Redox Reaction and Method for Balancing Redox Reaction MCQs

Balancing redox reactions can be quite complex, so a systematic approach is essential. The half-reaction method for balancing redox reactions highlights that redox reactions can be divided into two separate processes: an oxidation half-reaction, which shows only the oxidation process, and a reduction half-reaction, which shows only the reduction process. To achieve an overall balanced reaction, the two half-reactions are combined so that the electrons in each half-reaction cancel out. This method is particularly useful for reactions occurring in aqueous solutions. By combining the two half-reactions, a balanced redox equation is obtained.

(a) Zn acts as an oxidising agent when it reacts with HNO3
(b) HNO3 is a weaker acid than H2SO4 and HCl
(c) In electrochemical series, Zn is above hydrogen
(d) NO3– is reduced in preference to hydronium ion

(d) NO3– is reduced in preference to hydronium ion

(a) -1
(b) -3
(c) +3
(d) +5

(c) +3

(a) NaOH + HCl → NaCl + H2O
(b) BaCl2 + H2SO4 → BaSO4 + 2HCl
(c) CuSO4 + 2H2O → Cu(OH)2 + H2SO3
(d) Zn + 2HCl → ZnCl2 + H2

(d) Zn + 2HCl → ZnCl2 + H2

3Br2 + 6CO32- + 3H2O → 5Br– + BrO3– + 6HCO3–


(a) bromine is oxidised and carbonate is reduced
(b) bromine is reduced and water is oxidised
(c) bromine is neither reduced nor oxidised
(d) bromine is both reduced and oxidised

(d) bromine is both reduced and oxidised

(a) I2 will be reduced to I–
(b) there will be no redox reaction
(c) I– will be oxidised to I2
(d) Fe2+ will be oxidised to Fe3+

(c) I– will be oxidised to I2

(a) CrO42- -→ Cr2O72-
(b) Cr → CrCl3
(c) Na → Na+
(d) 2S2O32- → S4O62-

(a) CrO42- -→ Cr2O72-

(a) +1
(b) +2
(c) +3
(d) +4

(b) +2

(a) I–
(b) Si(s)
(c) NO3–(aq)
(d) Cr2O72-

(a) I–

SO2 + 2H2S → 3S + 2H2O


(a) 32
(b) 64
(c) 16
(d) 8

(c) 16

(a) -4
(b) 0
(c) +4
(d) +6

(d) +6