A-Level Biology Practice Test 18 – 60 Questions with Answers (Cambridge 9700)
This test focuses on the details that separate good answers from excellent ones, including control mechanisms, quantitative reasoning and gene regulation.
Cell structure
Q1. Which organelle is responsible for producing most of the ATP in an animal cell, and which structural feature increases its efficiency?
- (A) Mitochondrion, with folded inner membranes (cristae) giving a large surface for electron transport
- (B) Ribosome, with a large subunit that binds mRNA
- (C) Lysosome, with hydrolytic enzymes in an acidic interior
- (D) Nucleus, with pores that allow mRNA to leave
Show Answer
Answer: A – Cristae increase the area available for electron transport chains and ATP synthase, raising ATP output.
Q2. Centrioles are found in animal cells and play a role in which process?
- (A) Protein secretion through vesicles
- (B) Formation of spindle fibres during cell division
- (C) Photosynthesis in the cytoplasm
- (D) Storage of starch grains
Show Answer
Answer: B – Centrioles organise microtubules that form the spindle, although plant cells form spindles without them.
Q3. An electron microscope gives much higher resolution than a light microscope mainly because it uses what?
- (A) Visible light of a longer wavelength
- (B) Stains that colour organelles brightly
- (C) A beam of electrons with a much shorter wavelength than light
- (D) A larger lens that magnifies the specimen more
Show Answer
Answer: C – Shorter wavelength radiation can resolve smaller structures, revealing organelle ultrastructure in detail.
Biological molecules
Q4. The Benedict test for reducing sugars gives a positive result when what happens?
- (A) A blue-black colour appears on heating with iodine solution
- (B) A brick-red precipitate forms on heating with Benedict reagent
- (C) A purple colour appears on adding sodium hydroxide and copper sulfate
- (D) A white emulsion forms on adding ethanol
Show Answer
Answer: B – Reducing sugars reduce copper(II) ions in Benedict reagent to copper(I) oxide, forming a brick-red precipitate.
Q5. Amylose and amylopectin are both components of starch. How do they differ structurally?
- (A) Amylose is branched and amylopectin is unbranched
- (B) Amylose is made of beta-glucose and amylopectin of alpha-glucose
- (C) Amylose is an unbranched helix of alpha-glucose, while amylopectin is branched with 1,6-glycosidic bonds at branch points
- (D) Amylose is a protein and amylopectin is a lipid
Show Answer
Answer: C – Branching in amylopectin provides many ends for rapid hydrolysis, while helical amylose packs compactly.
Q6. Which test would confirm the presence of protein in a food sample?
- (A) Iodine test giving a blue-black colour
- (B) Benedict test giving a brick-red precipitate
- (C) Emulsion test giving a cloudy white suspension
- (D) Biuret test giving a purple colour
Show Answer
Answer: D – In the biuret test, copper ions in alkaline solution form a purple complex with peptide bonds.
Enzymes
Q7. In an investigation of enzyme activity, the rate increases with substrate concentration and then levels off. What explains the plateau?
- (A) The enzyme is denatured by excess substrate
- (B) The pH of the solution changes at high concentration
- (C) All active sites are occupied, so the enzyme is working at its maximum rate
- (D) Substrate molecules stop colliding with enzyme molecules
Show Answer
Answer: C – Once active sites are saturated, adding more substrate cannot increase the rate further.
Q8. Immobilised lactase is used to produce lactose-free milk. Which advantage is specific to immobilisation in this process?
- (A) Lactase becomes able to digest starch as well as lactose
- (B) Lactase works at any temperature without denaturing
- (C) Lactase no longer needs lactose as a substrate
- (D) Lactase can be retained in the reactor and reused, so it does not remain in the milk
Show Answer
Answer: D – Keeping the enzyme out of the product avoids altering the milk and allows the same enzyme to treat many batches.
Q9. A student investigates the effect of pH on amylase activity using a buffer. Why is a buffer important in this experiment?
- (A) It keeps the pH constant so that only the chosen pH variable is tested
- (B) It increases the temperature of the reaction mixture
- (C) It supplies extra substrate for the enzyme
- (D) It prevents the enzyme from being denatured at any pH
Show Answer
Answer: A – Without a buffer, pH could drift during the reaction and confound the results.
Cell membranes and transport
Q10. A red blood cell placed in a solution of lower water potential than its cytoplasm will do what?
- (A) Gain water by osmosis and burst
- (B) Remain unchanged because its membrane is impermeable to water
- (C) Gain solutes by active transport until equilibrium is reached
- (D) Lose water by osmosis and crenate
Show Answer
Answer: D – Water moves from higher water potential inside the cell to lower water potential outside, shrinking the cell.
Q11. Carrier proteins differ from channel proteins in facilitated diffusion in that carrier proteins do what?
- (A) Change shape to move a specific molecule across the membrane
- (B) Form a permanently open water-filled pore
- (C) Use ATP directly for every molecule transported
- (D) Transport only water molecules
Show Answer
Answer: A – Carrier proteins bind their molecule, change conformation, and release it on the other side, whereas channels provide a pore.
Q12. Plasmolysis of a plant cell occurs when the cell is placed in a concentrated solution because of what?
- (A) Water entering the vacuole faster than solutes leave
- (B) Water leaving the cell by osmosis, so the protoplast shrinks away from the cell wall
- (C) The cell wall dissolving in the concentrated solution
- (D) Active transport of water out of the cell using ATP
Show Answer
Answer: B – Loss of water reduces turgor until the cell membrane pulls away from the wall.
The mitotic cell cycle
Q13. Which event characterises metaphase of mitosis?
- (A) Chromosomes line up along the equator, attached to spindle fibres at their centromeres
- (B) Sister chromatids separate to opposite poles
- (C) DNA replicates to form sister chromatids
- (D) Two daughter nuclei form and cytokinesis begins
Show Answer
Answer: A – Alignment at the equator ensures that each daughter cell will receive one chromatid from every chromosome.
Q14. Mitosis is important for growth and repair because it produces daughter cells that are what?
- (A) Haploid and genetically different from the parent
- (B) Genetically identical to the parent cell and to each other
- (C) Diploid but with half the chromosomes of the parent
- (D) Specialised immediately and unable to divide again
Show Answer
Answer: B – Identical daughter cells maintain the genetic consistency needed for growth and tissue repair.
Q15. Which statement correctly contrasts mitosis with binary fission in bacteria?
- (A) Binary fission produces four genetically different cells
- (B) Mitosis occurs only in prokaryotes
- (C) Mitosis involves a spindle and a nucleus, while binary fission copies a circular chromosome and divides the cell without mitotic apparatus
- (D) Binary fission involves meiosis and fertilisation
Show Answer
Answer: C – Binary fission is simpler than mitosis: the single circular chromosome is copied and the cell divides, with no spindle or nucleus involved.
Nucleic acids and protein synthesis
Q16. Which property of the genetic code means that most amino acids are encoded by more than one codon?
- (A) It is non-overlapping
- (B) It is degenerate
- (C) It is universal in all organisms
- (D) It contains start and stop codons
Show Answer
Answer: B – Degeneracy means several codons can specify the same amino acid, buffering some mutations.
Q17. During mRNA processing in eukaryotes, introns are removed and exons are joined. What is this process called?
- (A) Translation
- (B) Replication
- (C) Splicing
- (D) Transcription
Show Answer
Answer: C – Splicing produces mature mRNA containing only coding sequences, ready for export to the cytoplasm.
Q18. An insertion of a single nucleotide into a coding sequence is usually more harmful than a substitution because it does what?
- (A) Changes only one amino acid in the protein
- (B) Prevents mRNA from leaving the nucleus
- (C) Stops ribosomes from binding to mRNA
- (D) Shifts the reading frame, changing all downstream codons
Show Answer
Answer: D – A frameshift alters every subsequent amino acid and often introduces a premature stop codon.
Transport in plants
Q19. Evidence for the mass flow hypothesis includes the observation that phloem sap moves at speeds that are what?
- (A) Far too slow to be explained by diffusion alone
- (B) Identical in all directions at all times
- (C) Much faster than diffusion could achieve, consistent with bulk flow under pressure
- (D) Independent of source and sink activity
Show Answer
Answer: C – Measured sap velocities of around one metre per hour far exceed diffusion rates, supporting mass flow.
Q20. Aphids feeding on phloem provide evidence about translocation because their stylets do what?
- (A) Block phloem transport completely
- (B) Inject toxins that kill sieve tube elements
- (C) Absorb water only from xylem vessels
- (D) Penetrate a single sieve tube, allowing sap to be collected and analysed under pressure
Show Answer
Answer: D – When an aphid is removed, sap continues to exude from the stylet, showing that phloem contents are under positive pressure.
Q21. Companion cells are closely associated with sieve tube elements in phloem. Which feature of companion cells most directly supports active loading of sucrose?
- (A) Many mitochondria supplying ATP for co-transport of sucrose into sieve tubes
- (B) Dead, hollow tubes with lignified walls
- (C) Chloroplasts that carry out photosynthesis for the sieve tube
- (D) Lignified walls that withstand tension from transpiration pull
Show Answer
Answer: A – Companion cells provide ATP for active loading, which raises solute concentration in sieve tubes and drives mass flow.
Transport in mammals
Q22. During the cardiac cycle, the atrioventricular valves close when what happens?
- (A) The atria contract and fill the ventricles
- (B) Blood flows from the veins into the atria
- (C) The semilunar valves open
- (D) Ventricular pressure exceeds atrial pressure as the ventricles contract
Show Answer
Answer: D – Rising ventricular pressure pushes the valve cusps shut, preventing backflow into the atria and producing the first heart sound.
Q23. Fetal haemoglobin has a higher affinity for oxygen than adult haemoglobin. Why is this advantageous?
- (A) It allows oxygen to be transferred from maternal blood to fetal blood across the placenta
- (B) It allows the fetus to release oxygen more easily in its tissues
- (C) It prevents the mother from losing oxygen to the fetus
- (D) It increases the oxygen-carrying capacity of maternal blood
Show Answer
Answer: A – At the low oxygen partial pressures in the placenta, fetal haemoglobin still loads oxygen effectively from maternal haemoglobin.
Q24. Myoglobin in muscle has a very high affinity for oxygen and a dissociation curve shifted far to the left. What does this imply?
- (A) Myoglobin releases oxygen readily at normal tissue oxygen levels
- (B) Myoglobin stores oxygen and releases it only when tissue oxygen levels fall very low
- (C) Myoglobin transports oxygen in the blood plasma
- (D) Myoglobin replaces haemoglobin in red blood cells
Show Answer
Answer: B – Myoglobin acts as an oxygen reserve for respiring muscle, unloading only during intense exercise when oxygen is scarce.
Gas exchange
Q25. In leaves, gas exchange for photosynthesis occurs mainly through which structures, and what controls their opening?
- (A) Stomata, whose guard cells change turgidity in response to light, carbon dioxide and water availability
- (B) Lenticels, which open and close with temperature
- (C) Root hairs, which absorb gases from soil
- (D) Xylem vessels, which carry gases upward
Show Answer
Answer: A – Guard cells become turgid and open the pore when conditions favour photosynthesis, and lose turgor to close it.
Q26. Insects can close their spiracles. What is the advantage of this control?
- (A) It increases oxygen uptake during flight
- (B) It reduces water loss while still allowing periodic gas exchange
- (C) It allows insects to breathe underwater
- (D) It prevents carbon dioxide from leaving the body
Show Answer
Answer: B – Closing spiracles limits evaporation from the tracheal system, an important adaptation for small terrestrial animals.
Q27. Which feature of fish gill lamellae increases gas exchange efficiency?
- (A) Thick walls that protect against water damage
- (B) A small surface area to reduce water flow
- (C) A large surface area, thin walls and a rich blood supply
- (D) A countercurrent flow of blood in the same direction as water
Show Answer
Answer: C – Lamellae provide extensive thin surfaces with capillaries, while countercurrent flow maintains the gradient.
Infectious diseases
Q28. Cholera toxin causes severe diarrhoea by acting on intestinal cells in which way?
- (A) It destroys red blood cells in the gut wall
- (B) It causes chloride ions and water to be secreted into the gut lumen
- (C) It blocks all absorption of glucose in the small intestine
- (D) It prevents the liver from producing bile
Show Answer
Answer: B – Toxin-induced chloride secretion draws water into the lumen by osmosis, causing rapid fluid loss.
Q29. Which factor most increases the spread of infectious disease in a population?
- (A) Widespread vaccination coverage
- (B) Clean water supplies and effective sewage treatment
- (C) Overcrowding, poor sanitation and limited access to healthcare
- (D) Quarantine of symptomatic individuals
Show Answer
Answer: C – Crowding and poor sanitation increase contact and transmission, while weak healthcare delays treatment and isolation.
Q30. A virus differs from a bacterium in that a virus does what?
- (A) Has its own ribosomes and mitochondria
- (B) Reproduces independently outside a host cell
- (C) Carries out aerobic respiration in its cytoplasm
- (D) Must infect a host cell and use its machinery to replicate
Show Answer
Answer: D – Viruses are non-living particles of nucleic acid in a protein coat, unable to replicate without a host.
Immunity
Q31. Helper T cells coordinate the immune response by doing what?
- (A) Directly producing antibodies against pathogens
- (B) Engulfing pathogens by phagocytosis
- (C) Releasing cytokines that activate B cells, killer T cells and phagocytes
- (D) Forming the physical barrier of the skin
Show Answer
Answer: C – Cytokines from helper T cells stimulate clonal expansion of the appropriate specific immune cells.
Q32. Killer T cells destroy infected body cells by recognising what on their surface?
- (A) Antibodies bound to the cell membrane
- (B) Complement proteins in the blood plasma
- (C) Hormones secreted by the infected cell
- (D) Foreign antigens presented on the cell surface
Show Answer
Answer: D – Infected cells display fragments of pathogen protein, marking them for destruction by killer T cells.
Q33. Herd immunity protects unvaccinated individuals in a population because of what effect?
- (A) High vaccination coverage reduces transmission, so the pathogen rarely reaches susceptible people
- (B) Vaccinated people produce antibodies that pass to unvaccinated neighbours
- (C) The pathogen becomes less virulent in vaccinated populations
- (D) Unvaccinated people develop memory cells by contact with vaccinated people
Show Answer
Answer: A – When most people are immune, chains of transmission break, indirectly shielding those who cannot be vaccinated.
Energy and respiration
Q34. Chemiosmosis in mitochondria depends on which gradient and structure?
- (A) A glucose gradient across the outer membrane and ATP synthase in the matrix
- (B) A sodium gradient across the cell surface membrane and carrier proteins
- (C) An oxygen gradient across the cristae and ribosomes
- (D) A proton gradient across the inner mitochondrial membrane and ATP synthase channels
Show Answer
Answer: D – Protons pumped into the intermembrane space flow back through ATP synthase, driving ATP formation.
Q35. Which feature adapts mitochondria for their function in active cells?
- (A) A large inner membrane surface area, many ATP synthase molecules and enzymes for the Krebs cycle
- (B) A single membrane with no internal compartments
- (C) Chlorophyll pigments for capturing light energy
- (D) Ribosomes that synthesise all mitochondrial proteins independently
Show Answer
Answer: A – Extensive cristae and abundant respiratory enzymes support high rates of aerobic ATP production.
Q36. Anaerobic respiration in plants (for example, in waterlogged roots) produces ethanol. Why is this harmful if it continues?
- (A) It yields no ATP at all
- (B) It produces toxic ethanol and yields far less ATP than aerobic respiration, so energy supply is limited
- (C) It consumes all available carbon dioxide
- (D) It prevents glycolysis from occurring
Show Answer
Answer: B – Ethanol accumulation damages cells, and the low ATP yield cannot sustain prolonged activity.
Photosynthesis
Q37. In the light-dependent stage, excited electrons from photosystem II are replaced by electrons from what source?
- (A) Photolysis of water
- (B) Reduction of NADP
- (C) The Calvin cycle
- (D) Chlorophyll b alone
Show Answer
Answer: A – Splitting water supplies replacement electrons, protons and oxygen for the electron transport chain.
Q38. Triose phosphate produced in the Calvin cycle has which two main fates?
- (A) It is always converted directly to starch in the chloroplast
- (B) It is used to regenerate ribulose bisphosphate or exported to make glucose, sucrose, amino acids and lipids
- (C) It is oxidised immediately in respiration with no other use
- (D) It is stored as chlorophyll in the thylakoids
Show Answer
Answer: B – Most triose phosphate regenerates the carbon dioxide acceptor, while the remainder provides building blocks for the plant.
Q39. A student separates leaf pigments by chromatography. Which pigment would travel furthest if it is most soluble in the solvent and least attracted to the paper?
- (A) The pigment with the lowest Rf value
- (B) The pigment that remains at the origin
- (C) The pigment with the highest Rf value
- (D) The pigment that is insoluble in the solvent
Show Answer
Answer: C – Rf is distance moved by the pigment divided by distance moved by the solvent, so the furthest pigment has the highest Rf.
Homeostasis
Q40. When blood water potential falls, osmoreceptors in the hypothalamus trigger which response?
- (A) Reduced ADH release and more dilute urine
- (B) Increased ADH release, more water reabsorbed in the collecting duct, and more concentrated urine
- (C) Increased insulin release from the pancreas
- (D) Vasodilation of skin arterioles
Show Answer
Answer: B – ADH increases collecting duct permeability, conserving water until blood water potential returns to normal.
Q41. The loop of Henle creates a solute gradient in the kidney medulla mainly by which mechanism?
- (A) Active pumping of water out of the descending limb
- (B) Reabsorption of glucose in the ascending limb
- (C) Active transport of sodium and chloride ions out of the ascending limb, which is impermeable to water
- (D) Secretion of urea into the glomerular filtrate
Show Answer
Answer: C – Salt pumped out of the ascending limb builds the medullary gradient that later allows water reabsorption.
Q42. Glucagon raises blood glucose by acting on the liver to promote which processes?
- (A) Glycogenesis and lipogenesis only
- (B) Uptake of glucose by muscle cells
- (C) Conversion of glucose to fat in adipose tissue
- (D) Glycogenolysis and gluconeogenesis
Show Answer
Answer: D – Glucagon stimulates breakdown of glycogen and synthesis of glucose from non-carbohydrate sources.
Q43. In cold conditions, shivering helps maintain body temperature because it does what?
- (A) Generates heat by rapid involuntary muscle contractions, increasing respiration rate
- (B) Reduces blood flow to the skin
- (C) Increases sweat evaporation from the skin
- (D) Causes hairs to stand erect, trapping air
Show Answer
Answer: A – Muscle contraction is an exothermic process, so shivering releases heat that warms the core.
Control and coordination
Q44. Auxin promotes phototropism in a shoot by doing what?
- (A) Inhibiting cell elongation on the shaded side
- (B) Causing equal growth on both sides of the shoot
- (C) Accumulating on the shaded side and promoting faster cell elongation there, bending the shoot toward light
- (D) Destroying cells on the illuminated side
Show Answer
Answer: C – Unequal auxin distribution produces unequal elongation, so the shoot bends toward the light source.
Q45. At the neuromuscular junction, acetylcholine is released from the motor neurone and binds to receptors on the muscle fibre. What follows if threshold is reached?
- (A) The muscle fibre becomes permanently contracted
- (B) Calcium ions are pumped out of the sarcoplasm immediately
- (C) The motor neurone stops releasing neurotransmitter forever
- (D) An action potential spreads over the muscle membrane and triggers contraction
Show Answer
Answer: D – Depolarisation of the muscle membrane leads to calcium release from the sarcoplasmic reticulum and sliding filament contraction.
Q46. The pupil constricts in bright light as part of a reflex. Which effector is involved?
- (A) Circular muscles of the iris contracting
- (B) Radial muscles of the iris contracting
- (C) Ciliary muscles relaxing
- (D) Suspensory ligaments tightening
Show Answer
Answer: A – Contraction of circular iris muscles reduces pupil diameter, limiting light entering the eye.
Q47. Hormonal coordination differs from nervous coordination in that hormonal responses are generally what?
- (A) Faster and more localised
- (B) Transmitted electrically along neurones
- (C) Limited to a single target cell
- (D) Slower, longer-lasting and more widespread, travelling in the blood
Show Answer
Answer: D – Hormones travel in blood to many target cells and are broken down slowly, so their effects persist longer.
Inheritance
Q48. If two genes are linked, a dihybrid test cross is expected to produce which pattern?
- (A) Equal numbers of all four phenotypes, as with independent assortment
- (B) Only the two parental phenotypes, with no recombinants at all
- (C) Only recombinant phenotypes
- (D) Mostly parental phenotypes, with fewer recombinant phenotypes from crossing over
Show Answer
Answer: D – Linked genes usually stay together, but crossing over produces a minority of recombinant offspring.
Q49. Epistasis occurs when one gene does what to another gene?
- (A) Masks or modifies the expression of a different gene
- (B) Is located on the same chromosome as another gene
- (C) Codes for the same protein as another gene
- (D) Is inherited only on the X chromosome
Show Answer
Answer: A – In epistasis, an allele at one locus suppresses the phenotypic effect of alleles at another locus.
Q50. A chi-squared test is used in genetics to assess what?
- (A) The exact genotype of every offspring
- (B) Whether observed offspring ratios differ significantly from expected ratios, or are consistent with chance variation
- (C) The mutation rate in a population
- (D) The age of a fossil lineage
Show Answer
Answer: B – A small chi-squared value suggests observed results fit the expected ratio, while a large value suggests a real deviation.
Q51. Polygenic inheritance, such as human height, is characterised by what?
- (A) Two discrete phenotypes controlled by one gene
- (B) Continuous variation controlled by many genes plus environmental influences
- (C) Inheritance only through the maternal line
- (D) A fixed 3:1 ratio in every cross
Show Answer
Answer: B – Many genes each contribute a small effect, producing a normal distribution of phenotypes.
Selection and evolution
Q52. Disruptive selection favours which phenotypes?
- (A) Both extremes over the intermediate phenotype
- (B) Only the intermediate phenotype
- (C) Only one extreme phenotype
- (D) All phenotypes equally
Show Answer
Answer: A – When extremes suit different niches, intermediates are selected against and variation increases.
Q53. Antibiotic resistance in bacteria is an example of evolution in action because it shows what?
- (A) Antibiotics create resistant mutations on demand
- (B) Selection increases the frequency of resistant alleles already present in the population
- (C) All bacteria become resistant after one exposure
- (D) Resistance is inherited through learned behaviour
Show Answer
Answer: B – Resistant variants survive treatment and reproduce, so their alleles become more common over generations.
Q54. Fossil evidence supports evolution because fossils show what?
- (A) That all species alive today existed unchanged in the earliest rocks
- (B) That species appear suddenly with no predecessors
- (C) A sequence of forms over geological time, with transitional features linking groups
- (D) That extinction has never occurred
Show Answer
Answer: C – The fossil record documents change over time and intermediate forms between major groups.
Classification, biodiversity and conservation
Q55. A newly discovered single-celled organism has no nucleus, a cell wall without peptidoglycan, and lives in a hot acidic spring. In which domain is it most likely classified?
- (A) Eukarya
- (B) Archaea
- (C) Plantae and Animalia
- (D) Fungi and Protista
Show Answer
Answer: B – Archaea are prokaryotes that often live in extreme environments and lack peptidoglycan, unlike bacteria.
Q56. A binomial name, such as Homo sapiens, is written with which convention?
- (A) Both words capitalised and underlined separately
- (B) Common name first, then genus
- (C) Genus capitalised and species lower case, both italicised or underlined
- (D) Species capitalised and genus lower case
Show Answer
Answer: C – The genus name comes first with a capital, followed by the specific epithet in lower case.
Q57. CITES is an international agreement that aims to protect biodiversity by doing what?
- (A) Banning all scientific research on endangered species
- (B) Funding zoos in every country
- (C) Requiring all habitats to become national parks
- (D) Regulating international trade in endangered plants and animals
Show Answer
Answer: D – By controlling trade in listed species, CITES reduces pressure from collection and trafficking.
Genetic technology
Q58. Which sequence correctly lists the main steps in producing recombinant human insulin in bacteria?
- (A) Insert gene into plasmid, transform bacteria, culture bacteria, extract insulin
- (B) Culture bacteria, extract insulin, insert gene, transform bacteria
- (C) Cut human DNA and plasmid with the same restriction enzyme, join them with ligase, transform bacteria, culture and harvest product
- (D) Transform bacteria, cut plasmid, join gene, extract insulin without culturing
Show Answer
Answer: C – Matching sticky ends allow the gene to be inserted into the plasmid, which is then taken up by bacteria for expression.
Q59. Gene therapy for a genetic disorder aims to do what?
- (A) Remove all genes from the affected tissue
- (B) Change the DNA of every cell in the body permanently in all treatments
- (C) Prevent the disorder from being inherited by altering gametes in somatic therapy
- (D) Replace a faulty gene with a working copy in affected cells, or add a functional gene
Show Answer
Answer: D – Somatic gene therapy introduces a functional gene into affected body cells, without altering gametes.
Q60. PCR is useful in forensic science because it can do what?
- (A) Amplify tiny amounts of DNA from a sample to produce enough material for profiling
- (B) Sequence an entire genome in a single step without primers
- (C) Repair damaged DNA in a crime scene sample
- (D) Identify a suspect from fingerprints alone
Show Answer
Answer: A – Repeated cycles of denaturation, annealing and extension copy a target sequence exponentially.
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