Electromagnetism MCQs
What is Electromagnetism?
Electromagnetism is a fundamental chapter in Physics that explores the interaction between electric and magnetic fields and the principles underlying electromagnetic forces. This chapter introduces students to the concept of electromagnetism, including how electric currents generate magnetic fields and how changing magnetic fields induce electric currents. The unit covers key topics such as Ampère’s Law, Faraday’s Law of Induction, and Maxwell’s Equations, which form the basis of classical electromagnetism. Students also learn about practical applications, including electromagnetic waves and their use in communication technologies.
Key Topics in Electromagnetism:
- Magnetic Fields: Understanding the nature and sources of magnetic fields, including magnetic forces on moving charges and current-carrying conductors.
- Ampère’s Law: Exploring the relationship between electric currents and the magnetic fields they produce.
- Faraday’s Law of Induction: Analyzing how changing magnetic fields induce electromotive force (EMF) and electric currents in conductors.
- Electromagnetic Waves: Studying the propagation of electromagnetic waves and their properties, such as wavelength, frequency, and speed.
- Maxwell’s Equations: Learning the set of four fundamental equations that describe how electric and magnetic fields interact and propagate.
- Applications of Electromagnetism: Exploring real-world applications, including electric motors, transformers, generators, and wireless communication technologies.
Benefits of Studying Electromagnetism:
- Foundational Knowledge: Provides a deep understanding of the interaction between electric and magnetic fields, essential for studying advanced topics in Physics and engineering.
- Technological Insights: Equips students with knowledge applicable to a wide range of technologies, including electronics, telecommunications, and power generation.
- Career Preparation: Prepares students for careers in electrical engineering, physics research, and other fields that rely on electromagnetic principles.
This chapter is crucial for students to develop a comprehensive understanding of electromagnetism, which is fundamental to many modern technologies and scientific advancements. Whether preparing for exams or pursuing a career in science and engineering, mastering Electromagnetism is key to achieving success.
- The force experienced by a current-carrying conductor in a magnetic field is called:
- a) Electrostatic force
- b) Magnetic force
- c) Gravitational force
- d) Frictional force
Answer: b) Magnetic force
- The unit of magnetic flux is:
- a) Tesla
- b) Weber
- c) Ampere
- d) Volt
Answer: b) Weber
- The direction of the magnetic field around a current-carrying wire is given by:
- a) Coulomb’s Law
- b) Ohm’s Law
- c) Faraday’s Law
- d) Right-Hand Rule
Answer: d) Right-Hand Rule
- The magnetic field at the center of a circular loop of radius rrr carrying a current III is:
- a) μ0I2πr\frac{\mu_0 I}{2\pi r}2πrμ0I
- b) μ0I4πr\frac{\mu_0 I}{4\pi r}4πrμ0I
- c) μ0I2r\frac{\mu_0 I}{2r}2rμ0I
- d) μ0I4r\frac{\mu_0 I}{4r}4rμ0I
Answer: a) μ0I2r\frac{\mu_0 I}{2r}2rμ0I
- The force between two parallel currents-carrying conductors is:
- a) Directly proportional to the product of the currents
- b) Inversely proportional to the distance between them
- c) Independent of the distance between them
- d) Both a and b
Answer: d) Both a and b
- The SI unit of magnetic field strength is:
- a) Tesla
- b) Weber
- c) Henry
- d) Ampere
Answer: a) Tesla
- A magnetic field is created by:
- a) A stationary electric charge
- b) A moving electric charge
- c) A permanent magnet only
- d) A stationary magnet
Answer: b) A moving electric charge
- The magnetic field lines around a bar magnet are:
- a) Straight and parallel
- b) Circular around the north pole
- c) Circular around the south pole
- d) Closed loops running from the north to the south pole
Answer: d) Closed loops running from the north to the south pole
- The phenomenon of electromagnetic induction was discovered by:
- a) Michael Faraday
- b) James Clerk Maxwell
- c) André-Marie Ampère
- d) Heinrich Hertz
Answer: a) Michael Faraday
- The induced EMF in a coil is proportional to:
- a) The rate of change of current
- b) The rate of change of magnetic flux
- c) The rate of change of temperature
- d) The rate of change of resistance
Answer: b) The rate of change of magnetic flux
- Lenz’s Law states that the direction of the induced current is such that:
- a) It opposes the change in magnetic flux
- b) It enhances the change in magnetic flux
- c) It has no effect on the change in magnetic flux
- d) It is equal to the change in magnetic flux
Answer: a) It opposes the change in magnetic flux
- The unit of magnetic flux is:
- a) Weber
- b) Tesla
- c) Henry
- d) Ampere
Answer: a) Weber
- A solenoid is:
- a) A coil of wire wound into a cylindrical shape
- b) A type of magnet
- c) A type of electric current
- d) A type of capacitor
Answer: a) A coil of wire wound into a cylindrical shape
- The magnetic field inside a solenoid is:
- a) Zero
- b) Uniform and parallel to the axis
- c) Circular and perpendicular to the axis
- d) Non-uniform and radial
Answer: b) Uniform and parallel to the axis
- The magnetic force on a charged particle moving in a magnetic field is maximized when:
- a) The particle is stationary
- b) The particle is moving parallel to the field
- c) The particle is moving perpendicular to the field
- d) The field is zero
Answer: c) The particle is moving perpendicular to the field
- The direction of the force on a current-carrying conductor in a magnetic field can be determined using:
- a) Fleming’s Left-Hand Rule
- b) Fleming’s Right-Hand Rule
- c) Lenz’s Law
- d) Faraday’s Law
Answer: a) Fleming’s Left-Hand Rule
- The magnetic field at a distance rrr from a long straight conductor carrying a current III is:
- a) μ0I2πr\frac{\mu_0 I}{2\pi r}2πrμ0I
- b) μ0I4πr\frac{\mu_0 I}{4\pi r}4πrμ0I
- c) μ0Ir\frac{\mu_0 I}{r}rμ0I
- d) μ0Ir2\frac{\mu_0 I}{r^2}r2μ0I
Answer: a) μ0I2πr\frac{\mu_0 I}{2\pi r}2πrμ0I
- The magnetic flux through a surface is given by:
- a) B×A×cosθB \times A \times \cos \thetaB×A×cosθ
- b) B×A×sinθB \times A \times \sin \thetaB×A×sinθ
- c) B×A×tanθB \times A \times \tan \thetaB×A×tanθ
- d) B×A×cotθB \times A \times \cot \thetaB×A×cotθ
Answer: a) B×A×cosθB \times A \times \cos \thetaB×A×cosθ
- A moving coil galvanometer can be converted into a voltmeter by:
- a) Connecting a low resistance in series
- b) Connecting a high resistance in series
- c) Connecting a high resistance in parallel
- d) Connecting a low resistance in parallel
Answer: b) Connecting a high resistance in series
- The force on a charged particle moving in a magnetic field is:
- a) F=qvBsinθF = qvB \sin \thetaF=qvBsinθ
- b) F=qvBcosθF = qvB \cos \thetaF=qvBcosθ
- c) F=qvBF = qvBF=qvB
- d) F=qvBsinθF = \frac{qvB}{\sin \theta}F=sinθqvB
Answer: a) F=qvBsinθF = qvB \sin \thetaF=qvBsinθ
- The magnetic field produced by a current-carrying solenoid is:
- a) Zero
- b) Uniform inside and outside the solenoid
- c) Uniform inside and non-uniform outside
- d) Non-uniform inside and uniform outside
Answer: c) Uniform inside and non-uniform outside
- The magnetic field at the center of a circular loop of radius rrr carrying a current III is:
- a) μ0I2r\frac{\mu_0 I}{2r}2rμ0I
- b) μ0I4r\frac{\mu_0 I}{4r}4rμ0I
- c) μ0Iπr\frac{\mu_0 I}{\pi r}πrμ0I
- d) μ0I2πr\frac{\mu_0 I}{2\pi r}2πrμ0I
Answer: d) μ0I2πr\frac{\mu_0 I}{2\pi r}2πrμ0I
- The force between two parallel wires carrying currents I1I_1I1 and I2I_2I2 separated by a distance ddd is given by:
- a) μ0I1I22πd\frac{\mu_0 I_1 I_2}{2\pi d}2πdμ0I1I2
- b) μ0I1I2d\frac{\mu_0 I_1 I_2}{d}dμ0I1I2
- c) μ0I1I24πd\frac{\mu_0 I_1 I_2}{4\pi d}4πdμ0I1I2
- d) μ0I1I2d2π\frac{\mu_0 I_1 I_2 d}{2\pi}2πμ0I1I2d
Answer: a) μ0I1I22πd\frac{\mu_0 I_1 I_2}{2\pi d}2πdμ0I1I2
- The unit of magnetic field strength is:
- a) Tesla
- b) Weber
- c) Coulomb
- d) Ampere
Answer: a) Tesla
- The formula for the magnetic field at the center of a solenoid is:
- a) B=μ0nIB = \mu_0 n IB=μ0nI
- b) B=μ0InB = \frac{\mu_0 I}{n}B=nμ0I
- c) B=μ0nIB = \frac{\mu_0 n}{I}B=Iμ0n
- d) B=μ0nI2B = \frac{\mu_0 n I}{2}B=2μ0nI
Answer: a) B=μ0nIB = \mu_0 n IB=μ0nI
- The magnetic flux through a surface is given by:
- a) B×A×sinθB \times A \times \sin \thetaB×A×sinθ
- b) B×A×cosθB \times A \times \cos \thetaB×A×cosθ
- c) B×AB \times AB×A
- d) B×Acosθ\frac{B \times A}{\cos \theta}cosθB×A
Answer: b) B×A×cosθB \times A \times \cos \thetaB×A×cosθ
- In a moving coil galvanometer, the deflection is:
- a) Directly proportional to the current
- b) Inversely proportional to the current
- c) Directly proportional to the voltage
- d) Inversely proportional to the voltage
Answer: a) Directly proportional to the current
- The principle of operation of a transformer is based on:
- a) Faraday’s Law of Electromagnetic Induction
- b) Ampère’s Law
- c) Gauss’s Law
- d) Coulomb’s Law
Answer: a) Faraday’s Law of Electromagnetic Induction
- The magnetic field at a point due to a long straight wire carrying current decreases:
- a) With the square of the distance from the wire
- b) With the distance from the wire
- c) With the cube of the distance from the wire
- d) Inversely with the square of the distance from the wire
Answer: b) With the distance from the wire
- The direction of induced EMF in a coil is given by:
- a) Lenz’s Law
- b) Fleming’s Left-Hand Rule
- c) Right-Hand Rule
- d) Faraday’s Law
Answer: a) Lenz’s Law
- The force between two parallel current-carrying conductors is:
- a) Directly proportional to the product of the currents
- b) Inversely proportional to the product of the currents
- c) Directly proportional to the distance between them
- d) Inversely proportional to the distance between them
Answer: d) Inversely proportional to the distance between them
- The SI unit of electric current is:
- a) Ampere
- b) Volt
- c) Ohm
- d) Tesla
Answer: a) Ampere
- The magnetic field lines of a bar magnet are:
- a) Always closed loops
- b) Always straight lines
- c) Radial lines
- d) Circular lines
Answer: a) Always closed loops
- A galvanometer can be used as an ammeter by:
- a) Connecting a low resistance in series
- b) Connecting a high resistance in series
- c) Connecting a low resistance in parallel
- d) Connecting a high resistance in parallel
Answer: a) Connecting a low resistance in series
- The magnetic field strength is maximum inside:
- a) A bar magnet
- b) A solenoid
- c) A toroid
- d) A current-carrying wire
Answer: b) A solenoid
- The flux linkage is:
- a) The product of magnetic flux and number of turns in a coil
- b) The product of magnetic field and area
- c) The ratio of flux to area
- d) The rate of change of magnetic flux
Answer: a) The product of magnetic flux and number of turns in a coil
- The force on a current-carrying conductor placed in a magnetic field is given by:
- a) F=BILsinθF = BIL \sin \thetaF=BILsinθ
- b) F=BILcosθF = BIL \cos \thetaF=BILcosθ
- c) F=B×IF = B \times IF=B×I
- d) F=BILF = BILF=BIL
Answer: a) F=BILsinθF = BIL \sin \thetaF=BILsinθ
- The magnetic field inside a current-carrying solenoid is:
- a) Non-uniform
- b) Uniform
- c) Zero
- d) Radial
Answer: b) Uniform
- A transformer works on the principle of:
- a) Electromagnetic Induction
- b) Electrostatic Induction
- c) Thermoelectric Induction
- d) Magnetic Induction
Answer: a) Electromagnetic Induction
- The magnetic flux through a surface is zero when:
- a) The surface is perpendicular to the magnetic field
- b) The surface is parallel to the magnetic field
- c) The magnetic field is zero
- d) The surface area is zero
Answer: b) The surface is parallel to the magnetic field
- The magnetic field produced by a current-carrying solenoid is:
- a) Zero inside the solenoid
- b) Uniform inside the solenoid
- c) Non-uniform inside the solenoid
- d) Uniform outside the solenoid
Answer: b) Uniform inside the solenoid
- The induced EMF in a coil is directly proportional to:
- a) The rate of change of magnetic field
- b) The area of the coil
- c) The number of turns in the coil
- d) The resistance of the coil
Answer: a) The rate of change of magnetic field
- The magnetic field lines inside a current-carrying solenoid are:
- a) Closed loops running from south to north
- b) Circular around the wire
- c) Radial lines
- d) Uniform and parallel to the axis
Answer: d) Uniform and parallel to the axis
- In a moving coil galvanometer, the magnetic field is:
- a) Radial
- b) Uniform
- c) Varying
- d) Zero
Answer: b) Uniform
- The magnetic field due to a long straight current-carrying wire decreases with:
- a) Distance from the wire
- b) Time
- c) Current
- d) Temperature
Answer: a) Distance from the wire
- The magnetic force on a current-carrying conductor is greatest when:
- a) The conductor is parallel to the magnetic field
- b) The conductor is perpendicular to the magnetic field
- c) The conductor is at an angle of 45 degrees to the magnetic field
- d) The magnetic field is zero
Answer: b) The conductor is perpendicular to the magnetic field
- In an electric motor, the coil rotates due to:
- a) The torque produced by the interaction of the magnetic field and the current
- b) The force of gravity
- c) The electric field
- d) The thermal expansion
Answer: a) The torque produced by the interaction of the magnetic field and the current
- The magnetic field inside a toroid is:
- a) Non-uniform
- b) Zero
- c) Uniform and parallel to the axis
- d) Uniform and circular
Answer: d) Uniform and circular
- The phenomenon of electromagnetic induction is used in:
- a) Generators
- b) Motors
- c) Transformers
- d) All of the above
Answer: d) All of the above
- The electromotive force (EMF) induced in a coil is given by:
- a) E=−dΦdtE = -\frac{d\Phi}{dt}E=−dtdΦ
- b) E=dΦdtE = \frac{d\Phi}{dt}E=dtdΦ
- c) E=B×vE = B \times vE=B×v
- d) E=B×AE = B \times AE=B×A
Answer: a) E=−dΦdtE = -\frac{d\Phi}{dt}E=−dtdΦ
- The direction of magnetic field lines inside a magnet is from:
- a) South to North
- b) North to South
- c) East to West
- d) West to East
Answer: b) North to South
- The magnetic field produced by a solenoid can be strengthened by:
- a) Increasing the number of turns in the coil
- b) Decreasing the current
- c) Increasing the length of the solenoid
- d) Reducing the cross-sectional area
Answer: a) Increasing the number of turns in the coil
- The magnetic force between two current-carrying conductors is:
- a) Attractive if currents are in opposite directions
- b) Repulsive if currents are in the same direction
- c) Attractive if currents are in the same direction
- d) Zero if currents are equal
Answer: c) Attractive if currents are in the same direction
- The unit of magnetic flux is:
- a) Weber
- b) Tesla
- c) Ampere
- d) Ohm
Answer: a) Weber
- The magnetic field due to a current-carrying solenoid is:
- a) Radial
- b) Uniform inside and non-uniform outside
- c) Non-uniform inside and uniform outside
- d) Uniform everywhere
Answer: b) Uniform inside and non-uniform outside
- The strength of the magnetic field inside a solenoid can be increased by:
- a) Increasing the current
- b) Decreasing the number of turns
- c) Increasing the length of the solenoid
- d) Using a thinner wire
Answer: a) Increasing the current
- The principle behind a moving coil meter is:
- a) Electromagnetic Induction
- b) Electromagnetic Force
- c) Electromagnetic Radiation
- d) Electromagnetic Wave
Answer: b) Electromagnetic Force
- The direction of the induced EMF in a coil is such that:
- a) It opposes the change in magnetic flux
- b) It enhances the change in magnetic flux
- c) It is perpendicular to the magnetic field
- d) It is directly proportional to the magnetic flux
Answer: a) It opposes the change in magnetic flux
- The magnetic field lines inside a current-carrying solenoid are:
- a) Non-uniform and circular
- b) Uniform and parallel to the axis
- c) Circular around the wire
- d) Radial
Answer: b) Uniform and parallel to the axis
- The magnetic field at the center of a circular loop is:
- a) Zero
- b) Directly proportional to the radius of the loop
- c) Inversely proportional to the radius of the loop
- d) Directly proportional to the current
Answer: d) Directly proportional to the current
- The SI unit of magnetic flux density is:
- a) Tesla
- b) Weber
- c) Coulomb
- d) Ampere
Answer: a) Tesla
- The phenomenon where a changing magnetic field induces an EMF is known as:
- a) Electromagnetic Induction
- b) Electrostatic Induction
- c) Electromagnetic Radiation
- d) Magnetic Resonance
Answer: a) Electromagnetic Induction
- The force on a current-carrying conductor in a magnetic field depends on:
- a) The strength of the magnetic field
- b) The length of the conductor
- c) The current through the conductor
- d) All of the above
Answer: d) All of the above
- The electromotive force (EMF) produced in a coil by electromagnetic induction is:
- a) Directly proportional to the rate of change of current
- b) Inversely proportional to the rate of change of magnetic flux
- c) Directly proportional to the rate of change of magnetic flux
- d) Inversely proportional to the number of turns in the coil
Answer: c) Directly proportional to the rate of change of magnetic flux
- The direction of the magnetic force on a moving charge is:
- a) Parallel to the velocity of the charge
- b) Perpendicular to the velocity of the charge
- c) Parallel to the magnetic field
- d) Opposite to the magnetic field
Answer: b) Perpendicular to the velocity of the charge
- The magnetic field inside a long solenoid is:
- a) Uniform and parallel to the axis
- b) Non-uniform and radial
- c) Circular and perpendicular to the axis
- d) Zero
Answer: a) Uniform and parallel to the axis
- The force on a current-carrying conductor in a magnetic field is given by:
- a) F=BILsinθF = BIL \sin \thetaF=BILsinθ
- b) F=BILcosθF = BIL \cos \thetaF=BILcosθ
- c) F=BILsinθF = \frac{BIL}{\sin \theta}F=sinθBIL
- d) F=BILF = BILF=BIL
Answer: a) F=BILsinθF = BIL \sin \thetaF=BILsinθ
- The magnetic field strength (B) inside a toroid is:
- a) Uniform and parallel to the axis
- b) Non-uniform
- c) Zero
- d) Uniform and circular
Answer: d) Uniform and circular
- The SI unit of magnetic field strength is:
- a) Tesla
- b) Weber
- c) Ampere
- d) Henry
Answer: a) Tesla
- The force experienced by a current-carrying conductor in a magnetic field is:
- a) Independent of the angle between the conductor and the magnetic field
- b) Maximum when the angle is 90 degrees
- c) Maximum when the angle is 0 degrees
- d) Minimum when the angle is 90 degrees
Answer: b) Maximum when the angle is 90 degrees
- The magnetic field around a current-carrying conductor is:
- a) Circular
- b) Radial
- c) Straight
- d) Elliptical
Answer: a) Circular
- A current-carrying solenoid behaves like:
- a) A bar magnet
- b) An electromagnet
- c) A permanent magnet
- d) A capacitor
Answer: b) An electromagnet
- The direction of the magnetic field lines around a straight current-carrying conductor is:
- a) Radial lines
- b) Circular lines
- c) Straight lines
- d) Parallel lines
Answer: b) Circular lines
- The force between two parallel current-carrying conductors is:
- a) Zero if currents are in opposite directions
- b) Attractive if currents are in opposite directions
- c) Repulsive if currents are in the same direction
- d) Zero if currents are in the same direction
Answer: b) Attractive if currents are in opposite directions
- The magnetic field produced by a current-carrying wire can be increased by:
- a) Increasing the current
- b) Decreasing the distance from the wire
- c) Increasing the length of the wire
- d) Increasing the radius of the wire
Answer: a) Increasing the current
- The magnetic flux through a surface is defined as:
- a) The product of magnetic field and area
- b) The product of magnetic field and the length
- c) The product of current and area
- d) The product of electric field and area
Answer: a) The product of magnetic field and area
- The force on a moving charge in a magnetic field is:
- a) Directly proportional to the speed of the charge
- b) Directly proportional to the magnitude of the charge
- c) Directly proportional to the strength of the magnetic field
- d) All of the above
Answer: d) All of the above
- The unit of magnetic flux density (B) is:
- a) Weber per square meter
- b) Tesla per square meter
- c) Newton per meter
- d) Joule per coulomb
Answer: a) Weber per square meter
- The magnetic field strength produced by a solenoid is:
- a) Directly proportional to the current
- b) Directly proportional to the number of turns
- c) Inversely proportional to the length of the solenoid
- d) All of the above
Answer: d) All of the above
- The magnetic field lines inside a current-carrying toroid are:
- a) Parallel to the axis
- b) Radial
- c) Circular
- d) Uniform and straight
Answer: c) Circular
- The magnetic force on a current-carrying conductor is:
- a) Maximum when the current is zero
- b) Minimum when the magnetic field is zero
- c) Independent of the current
- d) Directly proportional to the length of the conductor
Answer: d) Directly proportional to the length of the conductor
- The direction of the magnetic force on a current-carrying wire can be found using:
- a) Right-Hand Rule
- b) Left-Hand Rule
- c) Faraday’s Law
- d) Lenz’s Law
Answer: a) Right-Hand Rule
- The magnetic field inside a current-carrying coil is:
- a) Non-uniform
- b) Uniform and parallel to the axis
- c) Zero
- d) Radial
Answer: b) Uniform and parallel to the axis
- The phenomenon of inducing a current by a changing magnetic field is known as:
- a) Electromagnetic Induction
- b) Electromagnetic Radiation
- c) Electrostatic Induction
- d) Magnetic Resonance
Answer: a) Electromagnetic Induction
- The magnetic field strength (B) around a straight current-carrying wire is:
- a) Inversely proportional to the distance from the wire
- b) Directly proportional to the distance from the wire
- c) Zero inside the wire
- d) Uniform everywhere
Answer: a) Inversely proportional to the distance from the wire
- The magnetic flux (Φ) is given by:
- a) Φ=B×A×cosθ\Phi = B \times A \times \cos \thetaΦ=B×A×cosθ
- b) Φ=B×A×sinθ\Phi = B \times A \times \sin \thetaΦ=B×A×sinθ
- c) Φ=B×A\Phi = B \times AΦ=B×A
- d) Φ=B×cosθ\Phi = B \times \cos \thetaΦ=B×cosθ
Answer: a) Φ=B×A×cosθ\Phi = B \times A \times \cos \thetaΦ=B×A×cosθ
- The SI unit of magnetic flux is:
- a) Weber
- b) Tesla
- c) Henry
- d) Coulomb
Answer: a) Weber
- The magnetic field produced by a current-carrying wire is:
- a) Radial
- b) Circular
- c) Linear
- d) Elliptical
Answer: b) Circular
- The principle behind electromagnetic induction is:
- a) Faraday’s Law
- b) Lenz’s Law
- c) Ampère’s Law
- d) Gauss’s Law
Answer: a) Faraday’s Law
- The magnetic field at the center of a circular current-carrying loop is:
- a) Inversely proportional to the radius of the loop
- b) Directly proportional to the radius of the loop
- c) Zero
- d) Directly proportional to the current and inversely proportional to the radius
Answer: d) Directly proportional to the current and inversely proportional to the radius
- The magnetic field produced by a solenoid is:
- a) Zero inside and non-zero outside
- b) Uniform inside and non-uniform outside
- c) Non-uniform inside and uniform outside
- d) Non-uniform everywhere
Answer: b) Uniform inside and non-uniform outside
- The magnetic field strength inside a solenoid can be increased by:
- a) Increasing the number of turns per unit length
- b) Increasing the length of the solenoid
- c) Decreasing the current
- d) Using a non-ferromagnetic core
Answer: a) Increasing the number of turns per unit length
- The direction of magnetic field lines around a current-carrying wire is:
- a) Radial outward
- b) Radial inward
- c) Circular
- d) Parallel
Answer: c) Circular
- The magnetic field strength due to a current-carrying wire is:
- a) Directly proportional to the current
- b) Inversely proportional to the distance from the wire
- c) Directly proportional to the length of the wire
- d) Both a and b
Answer: d) Both a and b
- The magnetic field at the center of a solenoid is:
- a) Zero
- b) Uniform and parallel to the axis
- c) Non-uniform and radial
- d) Non-uniform and circular
Answer: b) Uniform and parallel to the axis
- The force between two parallel current-carrying conductors is:
- a) Directly proportional to the distance between them
- b) Inversely proportional to the distance between them
- c) Directly proportional to the current in each conductor
- d) Both b and c
Answer: d) Both b and c
- The magnetic field inside a current-carrying toroid is:
- a) Uniform and circular
- b) Non-uniform and radial
- c) Zero
- d) Uniform and parallel to the axis
Answer: a) Uniform and circular
- The force on a charged particle moving in a magnetic field is maximum when:
- a) The velocity of the particle is zero
- b) The angle between the velocity and the magnetic field is 90 degrees
- c) The magnetic field strength is zero
- d) The particle is stationary
Answer: b) The angle between the velocity and the magnetic field is 90 degrees
- The magnetic flux through a surface is:
- a) The product of the magnetic field and the distance from the surface
- b) The product of the magnetic field and the length of the surface
- c) The product of the magnetic field and the area of the surface
- d) The product of the electric field and the area of the surface
Answer: c) The product of the magnetic field and the area of the surface
- The magnetic field due to a current-carrying loop is: – a) Uniform at all points in space – b) Maximum at the center of the loop – c) Zero at the center of the loop – d) Directly proportional to the radius of the loop
Answer: b) Maximum at the center of the loop
