
- (B) New peptide bonds have formed between different amino acids
- (C) The enzyme has gained extra subunits from the surrounding solution
- (D) Its tertiary structure, held by weak bonds, has unfolded irreversibly and the active site shape is lost
Show Answer
Answer: D – Denaturation breaks hydrogen bonds and other weak interactions, so the active site loses its shape even though peptide bonds remain intact.
Enzymes
Q7. End-product inhibition is a form of feedback control in metabolic pathways. How does it work?
- (A) The end product denatures all enzymes in the cell permanently
- (B) The end product increases the activity of the first enzyme in the pathway
- (C) The end product acts as a non-competitive inhibitor of an early enzyme in the pathway, slowing its own production
- (D) The end product is converted back into the original substrate
Show Answer
Answer: C – When enough product accumulates, it binds away from the active site of an early enzyme, reducing further synthesis.
Q8. Why do enzymes show specificity for their substrates?
- (A) All enzymes have identical active sites
- (B) Substrates are all the same shape
- (C) Enzymes bind any molecule that collides with them
- (D) The active site has a specific shape and chemical properties complementary to the substrate
Show Answer
Answer: D – Complementarity of shape and charge allows only a particular substrate, or close relatives, to bind effectively.
Q9. Which graph shape is expected for enzyme activity against temperature, and why does activity fall after the optimum?
- (A) Activity rises to an optimum as collisions increase, then falls sharply as the enzyme denatures
- (B) Activity falls steadily as temperature rises
- (C) Activity stays constant at all temperatures
- (D) Activity rises steadily with temperature and never falls
Show Answer
Answer: A – Higher temperature increases collision frequency up to the optimum, beyond which the tertiary structure breaks down.
Cell membranes and transport
Q10. Glycoproteins in the cell surface membrane are important for which function?
- (A) Transporting water through aquaporins
- (B) Providing energy for active transport
- (C) Forming the lipid bilayer itself
- (D) Cell recognition and adhesion, including immune recognition of self cells
Show Answer
Answer: D – Carbohydrate chains attached to membrane proteins act as identification markers for cell-to-cell recognition.
Q11. Which molecule can cross the lipid bilayer by simple diffusion most easily?
- (A) A small, non-polar molecule such as oxygen
- (B) A large charged ion such as sodium
- (C) A large polar molecule such as glucose
- (D) A protein such as haemoglobin
Show Answer
Answer: A – Small non-polar molecules dissolve in the lipid bilayer, while charged and large polar molecules need proteins.
Q12. The sodium-potassium pump is an example of active transport because it does what?
- (A) Allows sodium ions to diffuse down their gradient
- (B) Uses ATP to move sodium out and potassium in against their gradients
- (C) Opens a channel for passive movement of both ions
- (D) Transports water molecules by osmosis
Show Answer
Answer: B – The pump hydrolyses ATP to move three sodium ions out and two potassium ions in per cycle.
The mitotic cell cycle
Q13. During prophase of mitosis, which changes occur?
- (A) Chromosomes condense, the nuclear envelope breaks down, and spindle fibres form
- (B) Sister chromatids separate to opposite poles
- (C) Chromosomes align on the equator
- (D) The cell divides into two daughter cells
Show Answer
Answer: A – Condensation makes chromosomes visible and manageable, while spindle formation prepares for their separation.
Q14. Telophase of mitosis is characterised by which events?
- (A) Chromosomes condense and spindle fibres appear
- (B) Nuclear envelopes reform and chromosomes decondense
- (C) Sister chromatids are pulled apart
- (D) DNA is replicated
Show Answer
Answer: B – As two nuclei form, chromosomes unwind and the cell prepares for cytokinesis.
Q15. Cancer may develop when mutations affect genes controlling the cell cycle. Which type of gene, when mutated, fails to stop uncontrolled division?
- (A) A gene for haemoglobin production
- (B) A gene for chlorophyll synthesis
- (C) A tumour suppressor gene, which normally inhibits division or triggers repair or cell death
- (D) A gene for antibody production
Show Answer
Answer: C – Loss of tumour suppressor function removes a brake on the cycle, allowing damaged cells to proliferate.
Nucleic acids and protein synthesis
Q16. Gene control in eukaryotes often involves transcription factors. What do transcription factors do?
- (A) They copy DNA during replication
- (B) They bind to specific DNA sequences and regulate whether RNA polymerase transcribes a gene
- (C) They translate mRNA into protein at the ribosome
- (D) They cut DNA at restriction sites
Show Answer
Answer: B – By binding promoters or enhancers, transcription factors switch genes on or off in particular cells.
Q17. Which statement about the start codon is correct?
- (A) It signals the end of translation
- (B) It is found only in prokaryotic mRNA
- (C) It is AUG, coding for methionine and marking where translation begins
- (D) It codes for the final amino acid in every protein
Show Answer
Answer: C – Translation starts at AUG, so most newly synthesised proteins begin with methionine.
Q18. A nonsense mutation differs from a missense mutation in that a nonsense mutation does what?
- (A) Changes one amino acid to another
- (B) Leaves the amino acid sequence unchanged
- (C) Deletes an entire gene from the chromosome
- (D) Creates a premature stop codon, truncating the protein
Show Answer
Answer: D – A stop codon halts translation early, usually producing a shortened, non-functional protein.
Transport in plants
Q19. Which adaptation of root hair cells increases the rate of water uptake?
- (A) Thick lignified walls
- (B) Absence of a cell membrane
- (C) A large surface area from the elongated hair and a thin wall
- (D) A large permanent vacuole filled with air
Show Answer
Answer: C – The hair greatly extends surface area in contact with soil water, shortening the uptake path.
Q20. Water moves through a plant by the apoplast pathway. What does this pathway involve?
- (A) Movement through the cytoplasm of living cells via plasmodesmata
- (B) Movement through vacuoles only
- (C) Movement inside xylem vessels after reaching the endodermis
- (D) Movement through cell walls and intercellular spaces, without crossing cell membranes, until the Casparian strip
Show Answer
Answer: D – The Casparian strip in the endodermis blocks the apoplast, forcing water into the symplast for selective control.
Q21. Sinks in phloem transport include which examples?
- (A) Growing roots, developing fruits and storage organs that import assimilates
- (B) Mature photosynthetic leaves exporting sucrose
- (C) Xylem vessels carrying water upward
- (D) Stomata releasing water vapour
Show Answer
Answer: A – Any region that uses or stores assimilates acts as a sink, while mature leaves are usually sources.
Transport in mammals
Q22. After oxygenation in the lungs, blood returns to the left atrium through which vessel?
- (A) Pulmonary artery
- (B) Vena cava
- (C) Hepatic vein
- (D) Pulmonary vein
Show Answer
Answer: D – Pulmonary veins are exceptional veins carrying oxygenated blood, returning it to the left atrium.
Q23. Capillaries are adapted for exchange by which features?
- (A) Walls one cell thick, narrow lumens slowing flow, and a very large total surface area
- (B) Thick muscular walls and valves
- (C) Elastic tissue that maintains high pressure
- (D) A wide lumen and rapid blood flow
Show Answer
Answer: A – Slow flow through thin-walled, abundant capillaries maximises time and area for exchange.
Q24. Excess tissue fluid that is not reabsorbed into capillaries is returned to the blood by which system?
- (A) The hepatic portal system
- (B) The lymphatic system, draining into veins near the heart
- (C) The pulmonary circulation
- (D) The renal system only
Show Answer
Answer: B – Lymph vessels collect remaining tissue fluid, filter it through nodes, and return it to the bloodstream.
Gas exchange
Q25. In fish gills, water flows over lamellae in the opposite direction to blood flow inside them. What advantage does this arrangement give?
- (A) It maintains a diffusion gradient along the whole lamella, maximising oxygen uptake
- (B) Fish ventilate their lungs by rib movements
- (C) Fish use a diaphragm to draw water over the gills
- (D) Fish rely only on diffusion of water through their skin
Show Answer
Answer: A – Countercurrent flow keeps blood oxygen concentration below water oxygen concentration along the entire lamella, so diffusion continues throughout.
Q26. In mammals, the trachea is kept open by which structures?
- (A) Smooth muscle rings that contract fully around it
- (B) C-shaped rings of cartilage that prevent collapse while allowing the oesophagus to expand
- (C) Bone plates surrounding the airway
- (D) Alveoli attached to its walls
Show Answer
Answer: B – Incomplete cartilage rings support the trachea but leave a gap where the oesophagus lies behind it.
Q27. Goblet cells in the airways produce mucus. What is the function of this mucus combined with cilia?
- (A) To absorb oxygen into the blood
- (B) To warm inhaled air only
- (C) To trap dust and pathogens, which cilia then move upward toward the throat
- (D) To increase the surface area for gas exchange
Show Answer
Answer: C – The mucus escalator protects the delicate alveoli from particles and microbes.
Infectious diseases
Q28. Which pathogen causes malaria, and what type of organism is it?
- (A) A bacterium transmitted by contaminated water
- (B) A protoctist of the genus Plasmodium, transmitted by Anopheles mosquitoes
- (C) A virus transmitted by airborne droplets
- (D) A fungus growing on skin
Show Answer
Answer: B – Plasmodium species are protoctists with a complex life cycle in humans and mosquitoes.
Q29. Why do people with HIV become vulnerable to opportunistic infections?
- (A) HIV destroys red blood cells, causing anaemia
- (B) HIV blocks all phagocytosis immediately
- (C) HIV destroys helper T cells, weakening both humoral and cell-mediated immunity
- (D) HIV prevents the skin from acting as a barrier
Show Answer
Answer: C – Without helper T cell coordination, antibody production and killer T cell activity both decline.
Q30. The best strategy to reduce antibiotic resistance in hospitals includes which combination?
- (A) Prescribing antibiotics for all viral infections as a precaution
- (B) Stopping antibiotic courses as soon as symptoms improve
- (C) Sharing antibiotics between patients to save supplies
- (D) Prescribing antibiotics only when needed, completing courses, and practising strict hygiene
Show Answer
Answer: D – Stewardship reduces selection pressure for resistance and limits spread of resistant strains.
Immunity
Q31. Clonal selection in B lymphocytes means what?
- (A) All B cells produce the same antibody regardless of antigen
- (B) B cells mutate to create a new antigen
- (C) A B cell with a receptor matching an antigen is selected to divide, producing identical plasma cells and memory cells
- (D) B cells are selected by antibiotics in the blood
Show Answer
Answer: C – Only the matching clone expands, giving a specific response tailored to that pathogen.
Q32. Autoimmune disease occurs when the immune system does what?
- (A) Fails to produce any antibodies
- (B) Produces antibodies only against foreign antigens
- (C) Loses all memory cells after infection
- (D) Mistakenly attacks the body’s own tissues as if they were foreign
Show Answer
Answer: D – Loss of self-tolerance leads to damage, as in type 1 diabetes or multiple sclerosis.
Q33. Natural active immunity is acquired by which route?
- (A) Infection with a pathogen, followed by the body’s own immune response and memory cell formation
- (B) Injection of ready-made antibodies
- (C) Vaccination with a weakened pathogen
- (D) Transfer of antibodies across the placenta only
Show Answer
Answer: A – Natural active immunity follows real infection, unlike artificial active immunity from vaccination.
Energy and respiration
Q34. Glycolysis occurs in the cytoplasm and produces which net yield per glucose molecule?
- (A) 32 ATP and 2 reduced NAD
- (B) 4 ATP, no reduced NAD and 1 pyruvate
- (C) 6 ATP and 6 carbon dioxide
- (D) A net yield of 2 ATP, 2 reduced NAD and 2 pyruvate molecules
Show Answer
Answer: D – Glycolysis breaks glucose into two pyruvates, with a small net ATP gain before the link reaction and Krebs cycle.
Q35. The link reaction converts pyruvate to acetyl coenzyme A. What else is produced in this step?
- (A) Carbon dioxide and reduced NAD
- (B) Oxygen and ATP directly
- (C) Glucose and water
- (D) Lactate and ethanol
Show Answer
Answer: A – Decarboxylation removes carbon dioxide and dehydrogenation produces reduced NAD for oxidative phosphorylation.
Q36. Why does cyanide poisoning rapidly stop aerobic respiration?
- (A) It prevents glycolysis in the cytoplasm
- (B) It inhibits the final cytochrome in the electron transport chain, so electrons cannot be passed to oxygen
- (C) It breaks down all ATP in the cell
- (D) It prevents glucose entering the cell
Show Answer
Answer: B – Blocking electron transport stops proton pumping, so chemiosmosis and ATP synthesis collapse.
Photosynthesis
Q37. Which statement about photosystem I and photosystem II is correct?
- (A) Photosystem II acts first, splitting water and passing electrons via carriers to photosystem I
- (B) Photosystem I acts first and directly splits water
- (C) Only photosystem I is involved in non-cyclic photophosphorylation
- (D) Both photosystems produce glucose directly
Show Answer
Answer: A – The Z-scheme runs from photosystem II to photosystem I, generating ATP and reduced NADP.
Q38. In the Calvin cycle, carbon dioxide is fixed by combining with which molecule, catalysed by which enzyme?
- (A) Glycerate 3-phosphate, catalysed by ATP synthase
- (B) Ribulose bisphosphate, catalysed by rubisco
- (C) Triose phosphate, catalysed by chlorophyll
- (D) Glucose, catalysed by amylase
Show Answer
Answer: B – Rubisco catalyses fixation of carbon dioxide to the five-carbon acceptor, forming an unstable six-carbon intermediate.
Q39. At low temperature, photosynthesis rate is limited mainly because of what?
- (A) Stomata close permanently
- (B) Chlorophyll is destroyed
- (C) Enzyme activity in the Calvin cycle is reduced, slowing carbon fixation
- (D) Light absorption stops completely
Show Answer
Answer: C – Low kinetic energy reduces enzyme-catalysed reactions, even when light and carbon dioxide are available.
Homeostasis
Q40. Negative feedback is essential in homeostasis because it does what?
- (A) Amplifies any change in the internal environment
- (B) Reverses a change, returning the controlled variable toward its set point
- (C) Prevents any response to external stimuli
- (D) Maintains a variable at a constantly rising level
Show Answer
Answer: B – A corrective response opposes the original deviation, keeping conditions within a narrow range.
Q41. Which hormone is released by the posterior pituitary gland to regulate water balance?
- (A) Insulin
- (B) Glucagon
- (C) Antidiuretic hormone
- (D) Thyroxine
Show Answer
Answer: C – ADH is made in the hypothalamus and released from the posterior pituitary when blood water potential falls.
Q42. In osmoregulation, a person who drinks a large volume of water will produce urine that is how different, and why?
- (A) Small in volume and concentrated, because ADH rises
- (B) Large in volume and dark, because the kidney cannot process water
- (C) Unchanged, because water intake does not affect ADH
- (D) Large in volume and dilute, because ADH falls and less water is reabsorbed
Show Answer
Answer: D – Rising blood water potential suppresses ADH, so collecting ducts become less permeable and excess water is excreted.
Control and coordination
Q43. Which sequence correctly describes transmission across a synapse?
- (A) Neurotransmitter is released from the postsynaptic membrane into the presynaptic cell
- (B) An action potential jumps directly from one neurone to the next without chemicals
- (C) Neurotransmitter diffuses across the synaptic cleft, binds receptors, and triggers a response in the postsynaptic cell
- (D) Calcium ions flow from the postsynaptic cell into the presynaptic cell
Show Answer
Answer: C – Calcium influx triggers vesicle fusion in the presynaptic terminal, releasing transmitter into the cleft.
Q44. The resting potential of a neurone is maintained mainly by which mechanism?
- (A) Open sodium channels allowing sodium to flood in
- (B) Closed potassium channels preventing any potassium movement
- (C) Neurotransmitter constantly released at synapses
- (D) Sodium-potassium pumps and differential membrane permeability, keeping the inside negative relative to outside
Show Answer
Answer: D – Pumping sodium out and potassium in, with more potassium leakage, gives a resting potential of about minus 70 millivolts.
Q45. Which plant hormone promotes fruit ripening and leaf abscission?
- (A) Ethene
- (B) Auxin only
- (C) Gibberellin only
- (D) Cytokinin only
Show Answer
Answer: A – Ethene is a gaseous hormone that accelerates ripening and promotes shedding of leaves and fruits.
Inheritance
Q46. A man with blood group AB marries a woman with blood group O. What blood groups are possible in their children?
- (A) AB only
- (B) O only
- (C) AB and O only
- (D) A and B only
Show Answer
Answer: D – The AB parent passes either IA or IB, and the O parent passes IO, giving children of group A or B.
Q47. Colour blindness is an X-linked recessive condition. A colour-blind man marries a woman with normal vision whose father was colour-blind. What proportion of their daughters will be colour-blind?
- (A) Half of their daughters
- (B) None, because daughters receive a normal X chromosome from their mother in every case
- (C) All of their daughters
- (D) One quarter of their daughters
Show Answer
Answer: A – The mother is a carrier, so half her daughters receive her affected X together with their father’s affected X and are colour-blind.
Q48. In a monohybrid cross between two heterozygotes, the genotypic ratio in the offspring is which ratio?
- (A) 3:1 dominant to recessive phenotype
- (B) 1 homozygous dominant : 2 heterozygous : 1 homozygous recessive
- (C) 9:3:3:1
- (D) 1:1
Show Answer
Answer: B – The phenotypic ratio is 3:1, but the underlying genotypes split 1:2:1.
Selection and evolution
Q49. Which definition of a species is most widely used in A-Level biology?
- (A) A group of organisms that can interbreed to produce fertile offspring
- (B) A group of organisms that look identical
- (C) A group of organisms living in the same habitat
- (D) A group of organisms with the same chromosome number only
Show Answer
Answer: A – The biological species concept is based on reproductive isolation, although it is difficult to apply to asexual organisms and fossils.
Q50. Stabilising selection is most likely to occur in which situation?
- (A) A population colonises a completely new environment
- (B) The environment is stable and the average phenotype is already well adapted
- (C) Two different niches favour opposite extremes
- (D) A new predator favours only the largest individuals
Show Answer
Answer: B – In stable conditions, extremes are selected against and the mean phenotype is preserved.
Q51. Genetic drift has the greatest effect in which populations?
- (A) Very large populations with random mating
- (B) Populations with high gene flow
- (C) Small populations, where chance events can change allele frequencies markedly
- (D) Populations under strong directional selection only
Show Answer
Answer: C – In small populations, sampling effects are large, so alleles can be lost or fixed by chance.
Q52. Using the Hardy-Weinberg equation, if the frequency of a recessive allele is 0.2, what is the expected frequency of homozygous recessive individuals?
- (A) 0.04
- (B) 0.20
- (C) 0.40
- (D) 0.80
Show Answer
Answer: A – Homozygous recessive frequency is q squared, which is 0.2 times 0.2, giving 0.04.
Classification, biodiversity and conservation
Q53. Which level of biodiversity refers to variation in genes within a species?
- (A) Ecosystem diversity
- (B) Genetic diversity
- (C) Species diversity only
- (D) Habitat diversity only
Show Answer
Answer: B – Genetic diversity is the range of alleles within a species, important for adaptation and survival.
Q54. Habitat fragmentation threatens species because it does what?
- (A) Increases the total area of habitat available
- (B) Connects populations with corridors
- (C) Isolates small populations, increasing inbreeding and edge effects
- (D) Removes all predators from the area
Show Answer
Answer: C – Fragmented patches support smaller populations that are more vulnerable to chance extinction.
Q55. Which conservation approach involves protecting a whole ecosystem in a national park?
- (A) Captive breeding in a zoo
- (B) Seed banking
- (C) Botanical garden cultivation
- (D) In situ conservation
Show Answer
Answer: D – National parks and reserves protect species where they live, preserving their habitats and interactions.
Q56. The main ethical argument against keeping endangered animals only in zoos is which concern?
- (A) Zoos are always more expensive than reserves
- (B) Animals cannot breed in captivity at all
- (C) Captive populations lose all genetic diversity immediately
- (D) Ex situ conservation alone cannot preserve natural behaviours, interactions and evolutionary processes
Show Answer
Answer: D – While zoos help as a backup, they cannot replace wild habitats for maintaining a species in its ecological context.
Genetic technology
Q57. A vector in genetic engineering is best defined as what?
- (A) A bacterium that produces antibiotics
- (B) An enzyme that cuts DNA
- (C) A carrier DNA molecule, such as a plasmid, used to transfer a gene into a host cell
- (D) A primer used in PCR
Show Answer
Answer: C – Plasmids can accept foreign DNA and replicate inside host bacteria, amplifying the gene.
Q58. DNA ligase is used in recombinant DNA technology to do what?
- (A) Cut DNA at specific sequences
- (B) Amplify DNA by PCR
- (C) Separate DNA fragments by size
- (D) Join DNA fragments by forming phosphodiester bonds between them
Show Answer
Answer: D – Ligase seals nicks in the sugar-phosphate backbone after a gene is inserted into a vector.
Q59. Which application of genetic technology raises the most direct concern about gene flow to wild relatives?
- (A) Growing herbicide-resistant GM crops near wild relatives that could receive the gene by pollination
- (B) Using PCR in a laboratory to diagnose disease
- (C) Producing insulin in contained bacterial fermenters
- (D) Using DNA profiling for forensic identification
Show Answer
Answer: A – Pollen transfer could spread engineered traits to wild plants, potentially creating resistant weeds.
Q60. In PCR, primers are needed because DNA polymerase can only do what?
- (A) Copy DNA without a template, using primers as a guide for the whole genome
- (B) Start synthesis at a free 3-prime hydroxyl group and extend an existing strand
- (C) Denature DNA at high temperature
- (D) Join Okazaki fragments on the lagging strand
Show Answer
Answer: B – Polymerase cannot start a new strand from scratch; it adds nucleotides to the 3-prime end of a primer annealed to the template.
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