ACS General Chemistry Practice Test 2

60 original exam-style multiple-choice questions with answers & explanations — covering every major topic tested on the ACS General Chemistry exam.

Note: These are original practice questions written in the ACS exam style — not reproduced exam questions. Use them to test your readiness for the real ACS General Chemistry exam.

📱 How to use: Try each question first, then click “Show Answer” to check. Covers: atomic structure, bonding, stoichiometry, gases, thermochemistry, kinetics, equilibrium, acids & bases, electrochemistry and more.

⚛ Atomic Structure & Periodic Trends

Q1The ground-state electron configuration of chromium (Z = 24) is

(A) [Ar] 4s^2 3d^4
(B) [Ar] 4s^2 3d^5
(C) [Ar] 4s^1 3d^5
(D) [Ar] 3d^6
Show Answer

Correct: (C)

A half-filled 4s and half-filled 3d subshell is extra stable, so one 4s electron is promoted to give [Ar] 4s^1 3d^5.

Q2Which element has the largest atomic radius?

(A) Na
(B) Mg
(C) Ca
(D) K
Show Answer

Correct: (D)

Radius increases down a group; K is below Na in Group 1 and also to the left of Ca, so it is the largest.

Q3The successive ionization energies of an element are IE1 = 738, IE2 = 1451, IE3 = 7733, IE4 = 10543 kJ/mol. The element is most likely in Group

(A) 2
(B) 14
(C) 15
(D) 16
Show Answer

Correct: (A)

The large jump between IE2 and IE3 shows the third electron comes from a filled inner shell, meaning two valence electrons: Group 2.

Q4Boron has two natural isotopes: ^10B (10.013 u) and ^11B (11.009 u). If the average atomic mass of boron is 10.81 u, the percent abundance of ^10B is closest to

(A) 10%
(B) 20%
(C) 50%
(D) 80%
Show Answer

Correct: (B)

Let x = fraction of ^10B: 10.013x + 11.009(1 − x) = 10.81, so 0.996x = 0.199 and x = 0.20, or 20%.

Q5Which set of quantum numbers (n, l, ml, ms) is NOT allowed for an electron in an atom?

(A) (3, 2, −2, +1/2)
(B) (2, 1, 0, −1/2)
(C) (4, 3, 2, +1/2)
(D) (2, 2, 1, +1/2)
Show Answer

Correct: (D)

The angular momentum quantum number l must be less than n, so l = 2 is not allowed when n = 2.

Q6Which ion has the smallest ionic radius?

(A) F^-
(B) O^2-
(C) Mg^2+
(D) Na^+
Show Answer

Correct: (C)

All four ions are isoelectronic; the one with the most protons, Mg^2+ (Z = 12), pulls the electrons in most tightly.

🔬 Chemical Bonding & Molecular Geometry

Q7In the best Lewis structure of SO3, the number of lone pairs on the central sulfur atom is

(A) 0
(B) 1
(C) 2
(D) 3
Show Answer

Correct: (A)

Sulfur forms three S=O double bonds (formal charges all zero), using all six valence electrons, leaving no lone pairs on S.

Q8The molecular geometry of the ammonium ion, NH4^+, is

(A) trigonal pyramidal
(B) tetrahedral
(C) square planar
(D) seesaw
Show Answer

Correct: (B)

Nitrogen has four bonding pairs and no lone pairs, giving a tetrahedral arrangement.

Q9Which bond is the most polar?

(A) C−H
(B) N−H
(C) F−H
(D) O−H
Show Answer

Correct: (C)

Fluorine has the largest electronegativity difference with hydrogen, so the F−H bond is the most polar.

Q10The hybridization of the carbon atom in CO2 is

(A) sp^2
(B) sp^3
(C) sp^3d
(D) sp
Show Answer

Correct: (D)

CO2 is linear with two electron domains on carbon, requiring two hybrid orbitals: sp.

Q11Which statement about the carbonate ion, CO3^2-, is correct?

(A) It contains two C=O double bonds and one C−O single bond in fixed positions.
(B) All three C−O bonds are equivalent.
(C) The carbon atom has one lone pair.
(D) The molecular geometry is trigonal pyramidal.
Show Answer

Correct: (B)

Resonance delocalizes the pi bond over all three C−O bonds, making them identical with bond order 1 1/3; the ion is trigonal planar with no lone pair on carbon.

Q12Which substance has the highest boiling point?

(A) H2O
(B) CH4
(C) CO2
(D) Ne
Show Answer

Correct: (A)

H2O exhibits hydrogen bonding, far stronger than the London dispersion forces in CH4, CO2, and Ne.

Q13Which molecule has the longest bond?

(A) H2
(B) N2
(C) O2
(D) F2
Show Answer

Correct: (D)

Bond length increases as bond order decreases: F2 (single bond, 142 pm) is longer than O2 (121 pm), N2 (110 pm), and H2 (74 pm).

🧪 Stoichiometry & Aqueous Reactions

Q14How many moles are in 49.0 g of H2SO4? (atomic masses: H = 1.0, S = 32.1, O = 16.0 g/mol)

(A) 0.250 mol
(B) 0.333 mol
(C) 0.500 mol
(D) 1.00 mol
Show Answer

Correct: (C)

Molar mass H2SO4 = 2(1.0) + 32.1 + 4(16.0) = 98.1 g/mol; 49.0 / 98.1 = 0.500 mol.

Q15What volume of 0.100 M NaOH is required to neutralize 25.0 mL of 0.200 M H2SO4?

(A) 100.0 mL
(B) 25.0 mL
(C) 50.0 mL
(D) 200.0 mL
Show Answer

Correct: (A)

H2SO4 + 2NaOH → Na2SO4 + 2H2O: 0.0250 L × 0.200 M = 0.00500 mol H2SO4 needs 0.0100 mol NaOH, so V = 0.0100 / 0.100 = 0.100 L = 100.0 mL.

Q16When aqueous solutions of Pb(NO3)2 and KI are mixed, the net ionic equation is

(A) K^+(aq) + NO3^-(aq) → KNO3(aq)
(B) Pb^2+(aq) + 2I^-(aq) → PbI2(s)
(C) Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq)
(D) Pb^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + 2I^-(aq) → PbI2(s) + 2K^+(aq) + 2NO3^-(aq)
Show Answer

Correct: (B)

PbI2 precipitates while K^+ and NO3^- are spectator ions and cancel.

Q17A 50.0 mL sample of 2.00 M CuSO4 is diluted to a total volume of 250.0 mL. The concentration of the diluted solution is

(A) 0.100 M
(B) 0.200 M
(C) 0.250 M
(D) 0.400 M
Show Answer

Correct: (D)

M2 = M1V1/V2 = (2.00 × 50.0) / 250.0 = 0.400 M.

Q18A compound has the empirical formula CH2 and a molar mass of 56.0 g/mol. Its molecular formula is

(A) CH2
(B) C2H4
(C) C4H8
(D) C6H12
Show Answer

Correct: (C)

Empirical mass CH2 = 14.0 g/mol; 56.0 / 14.0 = 4, so the molecular formula is C4H8.

Q1910.0 g of Ca (40.1 g/mol) reacts with 10.0 g of Cl2 (70.9 g/mol): Ca + Cl2 → CaCl2. Which reactant limits, and what mass of CaCl2 (110.98 g/mol) forms?

(A) Cl2 limiting; 15.6 g CaCl2
(B) Ca limiting; 27.7 g CaCl2
(C) Cl2 limiting; 31.3 g CaCl2
(D) Neither; the reaction does not occur under these conditions
Show Answer

Correct: (A)

10.0 g Ca = 0.249 mol and 10.0 g Cl2 = 0.141 mol; the 1:1 stoichiometry makes Cl2 limiting, giving 0.141 × 110.98 = 15.6 g CaCl2.

Q20The mass percent of nitrogen in NH4NO3 is closest to (N = 14.01, H = 1.008, O = 16.00 g/mol)

(A) 17.5%
(B) 35.0%
(C) 43.7%
(D) 60.0%
Show Answer

Correct: (B)

Molar mass = 14.01 + 4(1.008) + 14.01 + 3(16.00) = 80.05 g/mol; (2 × 14.01 / 80.05) × 100% = 35.0%.

🌀 Gases & Intermolecular Forces

Q21A 3.00 L container holds 1.20 mol of O2 gas at 37°C. What is the pressure in the container? (R = 0.0821 L·atm/mol·K)

(A) 5.09 atm
(B) 20.4 atm
(C) 10.2 atm
(D) 0.984 atm
Show Answer

Correct: (C)

P = nRT/V = (1.20)(0.0821)(310)/(3.00) = 10.2 atm.

Q22A gas Y effuses at 0.500 times the rate of helium (molar mass 4.00 g/mol) under identical conditions. What is the molar mass of Y?

(A) 8.00 g/mol
(B) 16.0 g/mol
(C) 32.0 g/mol
(D) 64.0 g/mol
Show Answer

Correct: (B)

By Graham's law, (0.500)^2 = 4.00/M(Y), so M(Y) = 4.00/0.25 = 16.0 g/mol.

Q23A gas mixture of N2 and Ar has a total pressure of 4.00 atm. If the mole fraction of N2 is 0.25, what is the partial pressure of Ar?

(A) 0.750 atm
(B) 1.00 atm
(C) 2.00 atm
(D) 3.00 atm
Show Answer

Correct: (D)

P(Ar) = X(Ar) × P(total) = (1 − 0.25)(4.00 atm) = 3.00 atm.

Q24Which substance has the highest vapor pressure at 25°C?

(A) CH3OCH3 (dimethyl ether)
(B) CH3CH2OH (ethanol)
(C) H2O
(D) CH3CH2CH2CH2CH3 (pentane)
Show Answer

Correct: (A)

Dimethyl ether cannot hydrogen bond and has the lowest boiling point, so it has the weakest intermolecular forces and the highest vapor pressure.

Q25At a given temperature, which gas has the greatest average molecular speed?

(A) CO2
(B) O2
(C) H2
(D) N2
Show Answer

Correct: (C)

Average molecular speed is inversely proportional to the square root of molar mass; H2 is the lightest gas listed.

🔥 Thermochemistry

Q26A 200.0 g sample of water cools from 90.0°C to 40.0°C. What is q for the water? (specific heat of water = 4.18 J/g·°C)

(A) +20.9 kJ
(B) −41.8 kJ
(C) +41.8 kJ
(D) −83.6 kJ
Show Answer

Correct: (B)

q = mcΔT = (200.0)(4.18)(40.0 − 90.0) = −4.18 × 10^4 J = −41.8 kJ; the negative sign indicates heat lost.

Q27Given the following enthalpies:
C2H2(g) + 5/2 O2(g) → 2 CO2(g) + H2O(l) ΔH = −1299.6 kJ
C(s) + O2(g) → CO2(g) ΔH = −393.5 kJ
H2(g) + 1/2 O2(g) → H2O(l) ΔH = −285.8 kJ
What is the standard enthalpy of formation of C2H2(g)?

(A) −226.8 kJ/mol
(B) +1299.6 kJ/mol
(C) −1072.8 kJ/mol
(D) +226.8 kJ/mol
Show Answer

Correct: (D)

By Hess's law, ΔHf = 2(−393.5) + (−285.8) − (−1299.6) = +226.8 kJ/mol.

Q28Use average bond enthalpies to estimate ΔH for the reaction 2 H2(g) + O2(g) → 2 H2O(g). (H−H = 436 kJ/mol, O=O = 498 kJ/mol, O−H = 463 kJ/mol)

(A) −482 kJ
(B) +482 kJ
(C) −3222 kJ
(D) −241 kJ
Show Answer

Correct: (A)

Bonds broken: 2(436) + 498 = 1370 kJ; bonds formed: 4(463) = 1852 kJ; ΔH = 1370 − 1852 = −482 kJ.

Q29In a coffee-cup calorimeter, 25.0 mL of 1.0 M HCl and 25.0 mL of 1.0 M NaOH, both initially at 25.0°C, are mixed. The temperature rises to 31.6°C. What is ΔH for the neutralization reaction per mole of water formed? (Assume density 1.00 g/mL and specific heat 4.18 J/g·°C for the solution.)

(A) −27.6 kJ/mol
(B) −110 kJ/mol
(C) −55.2 kJ/mol
(D) +55.2 kJ/mol
Show Answer

Correct: (C)

q(solution) = (50.0)(4.18)(6.6) = 1379 J; moles H2O = 0.0250; ΔH = −1.379 kJ/0.0250 mol = −55.2 kJ/mol.

Q30Which statement is true for an endothermic reaction?

(A) ΔH is negative
(B) The products have lower enthalpy than the reactants
(C) Heat is released to the surroundings
(D) The temperature of the surroundings decreases
Show Answer

Correct: (D)

An endothermic reaction absorbs heat from the surroundings, cooling them; ΔH is positive and the products are higher in enthalpy.

Q31Calculate ΔH for the combustion of methane: CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l), given ΔHf°: CH4 = −74.8 kJ/mol, CO2 = −393.5 kJ/mol, H2O(l) = −285.8 kJ/mol.

(A) −965.1 kJ
(B) −890.3 kJ
(C) +890.3 kJ
(D) −815.5 kJ
Show Answer

Correct: (B)

ΔH = [−393.5 + 2(−285.8)] − [−74.8 + 0] = −890.3 kJ.

⚡ Quantum Theory & Electronic Structure

Q32A metal has a threshold frequency of 1.20 × 10^15 s^-1 for the photoelectric effect. Light of wavelength 180 nm strikes the metal surface. What is the kinetic energy of the ejected electron? (h = 6.626 × 10^-34 J·s, c = 3.00 × 10^8 m/s)

(A) 7.95 × 10^-19 J
(B) 3.09 × 10^-19 J
(C) 1.10 × 10^-18 J
(D) 1.90 × 10^-18 J
Show Answer

Correct: (B)

E(photon) = hc/λ = 1.10 × 10^-18 J; work function Φ = hν0 = 7.95 × 10^-19 J; KE = 1.10 × 10^-18 − 7.95 × 10^-19 = 3.09 × 10^-19 J.

Q33How many orbitals are in the n = 4 principal shell, and what is the maximum number of electrons it can hold?

(A) 4 orbitals, 8 electrons
(B) 8 orbitals, 16 electrons
(C) 9 orbitals, 18 electrons
(D) 16 orbitals, 32 electrons
Show Answer

Correct: (D)

Number of orbitals = n^2 = 16; maximum electrons = 2n^2 = 32.

Q34What is the de Broglie wavelength of a proton moving at 2.00 × 10^5 m/s? (h = 6.626 × 10^-34 J·s, mass of proton = 1.67 × 10^-27 kg)

(A) 3.97 × 10^-12 m
(B) 9.92 × 10^-13 m
(C) 1.98 × 10^-12 m
(D) 1.98 × 10^-10 m
Show Answer

Correct: (C)

λ = h/mv = (6.626 × 10^-34)/(1.67 × 10^-27)(2.00 × 10^5) = 1.98 × 10^-12 m.

Q35An electron in a hydrogen atom falls from the n = 4 level to the n = 2 level. What is the wavelength of the emitted photon? (Rydberg constant R = 1.097 × 10^7 m^-1)

(A) 486 nm
(B) 656 nm
(C) 434 nm
(D) 1875 nm
Show Answer

Correct: (A)

1/λ = R(1/2^2 − 1/4^2) = (1.097 × 10^7)(3/16) = 2.06 × 10^6 m^-1, so λ = 4.86 × 10^-7 m = 486 nm.




⏱ Chemical Kinetics

Q36For the reaction 2 X + Y → products, the following initial-rate data were collected.
Experiment 1: [X] = 0.20 M, [Y] = 0.10 M, initial rate = 4.0 × 10^-4 M/s
Experiment 2: [X] = 0.40 M, [Y] = 0.10 M, initial rate = 4.0 × 10^-4 M/s
Experiment 3: [X] = 0.20 M, [Y] = 0.20 M, initial rate = 1.6 × 10^-3 M/s
What is the rate law for this reaction?

(A) Rate = k[X][Y]
(B) Rate = k[Y]
(C) Rate = k[X][Y]^2
(D) Rate = k[Y]^2
Show Answer

Correct: (D)

Doubling [X] does not change the rate (zero order in X); doubling [Y] quadruples the rate (second order in Y).

Q37A first-order reaction has a rate constant of 1.4 × 10^-2 s^-1. What is the half-life of the reactant?

(A) 50 s
(B) 14 s
(C) 99 s
(D) 71 s
Show Answer

Correct: (A)

t1/2 = 0.693/k = 0.693/(1.4 × 10^-2) = 49.5 s ≈ 50 s.

Q38A proposed mechanism for 2 NO(g) + Br2(g) → 2 NOBr(g) is:
Step 1: NO + Br2 ⇌ NOBr2 (fast equilibrium)
Step 2: NOBr2 + NO → 2 NOBr (slow)
What rate law is predicted by this mechanism?

(A) Rate = k[NO][Br2]
(B) Rate = k[NOBr2]
(C) Rate = k[NO]^2[Br2]
(D) Rate = k[NO]^2
Show Answer

Correct: (C)

The slow step gives Rate = k[NOBr2][NO]; from the fast pre-equilibrium, [NOBr2] = K[NO][Br2], so Rate = k'[NO]^2[Br2].

Q39A first-order reaction has k = 0.050 s^-1. If the initial concentration of reactant is 1.20 M, what is the concentration after 30.0 s?

(A) 0.054 M
(B) 0.27 M
(C) 0.60 M
(D) 1.1 M
Show Answer

Correct: (B)

ln[A] = ln(1.20) − (0.050)(30) = 0.182 − 1.50 = −1.32, so [A] = e^−1.32 = 0.27 M.

Q40A reaction has the rate law Rate = k[X]^2[Y]. What are the units of the rate constant k?

(A) s^-1
(B) M·s^-1
(C) M^-1·s^-1
(D) M^-2·s^-1
Show Answer

Correct: (D)

The reaction is third order overall, so k must have units of M^(1−3)·s^-1 = M^-2·s^-1 for the rate to come out in M/s.

Q41For most reactions, raising the temperature by 10°C approximately doubles the reaction rate. This observation is best explained by the fact that at higher temperature:

(A) a larger fraction of molecules have energy greater than the activation energy
(B) the activation energy of the reaction decreases
(C) collisions occur exactly twice as often
(D) the equilibrium constant of the reaction doubles
Show Answer

Correct: (A)

The rate increase comes mainly from the exponential increase in the fraction of molecules with enough energy to react, not from a modest increase in collision frequency.

⇆ Chemical Equilibrium

Q42For the reaction CaCO3(s) ⇌ CaO(s) + CO2(g), what is the correct expression for Kc?

(A) Kc = [CaO][CO2]/[CaCO3]
(B) Kc = [CO2]
(C) Kc = [CaO]/[CaCO3]
(D) Kc = 1/[CO2]
Show Answer

Correct: (B)

Pure solids are omitted from equilibrium expressions, leaving only the gaseous product.

Q43For 2 NO(g) + Br2(g) ⇌ 2 NOBr(g), the equilibrium concentrations are [NO] = 0.10 M, [Br2] = 0.20 M, and [NOBr] = 0.60 M. What is the value of Kc?

(A) 18
(B) 60
(C) 90
(D) 180
Show Answer

Correct: (D)

Kc = [NOBr]^2/([NO]^2[Br2]) = (0.60)^2/((0.10)^2(0.20)) = 0.36/0.002 = 180.

Q44For 2 H2(g) + O2(g) ⇌ 2 H2O(g), Kc = 2.4 × 10^47 at 500 K. What is Kp at this temperature? (R = 0.0821 L·atm/mol·K)

(A) 9.9 × 10^48
(B) 1.4 × 10^44
(C) 5.8 × 10^45
(D) 2.4 × 10^47
Show Answer

Correct: (C)

Δn = 2 − 3 = −1, so Kp = Kc(RT)^−1 = (2.4 × 10^47)/(0.0821 × 500) = 5.8 × 10^45.

Q45Consider N2(g) + O2(g) ⇌ 2 NO(g), ΔH° = +181 kJ/mol. Which change will increase the equilibrium concentration of NO?

(A) Increasing the temperature
(B) Decreasing the temperature
(C) Increasing the total pressure
(D) Adding a catalyst
Show Answer

Correct: (A)

The reaction is endothermic, so higher temperature shifts equilibrium toward products; pressure has no effect since Δn = 0.

Q46For PCl5(g) ⇌ PCl3(g) + Cl2(g), Kc = 0.045 at 250°C. A flask initially contains 0.60 M PCl5 and no products. What is [Cl2] at equilibrium?

(A) 0.027 M
(B) 0.14 M
(C) 0.21 M
(D) 0.30 M
Show Answer

Correct: (B)

x^2/(0.60 − x) = 0.045 gives x^2 + 0.045x − 0.027 = 0, so x = 0.14 M = [Cl2].

Q47For CO(g) + H2O(g) ⇌ CO2(g) + H2(g), Kc = 5.1 at 700 K. A mixture initially contains [CO] = 0.20 M, [H2O] = 0.20 M, [CO2] = 0.10 M, and [H2] = 0.10 M. Which statement is correct?

(A) Q = 0.25; the reaction proceeds toward reactants
(B) Q = 4.0; the reaction proceeds toward products
(C) Q = 0.25; the reaction proceeds toward products
(D) Q = 25; the system is at equilibrium
Show Answer

Correct: (C)

Q = ([CO2][H2])/([CO][H2O]) = (0.10)(0.10)/((0.20)(0.20)) = 0.25; since Q < K, the reaction proceeds toward products.

🧫 Acids, Bases & Buffers

Q48What is the pOH of a 0.0020 M Ba(OH)2 solution? (Assume complete dissociation.)

(A) 2.70
(B) 11.60
(C) 2.40
(D) 3.00
Show Answer

Correct: (C)

[OH^-] = 2(0.0020) = 0.0040 M; pOH = −log(4.0×10^-3) = 2.40.

Q49Which of the following aqueous mixtures acts as a buffer?

(A) 0.10 M HCN mixed with 0.10 M NaCN
(B) 0.10 M HCl mixed with 0.10 M NaCl
(C) 0.10 M NaCN only
(D) 0.10 M NH3 mixed with 0.10 M NaOH
Show Answer

Correct: (A)

It contains the weak acid HCN and its conjugate base CN^- in comparable amounts.

Q50A 0.050 M solution of the weak base NH3 has Kb = 1.8×10^-5. What is the pH of the solution?

(A) 8.72
(B) 11.30
(C) 12.70
(D) 10.98
Show Answer

Correct: (D)

[OH^-] = sqrt(Kb·C) = 9.5×10^-4 M, so pOH = 3.02 and pH = 14.00 − 3.02 = 10.98.

Q51For nitrous acid, HNO2, Ka = 4.5×10^-4. What is Kb for its conjugate base, NO2^-? (Kw = 1.0×10^-14)

(A) 4.5×10^-4
(B) 2.2×10^-11
(C) 2.2×10^-10
(D) 4.5×10^-10
Show Answer

Correct: (B)

Kb = Kw/Ka = (1.0×10^-14)/(4.5×10^-4) = 2.2×10^-11.

Q5220.0 mL of 0.10 M HCl is titrated with 0.10 M NaOH. What is the pH at the equivalence point?

(A) 4.50
(B) 9.20
(C) 5.00
(D) 7.00
Show Answer

Correct: (D)

A strong acid titrated with a strong base gives a neutral salt solution at equivalence.

Q53A buffer is prepared with [NH3] = 0.020 M and [NH4^+] = 0.20 M. If pKa = 9.25 for NH4^+, what is the pH?

(A) 10.25
(B) 9.25
(C) 8.25
(D) 7.30
Show Answer

Correct: (C)

pH = 9.25 + log(0.020/0.20) = 9.25 − 1.00 = 8.25.

🔋 Thermodynamics & Electrochemistry

Q54What is the sign of ΔS° for the reaction CaCO3(s) → CaO(s) + CO2(g)?

(A) negative
(B) positive
(C) approximately zero
(D) cannot be determined from the given information
Show Answer

Correct: (B)

A gas is produced from a solid with no gaseous reactant, so disorder increases.

Q55A reaction has ΔH° = +85 kJ/mol and ΔS° = +0.250 kJ/(mol·K). At which temperatures is the reaction spontaneous?

(A) only above 340 K
(B) only below 340 K
(C) at all temperatures
(D) at no temperature
Show Answer

Correct: (A)

ΔG = 0 at T = 85/0.250 = 340 K; with ΔH > 0 and ΔS > 0, ΔG < 0 only above 340 K.

Q56For the reaction Ni(s) + 2 Ag^+(aq) → Ni^2+(aq) + 2 Ag(s), E° = +0.80 V for Ag^+/Ag and E° = −0.25 V for Ni^2+/Ni. What is E°cell?

(A) 0.55 V
(B) 0.30 V
(C) 1.60 V
(D) 1.05 V
Show Answer

Correct: (D)

E°cell = E°cathode − E°anode = 0.80 − (−0.25) = 1.05 V.

Q57In the galvanic cell Zn|Zn^2+||Cu^2+|Cu, the concentration of Zn^2+ is increased while [Cu^2+] is held constant. What happens to the cell potential?

(A) It increases.
(B) It remains unchanged.
(C) It decreases.
(D) It immediately becomes zero.
Show Answer

Correct: (C)

By the Nernst equation, E = E° − (RT/nF) ln([Zn^2+]/[Cu^2+]); increasing [Zn^2+] raises Q and lowers E.

Q58What quantity of electric charge is required to deposit 9.0 g of aluminum from an Al^3+ solution? (Al^3+ + 3e^- → Al; molar mass of Al = 26.98 g/mol; F = 96,485 C/mol e^-)

(A) 3.22×10^4 C
(B) 9.65×10^4 C
(C) 2.90×10^5 C
(D) 1.93×10^5 C
Show Answer

Correct: (B)

Moles Al = 9.0/26.98 = 0.334 mol, requiring 3(0.334) = 1.00 mol e^-, so Q = 1.00 × 96,485 = 9.65×10^4 C.

☢ Nuclear & Descriptive Chemistry

Q59Which particle is emitted from the nucleus during positron emission?

(A) a positron
(B) an alpha particle
(C) a neutron
(D) a gamma photon
Show Answer

Correct: (A)

Positron emission ejects a positron (^0_+1e) as a proton converts into a neutron.

Q60A 120 g sample of a radioisotope with a half-life of 8.0 hours decays for 24 hours. What mass remains?

(A) 40.0 g
(B) 30.0 g
(C) 15.0 g
(D) 10.0 g
Show Answer

Correct: (C)

24/8.0 = 3 half-lives, so 120 × (1/2)^3 = 15.0 g remains.