AP Biology Practice Test 7 – 60 Questions with Answers (College Board)
Work through all 60 AP Biology questions, checking each answer as you go to build confidence for your AP Biology exam.
Chemistry of Life
Q1. A pH meter reads 6.0 for one solution and 4.0 for another. How do their hydrogen ion concentrations compare?
- (A) The pH 4 solution has 100 times more H+ than the pH 6 solution
- (B) The pH 6 solution has 100 times more H+ than the pH 4 solution
- (C) The pH 4 solution has twice as much H+ as the pH 6 solution
- (D) Their H+ concentrations are equal because pH is linear
Show Answer
Answer: A – pH is a logarithmic scale, so a difference of 2 units means a 102-fold difference in H+ concentration.
Q2. A plant cell in a dry soil loses water from its leaves, yet water keeps arriving from the roots. Which property of water molecules best explains the continuous column of water in the xylem?
- (A) The nonpolar nature of water molecules
- (B) The low specific heat of water
- (C) Cohesion between water molecules through hydrogen bonding
- (D) The ability of water to dissolve cellulose
Show Answer
Answer: C – Hydrogen bonds between water molecules let them stick together, so evaporation from leaves pulls a continuous column upward.
Q3. A molecule has a hydroxyl group (-OH) attached to a carbon atom. What is the most likely effect of this group on the molecule’s behaviour in water?
- (A) It makes the molecule hydrophobic and insoluble
- (B) It makes the molecule polar and able to form hydrogen bonds with water
- (C) It makes the molecule acidic by releasing a proton
- (D) It prevents the molecule from reacting with other molecules
Show Answer
Answer: B – Hydroxyl groups are polar and hydrophilic, increasing solubility in water, as in alcohols and sugars.
Q4. Two monosaccharides join to form a disaccharide. A molecule of water is released in the process. What is the name of the bond formed between the two sugars?
- (A) A peptide bond
- (B) A hydrogen bond
- (C) A phosphodiester bond
- (D) A glycosidic bond
Show Answer
Answer: D – Dehydration synthesis between monosaccharides forms a glycosidic linkage, as in maltose and sucrose.
Q5. A sample of double-stranded DNA contains 22 percent cytosine. What percentage of its bases are thymine?
- (A) 22 percent
- (B) 56 percent
- (C) 44 percent
- (D) 28 percent
Show Answer
Answer: D – By Chargaff’s rules, guanine is also 22 percent, leaving 56 percent for adenine plus thymine, so thymine is 28 percent.
Q6. An egg white is heated and turns from clear liquid to white solid, and the change cannot be reversed by cooling. The protein’s amino acid sequence is unchanged. What has happened?
- (A) The protein has been denatured, losing its secondary and tertiary structure
- (B) The protein has been hydrolysed into amino acids
- (C) New peptide bonds have formed between the proteins
- (D) The protein has been translated into a new sequence
Show Answer
Answer: A – Heat disrupts hydrogen bonds and other weak interactions, unfolding the protein without breaking its primary structure.
Q7. A phospholipid is placed in water. It spontaneously forms a bilayer with its tails hidden inside. Which property drives this arrangement?
- (A) The fatty acid tails are hydrophilic and attract water
- (B) The tails are hydrophobic, so they cluster away from water while the heads face it
- (C) The phosphate heads are hydrophobic and repel water
- (D) The phospholipids are held together by covalent bonds
Show Answer
Answer: B – Hydrophobic tails avoid water and hydrophilic heads interact with it, so a bilayer forms spontaneously.
Q8. Which level of protein structure is formed when an alpha helix in one region of a polypeptide interacts with a beta sheet in another region of the same chain?
- (A) Primary structure
- (B) Secondary structure
- (C) Tertiary structure
- (D) Quaternary structure
Show Answer
Answer: C – Tertiary structure is the overall three-dimensional folding of a single polypeptide, including interactions between its secondary structures.
Cell Structure and Function
Q9. A protein is made on the rough ER, modified in the Golgi apparatus, and then released from the cell in a vesicle. Which sequence of membrane structures does it pass through?
- (A) Nucleus, lysosome, plasma membrane
- (B) Rough ER, transport vesicle, Golgi, secretory vesicle, plasma membrane
- (C) Smooth ER, ribosome, vacuole, plasma membrane
- (D) Golgi, rough ER, mitochondrion, plasma membrane
Show Answer
Answer: B – The endomembrane system moves secretory proteins from the ER through the Golgi to the cell surface.
Q10. A child has Tay-Sachs disease, in which lipids accumulate inside cells because a lysosomal enzyme is missing. Which cellular function is directly impaired?
- (A) Protein synthesis on ribosomes
- (B) ATP production in mitochondria
- (C) Intracellular digestion of macromolecules in lysosomes
- (D) Photosynthesis in chloroplasts
Show Answer
Answer: C – Lysosomes contain hydrolytic enzymes that break down waste; without the enzyme, lipids build up inside them.
Q11. A cell is treated with a drug that depolymerises microtubules. Which process is most directly affected?
- (A) Diffusion of oxygen across the membrane
- (B) Glycolysis in the cytoplasm
- (C) Transcription in the nucleus
- (D) Movement of vesicles and separation of chromosomes during division
Show Answer
Answer: D – Microtubules form the spindle and vesicle tracks, so their loss disrupts chromosome movement and intracellular transport.
Q12. Plant cells are connected by plasmodesmata, and animal heart muscle cells are connected by gap junctions. What do these structures have in common?
- (A) They allow direct exchange of small molecules between neighbouring cells
- (B) They prevent all substances from leaving a cell
- (C) They anchor cells to the extracellular matrix
- (D) They generate ATP for neighbouring cells
Show Answer
Answer: A – Both are channels through cell walls or membranes that let ions and small molecules pass directly between cells.
Q13. At high temperatures, cholesterol in an animal cell membrane reduces its fluidity. At low temperatures, the same cholesterol increases fluidity. What is the best description of cholesterol’s role?
- (A) It makes the membrane rigid at all temperatures
- (B) It dissolves the phospholipid bilayer
- (C) It acts as a buffer of membrane fluidity, restraining phospholipid movement when hot and preventing close packing when cold
- (D) It transports cholesterol across the membrane by active transport
Show Answer
Answer: C – Cholesterol moderates fluidity in both directions, stabilising membranes across a temperature range.
Q14. A plant cell has a solute potential of -0.8 MPa and a pressure potential of +0.5 MPa. What is its water potential?
- (A) -1.3 MPa
- (B) +1.3 MPa
- (C) +0.3 MPa
- (D) -0.3 MPa
Show Answer
Answer: D – Water potential is the sum of solute and pressure potentials: -0.8 + 0.5 = -0.3 MPa.
Q15. A red blood cell is placed in distilled water. It swells and eventually bursts. Why does this happen?
- (A) Water enters by osmosis because the cell interior has a higher solute concentration than the surroundings
- (B) Salt enters the cell by active transport
- (C) The membrane pumps water in using ATP
- (D) The cell wall prevents water from leaving
Show Answer
Answer: A – In a hypotonic solution, water moves into the cell by osmosis until the membrane cannot withstand the pressure.
Q16. A researcher separates cell components by spinning a broken-cell mixture at increasing speeds. Nuclei pellet first, then mitochondria, then ribosomes. What is this technique called?
- (A) Gel electrophoresis
- (B) Cell fractionation by differential centrifugation
- (C) Chromatography
- (D) Fluorescence microscopy
Show Answer
Answer: B – Differential centrifugation pellets organelles in order of size and density, allowing each fraction to be studied separately.
Cellular Energetics
Q17. A reaction has a change in Gibbs free energy of -30 kJ/mol. What does the negative sign indicate?
- (A) The reaction is exergonic and can proceed spontaneously
- (B) The reaction is endergonic and requires a net input of energy
- (C) The reaction is at equilibrium
- (D) The reaction absorbs heat from the surroundings
Show Answer
Answer: A – A negative ΔG means the products have less free energy than the reactants, so the reaction releases energy and is spontaneous.
Q18. ATP hydrolysis releases energy that a cell uses to drive an endergonic reaction. Which term describes this pairing of reactions?
- (A) Denaturation
- (B) Energy coupling
- (C) Competitive inhibition
- (D) Photorespiration
Show Answer
Answer: B – Energy coupling uses the exergonic hydrolysis of ATP to power endergonic processes in the cell.
Q19. An enzyme’s activity is measured across a range of pH values. Activity is highest at pH 7 and falls sharply at pH 3 and pH 11. What best explains the fall at the extremes?
- (A) The substrate is used up faster at extreme pH
- (B) The enzyme is competitively inhibited by water
- (C) The enzyme’s active site is permanently enlarged
- (D) Extreme pH disrupts the bonds that maintain the enzyme’s shape, changing the active site
Show Answer
Answer: D – pH changes alter charges on amino acid side chains, breaking ionic and hydrogen bonds and denaturing the enzyme.
Q20. A noncompetitive inhibitor binds to an enzyme at a site other than the active site. What effect does it have on Vmax and Km?
- (A) Vmax increases and Km decreases
- (B) Vmax stays the same and Km increases
- (C) Vmax decreases and Km stays the same
- (D) Both Vmax and Km increase
Show Answer
Answer: C – A noncompetitive inhibitor reduces the number of functional enzyme molecules, lowering Vmax without changing substrate affinity.
Q21. In cyclic photophosphorylation, electrons from photosystem I return to the electron transport chain instead of reducing NADP+. What is the net product of this pathway?
- (A) Oxygen and NADPH
- (B) Glucose
- (C) Carbon dioxide
- (D) ATP only
Show Answer
Answer: D – Cyclic flow pumps protons to make ATP by chemiosmosis but produces no NADPH and no oxygen.
Q22. On a hot, dry afternoon a plant closes its stomata. Inside the leaf, oxygen accumulates and carbon dioxide falls. Rubisco begins to bind oxygen instead of carbon dioxide. What is this wasteful process called?
- (A) Chemiosmosis
- (B) Fermentation
- (C) Photorespiration
- (D) Oxidative phosphorylation
Show Answer
Answer: C – Photorespiration occurs when Rubisco oxygenates RuBP, releasing CO2 and consuming energy without producing sugar.
Q23. ATP synthase sits in the inner mitochondrial membrane. How does it make ATP?
- (A) Protons flowing down their gradient through ATP synthase drive the joining of ADP and phosphate
- (B) Electrons flow through ATP synthase and reduce oxygen
- (C) ATP synthase pumps protons into the matrix using ATP
- (D) ATP synthase splits water to release oxygen
Show Answer
Answer: A – Chemiosmosis uses the proton gradient: H+ moving through ATP synthase provides the energy to phosphorylate ADP.
Cell Communication and Cell Cycle
Q24. A hydrophilic signalling molecule such as insulin cannot cross the plasma membrane. Where is its receptor most likely to be located?
- (A) In the nucleus
- (B) On the outer surface of the plasma membrane
- (C) Inside the mitochondrion
- (D) In the cytoplasm, bound to DNA
Show Answer
Answer: B – Water-soluble ligands bind receptors on the cell surface, which then transmit the signal inside.
Q25. A receptor tyrosine kinase is activated when a growth factor binds. What happens next in the receptor itself?
- (A) The receptor is degraded in a lysosome immediately
- (B) Two receptor molecules pair up and phosphorylate each other on tyrosine residues
- (C) The receptor releases cAMP into the cytoplasm
- (D) The receptor moves into the nucleus and binds DNA directly
Show Answer
Answer: B – Ligand binding causes dimerisation and autophosphorylation, creating docking sites for relay proteins.
Q26. Bacteria in a dense culture release a signalling molecule; when its concentration passes a threshold, the whole population switches on genes for bioluminescence. What is this communication called?
- (A) Quorum sensing
- (B) Apoptosis
- (C) Synaptic signalling
- (D) Endocrine signalling
Show Answer
Answer: A – Quorum sensing lets bacteria coordinate gene expression according to population density.
Q27. A mutation inactivates the G1 checkpoint protein p53 in a human cell line. Which consequence is most likely?
- (A) The cell cannot enter mitosis at all
- (B) DNA replication is permanently blocked in S phase
- (C) Damaged DNA can be copied in S phase without repair
- (D) The cell skips cytokinesis and becomes multinucleate
Show Answer
Answer: C – The G1 checkpoint normally halts the cycle so DNA damage can be repaired before S phase; without it, damaged DNA is replicated.
Q28. In anaphase of mitosis, sister chromatids separate and move to opposite poles. What structure pulls them apart?
- (A) The nuclear envelope
- (B) The cell plate
- (C) The contractile ring
- (D) Microtubules of the spindle apparatus
Show Answer
Answer: D – Spindle microtubules attached to kinetochores shorten, pulling chromatids towards opposite poles.
Q29. A plant cell divides, and a new wall forms across the middle of the cell. What is this structure called, and what produces it?
- (A) A cleavage furrow produced by actin filaments
- (B) A septum produced by the rough ER
- (C) A cell plate produced by vesicles from the Golgi apparatus
- (D) A plasmodesma produced by the nucleus
Show Answer
Answer: C – In plant cytokinesis, Golgi vesicles fuse at the equator to form the cell plate, which becomes the new wall.
Q30. A proto-oncogene mutates into an oncogene. What is the most likely consequence for the cell?
- (A) The cell stops dividing permanently
- (B) The cell divides without normal control, as if a growth signal were always on
- (C) The cell undergoes apoptosis immediately
- (D) The cell loses its mitochondria
Show Answer
Answer: B – An activated oncogene behaves like a stuck accelerator, promoting uncontrolled cell division.
Heredity
Q31. A human cell has 46 chromosomes. How many different combinations of maternal and paternal chromosomes are possible in its gametes through independent assortment alone?
- (A) 23
- (B) 46
- (C) 46 x 2
- (D) 223
Show Answer
Answer: D – Each of the 23 chromosome pairs can orient either way at metaphase I, giving 223, or about 8.4 million, combinations.
Q32. A plant with purple flowers (P) is crossed with a white-flowered plant (pp). Half the offspring have purple flowers and half have white flowers. What is the genotype of the purple parent?
- (A) Pp
- (B) PP
- (C) pp
- (D) pP is impossible in diploids
Show Answer
Answer: A – A 1:1 ratio from a test cross shows the purple parent is heterozygous.
Q33. In snapdragons, crossing a red-flowered plant with a white-flowered plant produces all pink-flowered offspring. What pattern of inheritance is this?
- (A) Incomplete dominance
- (B) Complete dominance
- (C) Codominance
- (D) Sex linkage
Show Answer
Answer: A – In incomplete dominance the heterozygote shows an intermediate phenotype between the two homozygotes.
Q34. In mice, coat colour is controlled by two genes. Gene B gives black pigment, while a recessive mutation at gene C blocks all pigment production, so cc mice are albino regardless of their B genotype. What is this interaction called?
- (A) Polygenic inheritance
- (B) Codominance
- (C) Multiple alleles
- (D) Epistasis
Show Answer
Answer: D – Epistasis occurs when one gene masks the expression of another gene.
Q35. A pedigree shows a trait appearing in every generation, and every affected person has an affected parent. Which inheritance pattern is most likely?
- (A) Autosomal recessive
- (B) X-linked recessive
- (C) Autosomal dominant
- (D) Mitochondrial only
Show Answer
Answer: C – Dominant traits appear in every generation and are passed from an affected parent to about half the children.
Q36. A person has blood group AB. Which statement about their red blood cells is correct?
- (A) They carry neither A nor B antigens
- (B) They carry both A and B antigens, showing codominance
- (C) They carry only A antigens because A is dominant to B
- (D) They carry only B antigens because B is dominant to A
Show Answer
Answer: B – The IA and IB alleles are codominant, so both antigens are expressed.
Q37. A child is born with Down syndrome (trisomy 21). Which event most likely caused it?
- (A) A point mutation in chromosome 21
- (B) Crossing over between chromosomes 21 and 22
- (C) A deletion of part of chromosome 21
- (D) Nondisjunction of chromosome 21 during meiosis
Show Answer
Answer: D – Failure of chromosome 21 to separate gives a gamete with two copies, producing a zygote with three copies.
Gene Expression and Regulation
Q38. During DNA replication, one new strand is built continuously and the other is built in short fragments. What are those fragments called?
- (A) Primers
- (B) Okazaki fragments
- (C) Telomeres
- (D) Introns
Show Answer
Answer: B – The lagging strand is synthesised in Okazaki fragments, later joined by DNA ligase.
Q39. A newly made pre-mRNA in a human cell contains introns. What happens to these introns before translation?
- (A) They are removed by splicing, and the exons are joined together
- (B) They are translated into the first amino acids of the protein
- (C) They are copied into the DNA of the next generation
- (D) They are exported to the cytoplasm unchanged
Show Answer
Answer: A – RNA splicing removes non-coding introns, leaving the coding exons in the mature mRNA.
Q40. A ribosome is translating an mRNA. The tRNA carrying the growing polypeptide chain is in the P site, and a new tRNA has just arrived. In which site is the new tRNA?
- (A) The E site
- (B) The promoter site
- (C) The A site
- (D) The operator site
Show Answer
Answer: C – Incoming aminoacyl-tRNAs enter the A (aminoacyl) site, where the peptide bond is formed.
Q41. In a eukaryotic cell, a gene is switched on only when a specific activator protein binds to an enhancer far from the promoter. How does the enhancer influence the promoter?
- (A) The enhancer is transcribed into mRNA instead of the gene
- (B) The enhancer deletes the promoter sequence
- (C) DNA looping brings the bound activator into contact with the transcription machinery at the promoter
- (D) The enhancer blocks RNA polymerase from leaving the gene
Show Answer
Answer: C – Bending of the DNA allows distant enhancer-bound activators to interact with proteins at the promoter.
Q42. Methyl groups are added to the DNA of a gene’s promoter in a liver cell, and the gene is silenced for the rest of the cell’s life. What is this an example of?
- (A) Epigenetic regulation by DNA methylation
- (B) A frameshift mutation
- (C) Alternative splicing of the promoter
- (D) Competitive inhibition of RNA polymerase
Show Answer
Answer: A – DNA methylation can silence genes without changing the base sequence, and the pattern can be inherited by daughter cells.
Q43. A scientist wants to cut a DNA molecule at a specific sequence and leave short single-stranded overhangs. Which tool should she use?
- (A) DNA ligase
- (B) A restriction enzyme
- (C) Reverse transcriptase
- (D) RNA polymerase
Show Answer
Answer: B – Restriction enzymes cut at specific recognition sites, often producing sticky ends that can be joined to other fragments.
Q44. CRISPR-Cas9 is used to edit a gene in a cell. What guides the Cas9 enzyme to the correct DNA sequence?
- (A) A protein antibody
- (B) A primer made of DNA polymerase
- (C) A restriction enzyme
- (D) A guide RNA complementary to the target sequence
Show Answer
Answer: D – The guide RNA base-pairs with the target DNA, positioning Cas9 to cut at that site.
Natural Selection
Q45. In a population, the frequency of the recessive allele for a trait is 0.4. Assuming Hardy-Weinberg equilibrium, what is the frequency of the dominant allele?
- (A) 0.4
- (B) 0.6
- (C) 0.16
- (D) 0.36
Show Answer
Answer: B – Allele frequencies sum to 1, so p = 1 – q = 1 – 0.4 = 0.6.
Q46. Human birth weight shows a pattern in which very small and very large babies have lower survival rates than average-weight babies. Which type of selection is acting?
- (A) Directional selection
- (B) Disruptive selection
- (C) Sexual selection
- (D) Stabilising selection
Show Answer
Answer: D – Stabilising selection favours the intermediate phenotype and reduces variation in both directions.
Q47. A few individuals from a mainland bird population colonise a remote island. The island population has different allele frequencies from the mainland, purely by chance. What is this called?
- (A) Natural selection
- (B) Gene flow
- (C) The founder effect
- (D) Mutation
Show Answer
Answer: C – The founder effect is genetic drift caused by a small colonising group carrying only a sample of the original gene pool.
Q48. Male peacocks with larger, brighter tails attract more mates, even though the tails make them easier for predators to spot. What drives the evolution of these tails?
- (A) Sexual selection
- (B) Artificial selection
- (C) Genetic drift
- (D) Stabilising selection
Show Answer
Answer: A – Sexual selection favours traits that increase mating success, even when they reduce survival.
Q49. Two populations of fireflies live in the same meadow but flash their mating signals at different times of night, so they never interbreed. What type of reproductive isolation is this?
- (A) Hybrid inviability
- (B) Temporal isolation
- (C) Mechanical isolation
- (D) Gametic isolation
Show Answer
Answer: B – Temporal isolation occurs when species breed at different times, preventing mating.
Q50. A mule, the offspring of a horse and a donkey, is healthy but sterile. What type of reproductive barrier does this illustrate?
- (A) Habitat isolation
- (B) Behavioural isolation
- (C) Mechanical isolation
- (D) Hybrid sterility, a postzygotic barrier
Show Answer
Answer: D – Hybrid sterility is a postzygotic barrier: the hybrid forms but cannot produce viable gametes.
Q51. Sharks and dolphins both have streamlined bodies and fins, although sharks are fish and dolphins are mammals. What does this similarity illustrate?
- (A) Convergent evolution producing analogous structures
- (B) Homologous structures from a recent common ancestor
- (C) Divergent evolution from a shared marine ancestor
- (D) Artificial selection by humans
Show Answer
Answer: A – Similar environments select for similar body shapes in unrelated lineages, producing analogous structures.
Q52. The fossil record shows a sequence of horse fossils in which teeth change from low-crowned browsers to high-crowned grazers as grasslands spread. What does this series best demonstrate?
- (A) That fossils never change over time
- (B) That evolution occurs by sudden creation of new species
- (C) Gradual change in a lineage in response to a changing environment
- (D) That horses evolved from modern grasses
Show Answer
Answer: C – Transitional fossils document gradual adaptation of a lineage as its environment changes.
Ecology
Q53. A bacterial population doubles every 20 minutes under ideal conditions. Starting from 100 cells, approximately how many cells will there be after 2 hours?
- (A) 200
- (B) 1,200
- (C) 6,400
- (D) 3,200
Show Answer
Answer: C – Two hours is six doublings: 100 x 26 = 100 x 64 = 6,400 cells.
Q54. A population pyramid for a country is wide at the base and narrow at the top, with many children and few elderly people. What does this shape predict?
- (A) The population will grow rapidly as the large young cohorts reach reproductive age
- (B) The population will shrink immediately
- (C) The population is at carrying capacity
- (D) The birth rate is lower than the death rate
Show Answer
Answer: A – A wide base means many individuals are about to enter their reproductive years, driving future growth.
Q55. Which survivorship curve is typical of a species that produces many offspring, gives them little care, and has very high juvenile mortality, such as an oyster?
- (A) Type I, with most deaths in old age
- (B) Type II, with a constant death rate at all ages
- (C) A curve with no deaths at any age
- (D) Type III, with most deaths early in life
Show Answer
Answer: D – Type III species have high early mortality and low survival to adulthood, offset by very high fecundity.
Q56. In a food web, removing wolves from a valley leads to a deer population boom, overgrazing, and a decline in songbirds that nest in shrubs. What is this chain of effects called?
- (A) Primary succession
- (B) A trophic cascade
- (C) Competitive exclusion
- (D) Eutrophication
Show Answer
Answer: B – A trophic cascade occurs when changes at one trophic level ripple through the food web to affect others.
Q57. Fertilisers wash into a lake, causing an algal bloom. When the algae die, decomposers consume the oxygen in the water and fish die. What is this process called?
- (A) Biomagnification
- (B) Acid rain formation
- (C) Primary succession
- (D) Eutrophication
Show Answer
Answer: D – Nutrient enrichment drives algal growth; decomposition of the bloom then depletes dissolved oxygen.
Q58. A pesticide is applied to crops at low concentration, but top predators such as eagles accumulate much higher concentrations in their tissues. What is this phenomenon called?
- (A) Eutrophication
- (B) Biomagnification
- (C) Primary productivity
- (D) Denitrification
Show Answer
Answer: B – Biomagnification is the increase in concentration of a persistent toxin at successive trophic levels.
Q59. Which ecosystem has the highest net primary productivity per square metre?
- (A) Open ocean
- (B) Desert
- (C) Tropical rainforest
- (D) Tundra
Show Answer
Answer: C – Warm, wet tropical rainforests support year-round photosynthesis and the highest productivity per unit area.
Q60. An invasive plant species spreads rapidly in a new habitat, outcompeting native plants. Which factor most likely explains its success?
- (A) It has left behind its natural predators and pathogens
- (B) It cannot reproduce in the new habitat
- (C) It requires more nutrients than native plants
- (D) It is eaten by more herbivores than native plants
Show Answer
Answer: A – Escape from natural enemies, the enemy-release hypothesis, lets invaders grow unchecked in a new range.
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