Freezing Point of the Solvent MCQs

The normal freezing point of a pure liquid is the temperature at which the vapor pressure of the solid phase equals the vapor pressure of the liquid phase under atmospheric pressure. At this freezing point, the solid and liquid phases of the solvent are in equilibrium. When a solution freezes, it is not the solution itself that solidifies, but rather the pure solvent that separates out from the solution. Therefore, the freezing point of a solution is the temperature at which the vapor pressure of the solid solvent and the vapor pressure of the liquid solution are equal. Since the vapor pressure of a solution is lower than that of the pure liquid solvent, equilibrium can only be achieved when the vapor pressure of the solid solvent is lower.

(a) N2
(b) He
(c) H2
(d) CO2

(d) CO2

(a) 9g
(b) 6g
(c) 3g
(d) 0.3g

(c) 3g

(a) C2H4O2
(b) C3H6O3
(c) C5H10O5
(d) C4H8O4

(d) C4H8O4

(a) 250
(b) 300
(c) 400
(d) 1000

(c) 400

(a) Al2(SO4)3
(b) C6H12O6
(c) KCl
(d) C12H22O11

(a) Al2(SO4)3

(a) 2 liters of the solution contain 0.020 mole of SO4²⁻
(b) 2 liters of the solution contain 0.080 mole of H3O⁺
(c) 1 liter of the solution contains 0.020 mole of H3O⁺
(d) None of these

(b) 2 liters of the solution contain 0.080 mole of H3O⁺

(a) 0.02
(b) 1.2
(c) 1.11
(d) 0.08

(c) 1.11

(a) 0.93°C
(b) -0.93°C
(c) 1.86°C
(d) -1.86°C

(b) -0.93°C

(a) 75
(b) 60
(c) 80
(d) 70

(b) 60

(a) 0.01M
(b) 0.10M
(c) 0.001M
(d) 0.0001M

(b) 0.10M