A-Level Biology Practice Test 12 – 60 Questions with Answers (Cambridge 9700)
This test revisits every A-Level topic with fresh data and application questions, so treat each stem carefully before choosing an answer.
Cell structure
Q1. Which organelle is the site of most ATP synthesis in a eukaryotic cell, and why is it suited to this role?
- (A) The Golgi apparatus, because it has a large surface area of flattened sacs
- (B) The nucleus, because it contains the genes for respiration enzymes
- (C) The mitochondrion, because its folded inner membrane carries the electron transport chain and ATP synthase
- (D) The lysosome, because its enzymes release energy from food molecules
Show Answer
Answer: C – Cristae increase the area available for chemiosmosis, which is where most ATP is made in aerobic respiration.
Q2. A student compares a prokaryotic cell with a eukaryotic cell. Which feature is found in the prokaryotic cell but not in a typical eukaryotic cell?
- (A) A nucleus enclosed by a double membrane
- (B) Membrane-bound mitochondria
- (C) Circular DNA free in the cytoplasm, without a nucleus
- (D) A Golgi apparatus for modifying proteins
Show Answer
Answer: C – Prokaryotes lack a true nucleus and membrane-bound organelles, and their DNA is a single circular molecule.
Q3. Which function is carried out by the smooth endoplasmic reticulum?
- (A) Synthesis and transport of proteins for secretion
- (B) Production of ribosomal RNA
- (C) Lipid synthesis and detoxification of some substances
- (D) Digestion of worn-out organelles
Show Answer
Answer: C – The smooth endoplasmic reticulum lacks ribosomes and is associated with lipid and steroid synthesis.
Biological molecules
Q4. Which statement about the structure of starch is correct?
- (A) It is made of beta-glucose units joined by 1,4 and 1,6 glycosidic bonds
- (B) It is a polymer of fructose joined by peptide bonds
- (C) It is made of alpha-glucose units, with amylose unbranched and amylopectin branched
- (D) It is a single long chain of glucose with no branching at all
Show Answer
Answer: C – The alpha linkages give starch a helical, compact shape suited to storage, and branching in amylopectin allows rapid hydrolysis.
Q5. Why is cellulose strong despite being made only of glucose?
- (A) Cellulose chains are coiled into alpha-helices that resist stretching
- (B) Glucose units are joined by ester bonds into a triple helix
- (C) Beta-glucose units form straight chains linked by hydrogen bonds into microfibrils
- (D) Each glucose unit is bonded to a protein that stiffens the wall
Show Answer
Answer: C – Alternating beta-glucose units and many hydrogen bonds between parallel chains produce very strong fibres.
Q6. A protein has a quaternary structure. What does this mean?
- (A) It consists of a single polypeptide folded into an alpha-helix
- (B) It is made of four amino acids only
- (C) It consists of two or more polypeptide chains held together in a specific arrangement
- (D) Its sequence is determined by four different genes
Show Answer
Answer: C – Haemoglobin is a classic example, with four polypeptide chains working together as one functional molecule.
Enzymes
Q7. In an enzyme experiment, the substrate concentration is increased until the rate no longer rises. What limits the rate at this point?
- (A) The number of substrate molecules in solution
- (B) The temperature of the reaction mixture
- (C) The number of active sites available, because the enzyme is saturated
- (D) The concentration of the product, which acts as a substrate
Show Answer
Answer: C – At saturation, every active site is occupied for most of the time, so adding more substrate cannot increase the rate.
Q8. A non-competitive inhibitor is added to a reaction. Which statement is correct?
- (A) It binds to the active site and can be outcompeted by adding more substrate
- (B) It increases both Vmax and Km
- (C) It binds elsewhere on the enzyme, changes the active site shape, and lowers Vmax
- (D) It is broken down by the enzyme into a useful product
Show Answer
Answer: C – Because the inhibitor does not compete for the active site, extra substrate cannot restore the maximum rate.
Q9. Which graph feature shows that an enzyme has a high affinity for its substrate?
- (A) A high Vmax
- (B) A steep fall in rate as temperature rises
- (C) A low Km, meaning half-maximum rate is reached at a low substrate concentration
- (D) A high optimum pH
Show Answer
Answer: C – Km is the substrate concentration giving half Vmax, so a low Km indicates that the enzyme binds its substrate readily.
Cell membranes and transport
Q10. Which molecule crosses a cell surface membrane by simple diffusion most readily?
- (A) A large polar protein
- (B) A charged sodium ion
- (C) A small non-polar molecule such as oxygen
- (D) A glucose molecule
Show Answer
Answer: C – Small, non-polar molecules dissolve in the phospholipid bilayer, while ions and large polar molecules need channels, carriers or energy.
Q11. A red blood cell is placed in a solution with a lower water potential than the cell. What happens, and why?
- (A) The cell swells and bursts because water enters by osmosis
- (B) The cell takes up solutes by active transport until it bursts
- (C) The cell stays the same size because osmosis only occurs in plant cells
- (D) The cell shrinks and crenates because water leaves by osmosis
Show Answer
Answer: D – Water moves by osmosis from the higher water potential inside the cell to the lower water potential outside it.
Q12. In the ileum, glucose is absorbed against its concentration gradient by cotransport with sodium ions. What provides the energy for this indirectly?
- (A) ATP used by the sodium-potassium pump to maintain a sodium gradient
- (B) ATP used directly by glucose carrier proteins
- (C) Diffusion of glucose down its gradient in the blood
- (D) Hydrolysis of glucose in the gut lumen
Show Answer
Answer: A – The pump keeps sodium low inside the cell, so sodium entering with glucose moves down its gradient and carries glucose with it.
The mitotic cell cycle
Q13. Which statement about checkpoints in the cell cycle is correct?
- (A) Checkpoints prevent the cell from ever dividing more than once
- (B) Checkpoints double the chromosome number before every division
- (C) Checkpoints occur only after cytokinesis has finished
- (D) Checkpoints halt the cycle if DNA is damaged or chromosomes are not properly attached, allowing repair or preventing faulty division
Show Answer
Answer: D – Failure of checkpoint control can allow damaged cells to divide, which is a feature of cancer development.
Q14. A cell with 2n = 6 undergoes mitosis. How many chromosomes and chromatids are present in a daughter cell immediately after telophase?
- (A) 6 chromosomes, each with one chromatid
- (B) 3 chromosomes, each with two chromatids
- (C) 12 chromosomes, each with one chromatid
- (D) 6 chromosomes, each with two chromatids
Show Answer
Answer: A – Mitosis preserves the chromosome number, and sister chromatids have separated, so each chromosome now has a single chromatid.
Q15. Which stage of mitosis is characterised by chromosomes becoming visible as they condense and the nuclear envelope breaking down?
- (A) Metaphase
- (B) Telophase
- (C) Prophase
- (D) Anaphase
Show Answer
Answer: C – Condensation makes chromosomes visible under a microscope, and spindle formation begins during prophase.
Nucleic acids and protein synthesis
Q16. Which statement correctly compares DNA and RNA?
- (A) DNA contains uracil and ribose, while RNA contains thymine and deoxyribose
- (B) DNA is single-stranded and RNA is double-stranded in all cells
- (C) Both are double-stranded and contain thymine
- (D) DNA is usually double-stranded with deoxyribose and thymine, while RNA is usually single-stranded with ribose and uracil
Show Answer
Answer: D – The sugar and one base differ between the two nucleic acids, and their strand numbers usually differ too.
Q17. At a ribosome, what is the role of tRNA during translation?
- (A) It carries a specific amino acid to the ribosome and its anticodon pairs with an mRNA codon
- (B) It copies DNA into mRNA in the nucleus
- (C) It forms peptide bonds between ribosomal subunits
- (D) It removes introns from pre-mRNA
Show Answer
Answer: A – Each tRNA is charged with one amino acid, ensuring the polypeptide sequence matches the mRNA codons.
Q18. A point mutation changes a codon from UAU to UAA. What is the most likely effect on the protein?
- (A) No effect, because the code is degenerate
- (B) One amino acid is replaced by another with similar properties
- (C) Translation stops early, producing a shortened, usually non-functional protein
- (D) The whole reading frame shifts by one base
Show Answer
Answer: C – UAA is a stop codon, so this nonsense mutation terminates translation prematurely.
Transport in plants
Q19. Which factor would increase the rate of transpiration from a leaf?
- (A) High humidity and still air
- (B) Low temperature and darkness
- (C) Wind and low humidity, which maintain a steep water vapour gradient
- (D) Closing the stomata
Show Answer
Answer: C – Wind removes humid air from around the leaf, and dry air increases diffusion of water vapour out of the stomata.
Q20. What is the role of the Casparian strip in a root?
- (A) It pumps water into the xylem by active transport
- (B) It allows water to bypass the endodermis completely
- (C) It stores starch in the cortex for later use
- (D) It blocks the apoplast pathway in the endodermis, forcing water and ions through cell membranes into the symplast
Show Answer
Answer: D – The waterproof strip ensures selective uptake, since substances must cross a membrane to reach the vascular tissue.
Q21. Which statement about phloem sieve tubes is correct?
- (A) Sieve tube elements are dead cells with thick lignified walls
- (B) Sieve tubes are found only in the roots of flowering plants
- (C) Sieve tubes transport water and mineral ions from roots to leaves
- (D) Sieve tube elements are living cells with little cytoplasm and no nucleus, supported by companion cells
Show Answer
Answer: D – Companion cells carry out metabolism for the sieve elements, including loading of assimilates.
Transport in mammals
Q22. Why is the wall of the left ventricle thicker than that of the right ventricle?
- (A) The left ventricle pumps blood to the lungs at low pressure
- (B) The left ventricle has four valves instead of two
- (C) The right ventricle receives blood from the vena cava and needs more muscle
- (D) The left ventricle must generate enough pressure to pump blood around the whole body
Show Answer
Answer: D – The systemic circulation is much longer and offers more resistance than the pulmonary circulation.
Q23. Fetal haemoglobin has a higher affinity for oxygen than adult haemoglobin. What is the advantage?
- (A) It releases oxygen more easily in the fetal tissues
- (B) It prevents the Bohr shift from occurring in the fetus
- (C) It carries carbon dioxide more efficiently to the mother
- (D) It takes up oxygen from the maternal blood across the placenta, even at low oxygen partial pressures
Show Answer
Answer: D – The fetal dissociation curve lies to the left of the maternal curve, so oxygen moves from mother to fetus.
Q24. At the venule end of a capillary, most tissue fluid returns to the blood. Why?
- (A) Hydrostatic pressure is now low, so the solute potential gradient draws fluid back in
- (B) Lymph vessels pump fluid back into the capillary
- (C) Active transport moves water back into the blood
- (D) The capillary wall becomes impermeable to water at this end
Show Answer
Answer: A – As pressure falls along the capillary, the inward osmotic pull of plasma proteins dominates, and remaining fluid drains into lymph vessels.
Gas exchange
Q25. During inspiration in a mammal, what happens to the diaphragm and the external intercostal muscles?
- (A) The diaphragm relaxes and rises, and the external intercostal muscles relax
- (B) Both sets of muscles relax, allowing air to flow in passively
- (C) The diaphragm contracts and the internal intercostal muscles contract
- (D) The diaphragm contracts and flattens, and the external intercostal muscles contract, raising the ribs
Show Answer
Answer: D – These movements increase thoracic volume, lower air pressure in the lungs, and draw air in.
Q26. Which feature of the mammalian gas exchange surface maintains a steep diffusion gradient?
- (A) The thick layer of mucus lining the alveoli
- (B) The large volume of air left in the lungs after exhalation
- (C) The cartilage rings in the trachea
- (D) The rich capillary network that constantly removes oxygenated blood and brings deoxygenated blood
Show Answer
Answer: D – Continuous blood flow prevents oxygen building up at the surface and keeps the gradient steep.
Q27. A fish is in water with a low oxygen concentration. Which response would help maintain oxygen uptake?
- (A) Reducing ventilation rate to save energy
- (B) Switching to anaerobic respiration in the gills
- (C) Closing the operculum permanently
- (D) Increasing ventilation rate so more water flows over the gills
Show Answer
Answer: D – Faster water flow renews the oxygen supply at the lamellae, partly compensating for the lower concentration.
Infectious diseases
Q28. Which statement about the transmission of malaria is correct?
- (A) It is spread directly from person to person by coughing
- (B) It is spread by eating undercooked meat
- (C) It is spread through contaminated drinking water
- (D) It is spread by the bite of an infected female Anopheles mosquito carrying Plasmodium in its salivary glands
Show Answer
Answer: D – The mosquito acts as a vector, and only female mosquitoes take blood meals.
Q29. Why can antibiotics not be used to treat HIV infection?
- (A) HIV is a virus, and antibiotics target bacterial structures and processes that viruses lack
- (B) HIV is protected by a thick bacterial cell wall
- (C) Antibiotics destroy helper T cells before they can act
- (D) HIV mutates into a bacterium inside the host
Show Answer
Answer: A – Antiviral drugs are needed instead, targeting stages such as reverse transcription or viral protease activity.
Q30. Which measure is most effective for controlling the spread of cholera in an outbreak?
- (A) Vaccinating against the cholera virus
- (B) Quarantining all healthy people in the area
- (C) Spraying insecticide to kill mosquito vectors
- (D) Providing clean drinking water and safe sewage disposal to break faecal-oral transmission
Show Answer
Answer: D – Cholera is a bacterial disease spread through contaminated water, so sanitation addresses the route of transmission.
Immunity
Q31. A patient with HIV has a falling helper T cell count and develops infections that healthy people usually resist. Why does loss of helper T cells have such a wide effect?
- (A) They produce antibodies directly against free antigens
- (B) They form a physical barrier in the skin
- (C) They engulf pathogens and digest them in lysosomes
- (D) They release cytokines that stimulate B cells and killer T cells, so their loss weakens both arms of the response
Show Answer
Answer: D – Helper T cells coordinate the immune response, which is why their loss in HIV infection weakens immunity so severely.
Q32. A laboratory test uses an antibody that binds only the beta subunit of human chorionic gonadotrophin. Why is a monoclonal antibody preferred for this test?
- (A) It is a mixture of antibodies from many clones, giving a broader signal
- (B) It can be produced by phagocytes without any B cells
- (C) It binds every protein in the sample, increasing sensitivity
- (D) Identical antibodies from a single clone bind one epitope, reducing cross-reaction with similar hormones
Show Answer
Answer: D – Single specificity is what makes monoclonal antibodies reliable for distinguishing closely related molecules in diagnostic tests.
Q33. In active immunity, how does the body gain protection?
- (A) Antibodies are injected directly and give immediate, short-lived protection
- (B) Phagocytes are transferred from a donor
- (C) Antibodies pass from mother to baby in breast milk
- (D) The immune system responds to an antigen, produces its own antibodies and memory cells, giving longer-lasting protection
Show Answer
Answer: D – Vaccination works by triggering active immunity without causing the full disease.
Energy and respiration
Q34. Where do glycolysis, the Krebs cycle and oxidative phosphorylation occur in a eukaryotic cell?
- (A) Glycolysis in the cytoplasm, Krebs cycle in the mitochondrial matrix, oxidative phosphorylation on the inner mitochondrial membrane
- (B) All three in the cytoplasm
- (C) Glycolysis in the matrix, Krebs cycle on the cristae, oxidative phosphorylation in the cytoplasm
- (D) Glycolysis on the inner membrane, Krebs cycle in the cytoplasm, oxidative phosphorylation in the matrix
Show Answer
Answer: A – The locations reflect the sequence of reactions, from glucose breakdown in the cytoplasm to ATP synthesis on the cristae.
Q35. Which statement about the Krebs cycle is correct?
- (A) Acetyl coenzyme A combines with oxaloacetate, and carbon dioxide is released as intermediates are oxidised
- (B) Glucose is split into two molecules of pyruvate
- (C) Oxygen is reduced to water directly in the cycle
- (D) The cycle produces glucose from carbon dioxide
Show Answer
Answer: A – The cycle regenerates oxaloacetate and produces reduced NAD and FAD for oxidative phosphorylation.
Q36. If oxygen is absent, why does the yield of ATP from glucose fall sharply?
- (A) Glycolysis stops completely without oxygen
- (B) Reduced NAD and FAD cannot be reoxidised by the electron transport chain, so the Krebs cycle and oxidative phosphorylation cannot run
- (C) The mitochondria produce ATP directly from oxygen
- (D) Glucose cannot enter the cell without oxygen
Show Answer
Answer: B – Only substrate-level phosphorylation in glycolysis continues, giving a net yield of 2 ATP per glucose.
Photosynthesis
Q37. Which pigments are involved in photosynthesis, and where are they located?
- (A) Chlorophyll and carotenoids in the thylakoid membranes of chloroplasts
- (B) Haemoglobin and melanin in the stroma
- (C) Chlorophyll only, dissolved in the cell sap
- (D) Carotenoids only, in the mitochondrial matrix
Show Answer
Answer: A – The pigments are arranged in photosystems in the thylakoid membranes, where light energy is captured.
Q38. In cyclic photophosphorylation, what is produced, and what is not produced?
- (A) ATP is produced, but no reduced NADP and no oxygen
- (B) Reduced NADP is produced, but no ATP
- (C) Oxygen and ATP are produced, but no reduced NADP
- (D) Glucose is produced directly
Show Answer
Answer: A – Electrons cycle back to photosystem I, so only ATP is made, which can top up ATP supply for the Calvin cycle.
Q39. A leaf is kept in the dark and then illuminated. Which change occurs in the concentrations of glycerate 3-phosphate and triose phosphate?
- (A) Glycerate 3-phosphate falls and triose phosphate rises, because the light-dependent stage now supplies ATP and reduced NADP for reduction
- (B) Both fall because photosynthesis stops in the light
- (C) Glycerate 3-phosphate rises and triose phosphate falls
- (D) Neither changes, because the Calvin cycle does not need light
Show Answer
Answer: A – In the dark, glycerate 3-phosphate accumulates for lack of ATP and reduced NADP; in the light it is reduced to triose phosphate.
Homeostasis
Q40. Which statement about the control of blood glucose by glucagon is correct?
- (A) Glucagon is released when blood glucose is high and stimulates glycogenesis
- (B) Glucagon is released when blood glucose is low and stimulates glycogenolysis and gluconeogenesis in the liver
- (C) Glucagon is released by beta cells of the islets of Langerhans
- (D) Glucagon increases glucose uptake by muscle cells
Show Answer
Answer: B – Glucagon is released by alpha cells and raises blood glucose, opposing the action of insulin.
Q41. In the kidney, where does most selective reabsorption of glucose and amino acids occur?
- (A) In the glomerulus by ultrafiltration
- (B) In the proximal convoluted tubule by active transport and cotransport
- (C) In the loop of Henle by osmosis only
- (D) In the collecting duct by ADH action
Show Answer
Answer: B – These useful solutes are reabsorbed into the blood here, so they do not normally appear in urine.
Q42. A person drinks a large volume of water. Which sequence follows?
- (A) Blood water potential falls, osmoreceptors stimulate ADH release, urine becomes concentrated
- (B) Blood water potential rises, ADH release falls, collecting duct becomes less permeable, and a large volume of dilute urine is produced
- (C) ADH release rises, aquaporins increase, and urine volume falls
- (D) Blood water potential rises, ADH release rises, and water reabsorption increases
Show Answer
Answer: B – Reduced ADH means fewer aquaporins in the collecting duct, so less water is reabsorbed.
Control and coordination
Q43. During an action potential, what causes depolarisation of the axon membrane?
- (A) Potassium ions diffuse out through voltage-gated channels
- (B) Sodium ions diffuse in through voltage-gated channels, making the inside positive
- (C) The sodium-potassium pump reverses direction
- (D) Chloride ions diffuse in and neutralise the membrane
Show Answer
Answer: B – A stimulus opens sodium channels, and the influx of positive ions reverses the membrane potential.
Q44. Why does saltatory conduction in a myelinated neurone transmit impulses faster than in an unmyelinated neurone?
- (A) The impulse travels inside the myelin sheath itself
- (B) Action potentials occur only at nodes of Ranvier, so the impulse jumps between nodes
- (C) Myelin increases the diameter of the axon to several millimetres
- (D) Sodium channels are absent from myelinated neurones
Show Answer
Answer: B – Skipping the insulated regions saves time, and the nodes regenerate the action potential.
Q45. In phototropism, how does auxin cause a shoot to bend towards light?
- (A) Auxin accumulates on the shaded side, promoting cell elongation there, so the shoot bends towards the light
- (B) Auxin accumulates on the lit side and inhibits growth there completely
- (C) Auxin is destroyed on the shaded side, causing cells there to shrink
- (D) Auxin moves to the tip and stops all elongation
Show Answer
Answer: A – Faster elongation on the shaded side curves the shoot towards the light source.
Q46. Which statement about the mammalian eye and accommodation for near vision is correct?
- (A) The ciliary muscles relax, suspensory ligaments tighten, and the lens becomes thinner
- (B) The ciliary muscles contract, suspensory ligaments slacken, and the lens becomes rounder and more convex
- (C) The iris contracts to make the pupil larger
- (D) The lens moves forward without changing shape
Show Answer
Answer: B – A rounder lens refracts light more strongly, focusing the image of a near object onto the retina.
Inheritance
Q47. Two heterozygous parents for a recessive condition have children. What is the probability that a child is a carrier but does not show the condition?
- (A) 1 in 4
- (B) 1 in 2
- (C) 3 in 4
- (D) 1 in 8
Show Answer
Answer: B – The cross gives genotypes AA, Aa, Aa and aa, so half the offspring are heterozygous carriers.
Q48. What is meant by linkage between two genes?
- (A) The genes are on different chromosomes and assort independently
- (B) The genes are on the same chromosome and tend to be inherited together, unless crossing over separates them
- (C) The genes code for the same protein
- (D) The genes are both dominant
Show Answer
Answer: B – Linked genes do not give the expected 9:3:3:1 ratio in a dihybrid cross, and recombinant phenotypes are rarer.
Q49. In a test cross, an individual showing the dominant phenotype is crossed with a homozygous recessive individual. What does the result reveal?
- (A) Whether the dominant individual is homozygous or heterozygous
- (B) The chromosome number of the species
- (C) Whether the trait is sex-linked
- (D) The mutation rate of the gene
Show Answer
Answer: A – If any recessive offspring appear, the dominant parent must carry the recessive allele.
Q50. Which statement about epistasis is correct?
- (A) One gene masks the expression of another gene at a different locus
- (B) Two alleles of the same gene are both expressed
- (C) A single gene affects several different traits
- (D) Continuous variation is caused by many genes acting together
Show Answer
Answer: A – Epistasis alters expected Mendelian ratios, for example giving a 9:7 ratio in some dihybrid crosses.
Selection and evolution
Q51. Which type of selection favours the intermediate phenotype and reduces variation?
- (A) Directional selection
- (B) Disruptive selection
- (C) Stabilising selection
- (D) Artificial selection
Show Answer
Answer: C – Stabilising selection acts against both extremes, for example in human birth weight.
Q52. The Hardy-Weinberg principle can be used to estimate allele frequencies. Which condition must hold for a population to remain in Hardy-Weinberg equilibrium?
- (A) Strong natural selection must act on the gene
- (B) There must be no mutation, migration, selection or genetic drift, and mating must be random
- (C) The population must be very small
- (D) Only one allele of the gene may exist
Show Answer
Answer: B – If any of these conditions is broken, allele frequencies change and evolution occurs.
Q53. In a population, the frequency of a recessive allele is 0.2. Assuming Hardy-Weinberg equilibrium, what is the expected frequency of heterozygotes?
- (A) 0.04
- (B) 0.16
- (C) 0.32
- (D) 0.64
Show Answer
Answer: C – With p = 0.8 and q = 0.2, heterozygote frequency is 2pq = 2 x 0.8 x 0.2 = 0.32.
Q54. Which statement about the founder effect is correct?
- (A) A small group colonises a new area, carrying only a sample of the original gene pool, so allele frequencies differ from the source population
- (B) A large population splits into two equal halves with identical allele frequencies
- (C) Mutation rates increase when a population is founded
- (D) Founders always carry every allele present in the original population
Show Answer
Answer: A – Genetic drift has a large effect in small founding populations, and rare alleles may become common or be lost.
Classification, biodiversity and conservation
Q55. Which feature is used to classify organisms into the five kingdoms in the traditional system?
- (A) Their DNA sequence alone
- (B) Cell structure, body organisation and method of nutrition
- (C) Their habitat and geographical distribution only
- (D) The number of chromosomes they possess
Show Answer
Answer: B – These structural and nutritional features distinguish prokaryotes, protoctists, fungi, plants and animals.
Q56. Why is genetic diversity within a species important for its long-term survival?
- (A) It guarantees that every individual is identical and well adapted
- (B) It provides variation on which natural selection can act when the environment changes
- (C) It prevents any mutation from occurring
- (D) It increases the population size directly
Show Answer
Answer: B – A genetically uniform population is more vulnerable to disease and environmental change.
Q57. A conservation programme sets up a captive breeding programme and later reintroduces animals to the wild. Which type of conservation is this, and what is a key risk?
- (A) In situ conservation, with a risk of habitat loss
- (B) Ex situ conservation, with a risk of reduced genetic diversity if few founders are used
- (C) In situ conservation, with a risk of inbreeding in captivity
- (D) Ex situ conservation, with no risks at all
Show Answer
Answer: B – Captive breeding keeps a species alive outside its habitat, but careful management is needed to maintain genetic variation.
Genetic technology
Q58. Which statement about gene therapy for a recessive genetic disorder is correct?
- (A) A faulty gene is replaced or supplemented with a working copy, often delivered by a modified virus vector
- (B) The patient’s DNA is removed and replaced with donor DNA
- (C) Gene therapy changes the genes of all future generations in every case
- (D) Gene therapy works by giving the patient extra chromosomes
Show Answer
Answer: A – Somatic gene therapy affects only the treated individual, while germ-line therapy would affect offspring and raises additional ethical issues.
Q59. In genetic fingerprinting, why are variable number tandem repeats useful?
- (A) They are identical in all individuals
- (B) They vary in length between individuals, giving a distinctive pattern of fragments
- (C) They code for essential proteins
- (D) They are found only in bacteria
Show Answer
Answer: B – Differences in repeat number produce different fragment sizes after digestion and electrophoresis.
Q60. Which social or ethical concern is associated with genetic screening?
- (A) Screening always cures the condition it detects
- (B) Results could lead to discrimination in employment or insurance, and raise difficult decisions about whether to have children
- (C) Screening changes the DNA of the person tested
- (D) Screening is only possible after a person has died
Show Answer
Answer: B – Knowledge of genetic risk has benefits for planning and treatment, but also raises privacy and consent issues.
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