ACS General Chemistry Practice Test 6

60 original exam-style multiple-choice questions with answers & explanations — covering every major topic tested on the ACS General Chemistry exam.

Note: These are original practice questions written in the ACS exam style — not reproduced exam questions. Use them to test your readiness for the real ACS General Chemistry exam.

📱 How to use: Try each question first, then click “Show Answer” to check. Covers: atomic structure, bonding, stoichiometry, gases, thermochemistry, kinetics, equilibrium, acids & bases, electrochemistry and more.

⚛ Atomic Structure & Periodic Trends

Q1An atom of the isotope Se-79 contains how many neutrons?

(A) 34
(B) 45
(C) 79
(D) 113
Show Answer

Correct: (B)

Selenium has atomic number 34, so neutrons = 79 – 34 = 45.

Q2Which element has the ground-state electron configuration [Ar] 4s1 3d5?

(A) Mn
(B) V
(C) Fe
(D) Cr
Show Answer

Correct: (D)

Chromium is the well-known exception to the expected [Ar] 4s2 3d4 configuration, adopting [Ar] 4s1 3d5 for a half-filled d subshell.

Q3Which of the following elements has the largest electron affinity?

(A) Cl
(B) F
(C) Br
(D) I
Show Answer

Correct: (A)

Although electron affinity generally increases up a group, chlorine exceeds fluorine because fluorine's small size causes greater electron-electron repulsion when the extra electron is added.

Q4Which of the following correctly lists the elements in order of increasing atomic radius?

(A) Si < P < S < Cl
(B) Cl < P < S < Si
(C) Cl < S < P < Si
(D) Si < Cl < S < P
Show Answer

Correct: (C)

Atomic radius decreases across a period as effective nuclear charge increases: Cl < S < P < Si.

Q5In a phosphorus atom, which electron experiences the smallest effective nuclear charge?

(A) A 2s electron
(B) A 2p electron
(C) A 1s electron
(D) A 3p electron
Show Answer

Correct: (D)

The 3p valence electrons are farthest from the nucleus and most shielded by inner electrons, so they feel the smallest effective nuclear charge.

Q6Which electronic transition in a hydrogen atom emits light of the shortest wavelength?

(A) n = 3 → n = 2
(B) n = 4 → n = 2
(C) n = 5 → n = 3
(D) n = 5 → n = 1
Show Answer

Correct: (D)

The shortest wavelength corresponds to the largest energy drop, which is the n = 5 to n = 1 transition (Lyman series).

🔬 Chemical Bonding & Molecular Geometry

Q7In the best Lewis structure of carbon monoxide, CO, what are the formal charges on carbon and oxygen?

(A) C = -1, O = +1
(B) C = 0, O = 0
(C) C = +1, O = -1
(D) C = -2, O = +2
Show Answer

Correct: (A)

In the :C≡O:+ structure, carbon has one lone pair and three bonds (formal charge -1) and oxygen has one lone pair and three bonds (formal charge +1).

Q8Which of the following molecules has bond angles closest to 120°?

(A) CH4
(B) H2O
(C) SO3
(D) SF6
Show Answer

Correct: (C)

SO3 is trigonal planar with bond angles of 120°.

Q9How many lone pairs are on the xenon atom in the Lewis structure of XeF2?

(A) 1
(B) 3
(C) 2
(D) 4
Show Answer

Correct: (B)

XeF2 has a linear geometry with three lone pairs on the central xenon atom (AX2E3); each fluorine also has three lone pairs, but the question asks only about xenon.

Q10Using bond energies H-H = 436 kJ/mol, Cl-Cl = 242 kJ/mol, and H-Cl = 431 kJ/mol, estimate ΔH° for the reaction H2(g) + Cl2(g) → 2 HCl(g).

(A) -92 kJ
(B) -184 kJ
(C) +184 kJ
(D) -366 kJ
Show Answer

Correct: (B)

ΔH = (436 + 242) – 2(431) = 678 – 862 = -184 kJ.

Q11Which of the following species exhibits resonance?

(A) CO3^2-
(B) H2O
(C) CCl4
(D) NH3
Show Answer

Correct: (A)

The carbonate ion has three equivalent C-O bonds that cannot be represented by a single Lewis structure, requiring three resonance forms.

Q12Rank the following ionic compounds in order of increasing lattice energy.

(A) AlCl3 < MgCl2 < NaCl
(B) MgCl2 < NaCl < AlCl3
(C) NaCl < MgCl2 < AlCl3
(D) NaCl < AlCl3 < MgCl2
Show Answer

Correct: (C)

Lattice energy increases with cation charge for a common anion: Na+ (1+) < Mg2+ (2+) < Al3+ (3+).

Q13Which of the following molecules contains the shortest bond?

(A) I2
(B) Br2
(C) Cl2
(D) H2
Show Answer

Correct: (D)

H2 has the smallest atoms and a short single bond (~74 pm), shorter than any of the halogen-halogen bonds.

🧪 Stoichiometry & Aqueous Reactions

Q14What volume of 6.0 M HCl is required to prepare 500 mL of 0.50 M HCl?

(A) 41.7 mL
(B) 60.0 mL
(C) 24.0 mL
(D) 83.3 mL
Show Answer

Correct: (A)

Using M1V1 = M2V2: V1 = (0.50 M)(0.500 L)/(6.0 M) = 0.0417 L = 41.7 mL.

Q15What mass of AgCl precipitates when 50.0 mL of 0.200 M AgNO3 reacts with excess NaCl solution?

(A) 2.87 g
(B) 0.717 g
(C) 1.43 g
(D) 14.3 g
Show Answer

Correct: (C)

Moles Ag+ = (0.0500 L)(0.200 mol/L) = 0.0100 mol; mass AgCl = (0.0100 mol)(143.3 g/mol) = 1.43 g.

Q16A stock solution of 6.00 M HCl is used to prepare 750. mL of 0.250 M HCl. What volume of the stock solution is required?

(A) 125 mL
(B) 62.5 mL
(C) 15.6 mL
(D) 31.3 mL
Show Answer

Correct: (D)

M1V1 = M2V2 gives V1 = (0.250 M)(750. mL) / 6.00 M = 31.3 mL.

Q17Solutions of ammonium sulfide and copper(II) sulfate are mixed, forming a precipitate. What is the net ionic equation for this reaction?

(A) 2 NH4+(aq) + SO4^2-(aq) → (NH4)2SO4(aq)
(B) Cu^2+(aq) + S^2-(aq) → CuS(s)
(C) Cu^2+(aq) + SO4^2-(aq) → CuSO4(aq)
(D) 2 NH4+(aq) + S^2-(aq) → (NH4)2S(aq)
Show Answer

Correct: (B)

CuS is the insoluble precipitate; NH4+ and SO4^2- remain in solution as spectator ions.

Q18When the reaction MnO4- + SO3^2- → MnO2 + SO4^2- is balanced in basic solution with the smallest whole-number coefficients, what is the coefficient of H2O?

(A) 1
(B) 2
(C) 3
(D) 4
Show Answer

Correct: (A)

The balanced equation in base is 2 MnO4- + 3 SO3^2- + H2O → 2 MnO2 + 3 SO4^2- + 2 OH-; H2O has a coefficient of 1.

Q19A 25.00 mL sample of vinegar is titrated with 0.500 M NaOH; 18.75 mL is required to reach the phenolphthalein endpoint. What is the molarity of acetic acid (HC2H3O2) in the vinegar?

(A) 0.188 M
(B) 0.750 M
(C) 0.375 M
(D) 1.33 M
Show Answer

Correct: (C)

0.01875 L x 0.500 mol/L = 0.00938 mol NaOH = 0.00938 mol acetic acid (1:1); 0.00938 mol / 0.02500 L = 0.375 M.

Q20Calcium carbonate decomposes according to CaCO3(s) → CaO(s) + CO2(g). Heating 50.0 g of CaCO3 yields 19.5 g of CaO. What is the percent yield of CaO?

(A) 39.0%
(B) 87.2%
(C) 56.1%
(D) 69.6%
Show Answer

Correct: (D)

50.0 g CaCO3 = 0.500 mol, giving 0.500 mol CaO = 28.0 g theoretically; (19.5 g / 28.0 g) x 100 = 69.6%.

🌀 Gases & Intermolecular Forces

Q21Which of the following gases has the greatest density at STP?

(A) CH4
(B) SO2
(C) O2
(D) He
Show Answer

Correct: (B)

At the same T and P, gas density is proportional to molar mass; SO2 (64.07 g/mol) is the heaviest of the four.

Q22A sample of an unknown gas effuses through a pinhole in 48.0 s, while the same volume of neon effuses in 30.0 s under identical conditions. What is the approximate molar mass of the unknown gas?

(A) 51.7 g/mol
(B) 32.3 g/mol
(C) 82.7 g/mol
(D) 12.6 g/mol
Show Answer

Correct: (A)

Effusion time is proportional to sqrt(M), so M = 20.18 g/mol x (48.0/30.0)^2 = 51.7 g/mol.

Q23At a given temperature, which liquid would have the highest vapor pressure?

(A) Water
(B) Ethanol
(C) Acetone
(D) Diethyl ether
Show Answer

Correct: (D)

Diethyl ether has the weakest intermolecular forces (no hydrogen-bond donation), so its molecules escape most readily into the vapor phase.

Q24A 10.0 L vessel at 298 K contains 4.00 g of He and 16.0 g of CH4. What is the partial pressure of CH4?

(A) 1.22 atm
(B) 4.88 atm
(C) 2.44 atm
(D) 3.66 atm
Show Answer

Correct: (C)

n(He) = 0.999 mol, n(CH4) = 0.998 mol, so the mole fraction of CH4 is 0.500; total pressure = 4.88 atm, giving P(CH4) = 0.500 x 4.88 atm = 2.44 atm.

Q25Which compound has the highest boiling point?

(A) CH3CH2OH
(B) CH3OCH3
(C) CH3CH2F
(D) CH3CH2CH3
Show Answer

Correct: (A)

Ethanol can form hydrogen bonds, which are stronger than the dipole-dipole forces in dimethyl ether and fluoroethane or the London dispersion forces in propane.

🔥 Thermochemistry

Q26Calculate ΔH° for the combustion of ethane, C2H6(g) + 7/2 O2(g) → 2 CO2(g) + 3 H2O(l), given ΔHf° values (kJ/mol): CO2(g) = -394, H2O(l) = -286, C2H6(g) = -85.

(A) -1731 kJ
(B) -1561 kJ
(C) +1561 kJ
(D) -1391 kJ
Show Answer

Correct: (B)

ΔH = [2(-394) + 3(-286)] – (-85) = -1646 + 85 = -1561 kJ.

Q27When 4.50 g of NH4NO3 (80.05 g/mol) dissolves in 60.0 g of water, the temperature of the solution drops from 22.4°C to 18.9°C. What is the molar enthalpy of solution of NH4NO3? (assume the specific heat of the solution is 4.184 J/g·°C)

(A) +14.2 kJ/mol
(B) -16.8 kJ/mol
(C) +1.68 kJ/mol
(D) +16.8 kJ/mol
Show Answer

Correct: (D)

The solution loses q = (64.5 g)(4.184 J/g·°C)(-3.5°C) = -945 J, so the dissolution absorbs +945 J; 4.50 g = 0.0562 mol, giving ΔHsoln = +16.8 kJ/mol (endothermic).

Q28Calculate ΔH for 2 NO(g) + O2(g) → 2 NO2(g), given:
N2(g) + O2(g) → 2 NO(g) ΔH = +180 kJ
N2(g) + 2 O2(g) → 2 NO2(g) ΔH = +66 kJ

(A) -114 kJ
(B) +114 kJ
(C) -246 kJ
(D) +246 kJ
Show Answer

Correct: (A)

Subtracting the first equation from the second gives the target reaction with ΔH = 66 – 180 = -114 kJ.

Q29How much heat is released when 36.0 g of water vapor at 100°C condenses to liquid water at 100°C? (ΔHvap = 40.7 kJ/mol)

(A) 40.7 kJ
(B) 1460 kJ
(C) 81.4 kJ
(D) 20.4 kJ
Show Answer

Correct: (C)

36.0 g H2O = 2.00 mol; heat released = 2.00 mol x 40.7 kJ/mol = 81.4 kJ.

Q30A 150.0 g sample of copper (specific heat 0.385 J/g·°C) absorbs 2.31 kJ of heat. If the initial temperature is 25.0°C, what is the final temperature?

(A) 45.0°C
(B) 65.0°C
(C) 35.0°C
(D) 55.0°C
Show Answer

Correct: (B)

ΔT = 2310 J / (150.0 g x 0.385 J/g·°C) = 40.0°C; final temperature = 25.0 + 40.0 = 65.0°C.

Q31Given the following thermochemical data:
C(s) + O2(g) → CO2(g), ΔH = −394 kJ
CO(g) + 1/2O2(g) → CO2(g), ΔH = −283 kJ
What is ΔH for C(s) + 1/2O2(g) → CO(g)?

(A) −677 kJ
(B) +111 kJ
(C) −394 kJ
(D) −111 kJ
Show Answer

Correct: (D)

Reverse the second equation (+283 kJ) and add to the first: −394 + 283 = −111 kJ.

⚡ Quantum Theory & Electronic Structure

Q32How many angular (planar) nodes does a 3d orbital have?

(A) 0
(B) 1
(C) 2
(D) 3
Show Answer

Correct: (C)

Number of angular nodes equals the azimuthal quantum number l, and for a d orbital l = 2.

Q33Which of the following sets of quantum numbers (n, l, m_l) is NOT allowed?

(A) 3, 1, −2
(B) 5, 4, +4
(C) 2, 0, 0
(D) 4, 2, −1
Show Answer

Correct: (A)

For l = 1, |m_l| cannot exceed 1, so m_l = −2 is forbidden; all other sets are valid.

Q34An electron in a hydrogen atom falls from n = 3 to n = 2, emitting a photon with energy 1.89 eV. What is the frequency of this photon? (h = 6.626 × 10^−34 J·s; 1 eV = 1.602 × 10^−19 J)

(A) 6.56 × 10^14 s^−1
(B) 1.89 × 10^14 s^−1
(C) 2.19 × 10^7 s^−1
(D) 4.57 × 10^14 s^−1
Show Answer

Correct: (D)

E = 1.89 × 1.602 × 10^−19 = 3.03 × 10^−19 J; ν = E/h = 4.57 × 10^14 s^−1.

Q35A metal has a work function of 4.0 eV. What is the longest wavelength of light that can still eject electrons from this metal? (hc = 1240 eV·nm)

(A) 310 nm
(B) 620 nm
(C) 155 nm
(D) 1240 nm
Show Answer

Correct: (A)

Threshold: hc/λ_max = 4.0 eV, so λ_max = 1240/4.0 = 310 nm; longer wavelengths lack sufficient photon energy.




⏱ Chemical Kinetics

Q36Initial-rate data for X + Y → products:
Expt 1: [X] = 0.20 M, [Y] = 0.10 M, rate = 3.0 × 10^−4 M/s
Expt 2: [X] = 0.40 M, [Y] = 0.10 M, rate = 6.0 × 10^−4 M/s
Expt 3: [X] = 0.20 M, [Y] = 0.30 M, rate = 2.7 × 10^−3 M/s
What is the rate law?

(A) rate = k[X][Y]
(B) rate = k[X][Y]^2
(C) rate = k[X]^2[Y]
(D) rate = k[Y]^2
Show Answer

Correct: (B)

Doubling [X] doubles the rate (first order in X); tripling [Y] increases the rate ninefold (second order in Y).

Q37A first-order decomposition has a half-life of 45 min. Starting with 1.00 g of reactant, how long will it take for 0.125 g to remain?

(A) 135 min
(B) 45 min
(C) 90 min
(D) 360 min
Show Answer

Correct: (A)

0.125 g is (1/2)^3 of the original, so 3 half-lives elapse: 3 × 45 = 135 min.

Q38Two reactions have the same frequency factor A at 298 K. Reaction 1 has E_a = 80 kJ/mol and reaction 2 has E_a = 100 kJ/mol. Approximately how much faster is reaction 1 than reaction 2? (R = 8.314 J/mol·K)

(A) 3.2 × 10^3 times
(B) 1.25 times
(C) 20 times
(D) 100 times
Show Answer

Correct: (A)

k1/k2 = e^(ΔE_a/RT) = e^(20000/(8.314 × 298)) = e^8.07 ≈ 3.2 × 10^3.

Q39Which statement best explains why reaction rates generally increase with increasing temperature?

(A) All molecular collisions become perfectly elastic at higher temperatures
(B) A greater fraction of molecules possess kinetic energy exceeding the activation energy
(C) The equilibrium constant of the reaction becomes larger
(D) The enthalpy change of the reaction becomes more negative
Show Answer

Correct: (B)

Higher T shifts the Boltzmann distribution so more collisions have E ≥ E_a; the collision frequency increase is comparatively minor.

Q40A proposed mechanism is:
Step 1 (fast): A + B → C + D
Step 2 (slow): C + E → F + G
Which species is the reaction intermediate?

(A) A
(B) E
(C) F
(D) C
Show Answer

Correct: (D)

C is produced in step 1 and consumed in step 2, never appearing in the overall equation, which defines an intermediate.

Q41A plot of 1/[A] versus time for a decomposition reaction gives a straight line. What is the order of the reaction with respect to A?

(A) second
(B) zero
(C) first
(D) third
Show Answer

Correct: (A)

The integrated rate law 1/[A]_t = kt + 1/[A]_0 is linear in time only for a second-order reaction.

⇆ Chemical Equilibrium

Q42For H2(g) + I2(g) ⇌ 2HI(g), the equilibrium concentrations are [H2] = 0.10 M, [I2] = 0.10 M, and [HI] = 0.50 M. What is Kc?

(A) 2.5
(B) 25
(C) 250
(D) 0.040
Show Answer

Correct: (B)

Kc = [HI]^2/([H2][I2]) = (0.50)^2/(0.10 × 0.10) = 0.25/0.010 = 25.

Q43For 2NO2(g) ⇌ N2O4(g) at equilibrium, the volume of the container is suddenly decreased at constant temperature. What happens?

(A) The equilibrium shifts toward NO2
(B) No shift occurs because only temperature changes K
(C) The equilibrium shifts toward N2O4
(D) The equilibrium shifts toward NO2 and then returns to its original position
Show Answer

Correct: (C)

Decreasing volume raises total pressure, favoring the side with fewer moles of gas (1 mol N2O4 vs 2 mol NO2).

Q44For which of the following reactions does Kp equal Kc at any given temperature?

(A) N2(g) + 3H2(g) ⇌ 2NH3(g)
(B) 2SO2(g) + O2(g) ⇌ 2SO3(g)
(C) PCl5(g) ⇌ PCl3(g) + Cl2(g)
(D) CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
Show Answer

Correct: (D)

Kp = Kc(RT)^Δn; only this reaction has Δn = 0 (2 gas mol → 2 gas mol), so Kp = Kc.

Q45For A(g) ⇌ 2B(g), Kp = 0.50. A mixture initially has P_A = 2.0 atm and P_B = 1.0 atm. Which statement is correct?

(A) Q < K; the reaction proceeds toward products
(B) Q > K; the reaction proceeds toward reactants
(C) Q = K; the system is already at equilibrium
(D) Equilibrium cannot be determined without the total pressure
Show Answer

Correct: (C)

Qp = P_B^2/P_A = (1.0)^2/2.0 = 0.50 = Kp, so the system is at equilibrium.

Q46For the reaction 2 SO2(g) + O2(g) ⇆ 2 SO3(g), Kc = 4.6 × 10^4 at 900 K. What is the value of Kp? (R = 0.0821 L·atm/mol·K)

(A) 6.2 × 10^2
(B) 4.6 × 10^4
(C) 3.4 × 10^6
(D) 8.5
Show Answer

Correct: (A)

Δn = 2 – 3 = -1, so Kp = Kc(RT)^Δn = (4.6 × 10^4)/(0.0821 × 900) = 6.2 × 10^2.

Q47For PCl5(g) ⇆ PCl3(g) + Cl2(g), Kc = 0.042 at 250°C. A 5.00 L flask contains 0.100 mol PCl5, 0.200 mol PCl3, and 0.150 mol Cl2. In which direction will the reaction proceed?

(A) Toward products; [PCl3] and [Cl2] will increase.
(B) Toward reactants; [PCl5] will increase.
(C) The system is at equilibrium; no net change will occur.
(D) Toward products; [PCl5] will increase.
Show Answer

Correct: (B)

Q = (0.0400)(0.0300)/(0.0200) = 0.060 > Kc = 0.042, so the reaction shifts left toward reactants.

🧫 Acids, Bases & Buffers

Q48What is the pH of a 0.20 M solution of pyridine, C5H5N (Kb = 1.7 × 10^-9)?

(A) 9.27
(B) 4.73
(C) 8.77
(D) 12.04
Show Answer

Correct: (A)

[OH-] = √(Kb × C) = 1.8 × 10^-5 M, so pOH = 4.73 and pH = 9.27.

Q49The first ionization of carbonic acid has Ka1 = 4.3 × 10^-7. What is the pH of a 0.10 M H2CO3 solution? (Ignore the second ionization.)

(A) 1.00
(B) 6.37
(C) 2.68
(D) 3.68
Show Answer

Correct: (D)

[H+] = √(Ka1 × C) = √(4.3 × 10^-8) = 2.1 × 10^-4 M, so pH = 3.68.

Q50A buffer contains 0.30 M acetic acid and 0.30 M sodium acetate. What is the pH after 0.10 mol of HCl is added per liter of buffer? (Ka = 1.8 × 10^-5)

(A) 4.74
(B) 5.04
(C) 4.44
(D) 3.74
Show Answer

Correct: (C)

The added H+ converts acetate to acetic acid: [HA] = 0.40 M, [A-] = 0.20 M; pH = 4.74 + log(0.20/0.40) = 4.44.

Q51A 0.10 M solution of methylamine, CH3NH2 (Kb = 4.4 × 10^-4), is titrated with 0.10 M HCl. Which statement is correct?

(A) The pH at the equivalence point is 7.00.
(B) The pH at the equivalence point is less than 7.00.
(C) The pH at the half-equivalence point equals the pKb of methylamine.
(D) Methylamine is the titrant and HCl is the analyte.
Show Answer

Correct: (B)

At the equivalence point only CH3NH3+ is present, which hydrolyzes to give an acidic solution (pH < 7).

Q52The Kb of ammonia is 1.8 × 10^-5. What is the Ka of the ammonium ion, NH4+?

(A) 5.6 × 10^-10
(B) 1.8 × 10^-5
(C) 1.8 × 10^-9
(D) 5.6 × 10^-5
Show Answer

Correct: (A)

Ka × Kb = Kw, so Ka = (1.0 × 10^-14)/(1.8 × 10^-5) = 5.6 × 10^-10.

Q53Consider the acids: HClO (Ka = 3.5 × 10^-8), HCN (Ka = 6.2 × 10^-10), HF (Ka = 6.8 × 10^-4), CH3COOH (Ka = 1.8 × 10^-5). Which conjugate base is the strongest?

(A) ClO-
(B) CN-
(C) F-
(D) CH3COO-
Show Answer

Correct: (B)

The weakest acid (HCN, smallest Ka) has the strongest conjugate base (CN-).

🔋 Thermodynamics & Electrochemistry

Q54Which set of conditions gives a reaction that is spontaneous at all temperatures?

(A) ΔH < 0, ΔS > 0
(B) ΔH > 0, ΔS < 0
(C) ΔH > 0, ΔS > 0
(D) ΔH < 0, ΔS < 0
Show Answer

Correct: (A)

With ΔH negative and -TΔS negative, ΔG = ΔH – TΔS is negative at every temperature.

Q55For the reaction 2 H2O2(l) → 2 H2O(l) + O2(g), ΔH° = -196 kJ and ΔS° = +125 J/K. What is ΔG° at 298 K?

(A) -159 kJ
(B) +233 kJ
(C) -196 kJ
(D) -233 kJ
Show Answer

Correct: (D)

ΔG° = ΔH° – TΔS° = -196 kJ – (298 K)(0.125 kJ/K) = -233 kJ.

Q56For the galvanic cell Mg(s) | Mg^2+(1 M) || Ag+(1 M) | Ag(s), with E°(Mg^2+/Mg) = -2.37 V and E°(Ag+/Ag) = +0.80 V, what is the standard cell potential?

(A) -3.17 V
(B) 1.57 V
(C) 3.17 V
(D) 2.37 V
Show Answer

Correct: (C)

E°cell = E°cathode – E°anode = (+0.80 V) – (-2.37 V) = 3.17 V.

Q57How long must a current of 4.00 A flow to deposit 12.7 g of copper (molar mass 63.5 g/mol) from CuSO4(aq)?

(A) 4.82 × 10^3 s
(B) 9.65 × 10^3 s
(C) 2.41 × 10^3 s
(D) 1.93 × 10^4 s
Show Answer

Correct: (B)

12.7 g Cu = 0.200 mol, requiring 0.400 mol e- (Cu^2+ + 2e- → Cu); charge = 0.400 × 96485 = 3.86 × 10^4 C; time = 3.86 × 10^4/4.00 = 9.65 × 10^3 s.

Q58Given E° values: Mg^2+/Mg = -2.37 V, Zn^2+/Zn = -0.76 V, Cu^2+/Cu = +0.34 V, Ag+/Ag = +0.80 V. Which species is the strongest reducing agent?

(A) Ag+
(B) Cu(s)
(C) Zn(s)
(D) Mg(s)
Show Answer

Correct: (D)

The strongest reducing agent is the species most easily oxidized, which corresponds to the most negative reduction potential: Mg(s).

☢ Nuclear & Descriptive Chemistry

Q59Complete the nuclear equation: ^238_92U → ^234_90Th + ?

(A) ^4_2He
(B) ^0_-1e
(C) ^1_0n
(D) ^0_1e
Show Answer

Correct: (A)

Mass number: 238 = 234 + 4; atomic number: 92 = 90 + 2, identifying an alpha particle, ^4_2He.

Q60Which ion is correctly matched with its formula and charge?

(A) Sulfate — SO3^2-
(B) Nitrate — NO2-
(C) Carbonate — CO3^2-
(D) Hydroxide — OH2-
Show Answer

Correct: (C)

Carbonate is CO3^2-; sulfate is SO4^2-, nitrate is NO3-, and hydroxide is OH-.