ACS General Chemistry Practice Test 17

60 original exam-style multiple-choice questions with answers & explanations — covering every major topic tested on the ACS General Chemistry exam.

Note: These are original practice questions written in the ACS exam style — not reproduced exam questions. Use them to test your readiness for the real ACS General Chemistry exam.

📱 How to use: Try each question first, then click “Show Answer” to check. Covers: atomic structure, bonding, stoichiometry, gases, thermochemistry, kinetics, equilibrium, acids & bases, electrochemistry and more.

⚛ Atomic Structure & Periodic Trends

Q1Which of the following is the ground-state electron configuration of a neutral chromium atom?

(A) [Ar]4s2 3d4
(B) [Ar]4s1 3d5
(C) [Ar]3d6
(D) [Ar]4s2 3d3
Show Answer

Correct: (B)

A half-filled 3d subshell plus a half-filled 4s subshell is more stable than [Ar]4s2 3d4, so one 4s electron is promoted to 3d.

Q2Which element has the largest first ionization energy?

(A) Na
(B) Mg
(C) Al
(D) Ne
Show Answer

Correct: (D)

Ionization energy generally increases across a period and decreases down a group; neon, a Period 2 noble gas, has the highest first ionization energy of these.

Q3Which of the following lists the atoms in order of decreasing atomic radius?

(A) F > Cl > Br > I
(B) Cl > F > Br > I
(C) I > Br > Cl > F
(D) Br > I > Cl > F
Show Answer

Correct: (C)

Atomic radius increases down a group because additional electron shells are added, so iodine is the largest and fluorine the smallest.

Q4Which ion is NOT isoelectronic with a neon atom?

(A) F−
(B) Na+
(C) Mg2+
(D) Cl−
Show Answer

Correct: (D)

F−, Na+, and Mg2+ each have 10 electrons like neon, but Cl− has 18 electrons.

Q5A photon with a wavelength of 500. nm strikes a metal surface whose work function is 3.30 × 10−19 J. What is the kinetic energy of the ejected electron? (h = 6.626 × 10−34 J·s, c = 3.00 × 108 m/s)

(A) 6.8 × 10−20 J
(B) 3.98 × 10−19 J
(C) 3.30 × 10−19 J
(D) No electron is ejected
Show Answer

Correct: (A)

The photon energy is hc/λ = 3.98 × 10−19 J, which exceeds the work function, so KE = 3.98 × 10−19 − 3.30 × 10−19 = 6.8 × 10−20 J.

Q6Which set of quantum numbers (n, l, ml) is NOT possible for an electron in an atom?

(A) 3, 1, −1
(B) 3, 2, −3
(C) 4, 0, 0
(D) 2, 1, 1
Show Answer

Correct: (B)

The magnetic quantum number ml must satisfy |ml| ≤ l, so ml = −3 is impossible when l = 2.

🔬 Chemical Bonding & Molecular Geometry

Q7What is the molecular geometry of XeF4?

(A) Square planar
(B) Tetrahedral
(C) See-saw
(D) Square pyramidal
Show Answer

Correct: (A)

Xenon has 6 electron domains (4 bonding pairs + 2 lone pairs); the two lone pairs occupy axial positions of the octahedral arrangement, leaving a square planar shape.

Q8What is the hybridization of the sulfur atom in SF4?

(A) sp
(B) sp2
(C) sp3
(D) sp3d
Show Answer

Correct: (D)

Sulfur has 5 electron domains (4 bonding pairs + 1 lone pair), which requires sp3d hybridization.

Q9Which molecule has a nonzero net dipole moment?

(A) CO2
(B) BF3
(C) H2O
(D) CCl4
Show Answer

Correct: (C)

H2O is bent, so its bond dipoles do not cancel; the other three are symmetric and nonpolar.

Q10Which species has the shortest carbon–oxygen bond?

(A) CH3OH
(B) CO
(C) CO2
(D) HCO3−
Show Answer

Correct: (B)

Carbon monoxide has a C≡O triple bond (bond order 3), and bond length decreases as bond order increases.

Q11How many lone pairs are on the central xenon atom in XeF2?

(A) 3
(B) 2
(C) 1
(D) 0
Show Answer

Correct: (A)

Xenon contributes 8 valence electrons and each F contributes 1, giving 5 electron domains (2 bonding + 3 lone pairs) in a linear arrangement.

Q12In the best Lewis structure of the nitrate ion, NO3−, what is the formal charge on the nitrogen atom?

(A) −1
(B) 0
(C) +1
(D) +2
Show Answer

Correct: (C)

Formal charge = 5 − (0 + 8/2) = +1; the negative charge of the ion is distributed over the oxygen atoms.

Q13Which bond is the most polar?

(A) C–F
(B) O–H
(C) N–H
(D) C–Cl
Show Answer

Correct: (A)

The C–F bond has the largest electronegativity difference (4.0 − 2.5 = 1.5), giving it the greatest bond polarity.

🧪 Stoichiometry & Aqueous Reactions

Q14What mass of CO2 is produced when 25.0 g of CaCO3 decomposes completely according to CaCO3 → CaO + CO2?

(A) 22.0 g
(B) 5.50 g
(C) 11.0 g
(D) 25.0 g
Show Answer

Correct: (C)

25.0 g CaCO3 ÷ 100.09 g/mol = 0.2498 mol, producing 0.2498 mol × 44.01 g/mol = 11.0 g of CO2.

Q15How many moles of H2O can be formed from 4.0 mol of H2 and 1.5 mol of O2 in the reaction 2H2 + O2 → 2H2O?

(A) 1.5 mol
(B) 3.0 mol
(C) 4.0 mol
(D) 6.0 mol
Show Answer

Correct: (B)

O2 is limiting (1.5 mol O2 requires only 3.0 mol H2), so 2 × 1.5 = 3.0 mol of H2O forms.

Q16What is the molarity of the solution when 50.0 mL of 3.00 M NaOH is diluted with water to a final volume of 250. mL?

(A) 0.600 M
(B) 0.750 M
(C) 1.20 M
(D) 15.0 M
Show Answer

Correct: (A)

M2 = M1V1/V2 = (3.00 M)(50.0 mL)/(250. mL) = 0.600 M.

Q17What is the net ionic equation for the reaction of aqueous silver nitrate with aqueous sodium chloride?

(A) Na+(aq) + NO3−(aq) → NaNO3(aq)
(B) AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
(C) Ag+(aq) + Cl−(aq) → AgCl(s)
(D) Ag+(aq) + NO3−(aq) + Na+(aq) + Cl−(aq) → AgCl(s) + NaNO3(aq)
Show Answer

Correct: (C)

AgCl precipitates; Na+ and NO3− are spectator ions and cancel from the net ionic equation.

Q18What is the oxidation number of chromium in K2Cr2O7?

(A) +3
(B) +4
(C) +5
(D) +6
Show Answer

Correct: (D)

With K at +1 and O at −2: 2(+1) + 2x + 7(−2) = 0 gives x = +6.

Q19A compound contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is its empirical formula?

(A) CHO
(B) C2H6O
(C) CH2O
(D) C2H4O2
Show Answer

Correct: (C)

The mole ratio is 3.33 mol C : 6.7 mol H : 3.33 mol O, which simplifies to 1:2:1, giving CH2O.

Q20How many milliliters of 0.200 M H2SO4 are required to neutralize 30.0 mL of 0.100 M NaOH? (H2SO4 + 2NaOH → Na2SO4 + 2H2O)

(A) 15.0 mL
(B) 30.0 mL
(C) 3.75 mL
(D) 7.50 mL
Show Answer

Correct: (D)

3.00 mmol NaOH requires 1.50 mmol H2SO4 (2:1 ratio), and 1.50 mmol ÷ 0.200 M = 7.50 mL.

🌀 Gases & Intermolecular Forces

Q21What is the volume occupied by 0.500 mol of an ideal gas at 2.00 atm and 300. K? (R = 0.08206 L·atm/mol·K)

(A) 12.3 L
(B) 3.08 L
(C) 6.15 L
(D) 24.6 L
Show Answer

Correct: (C)

V = nRT/P = (0.500)(0.08206)(300.)/(2.00) = 6.15 L.

Q22Which gas effuses the fastest at the same temperature?

(A) O2
(B) N2
(C) CH4
(D) He
Show Answer

Correct: (D)

By Graham's law, effusion rate is inversely proportional to the square root of molar mass, so helium (4.00 g/mol) is fastest.

Q23Which gas would show the greatest deviation from ideal behavior at high pressure and low temperature?

(A) H2
(B) Xe
(C) Ne
(D) N2
Show Answer

Correct: (B)

Xenon has the largest, most polarizable electron cloud, so its intermolecular attractions cause the largest deviation from ideality.

Q24Which liquid has the highest boiling point?

(A) CH3CH3
(B) CH3OCH3
(C) CH3CH2F
(D) CH3CH2OH
Show Answer

Correct: (D)

Ethanol can hydrogen bond, the strongest intermolecular force among these choices, giving it the highest boiling point.

Q25A gas mixture contains 2.0 mol N2 and 3.0 mol O2 at a total pressure of 750 torr. What is the partial pressure of O2?

(A) 300 torr
(B) 450 torr
(C) 500 torr
(D) 750 torr
Show Answer

Correct: (B)

By Dalton's law, PO2 = (3.0/5.0) × 750 torr = 450 torr.

🔥 Thermochemistry

Q26How much heat is absorbed when 100.0 g of water is heated from 25.0°C to 35.0°C? (specific heat of water = 4.184 J/g·°C)

(A) 41.8 kJ
(B) 10.5 kJ
(C) 418 J
(D) 4.18 kJ
Show Answer

Correct: (D)

q = mcΔT = (100.0 g)(4.184 J/g·°C)(10.0°C) = 4184 J = 4.18 kJ.

Q27For which process is ΔH negative?

(A) Combustion of propane
(B) Melting of ice
(C) Vaporization of water
(D) Sublimation of dry ice
Show Answer

Correct: (A)

Combustion releases heat to the surroundings, so it is exothermic and ΔH < 0; the others absorb heat.

Q28Given (1) C(s) + O2(g) → CO2(g), ΔH = −393.5 kJ and (2) CO(g) + ½O2(g) → CO2(g), ΔH = −283.0 kJ, what is ΔH for C(s) + ½O2(g) → CO(g)?

(A) −676.5 kJ
(B) +110.5 kJ
(C) −110.5 kJ
(D) −283.0 kJ
Show Answer

Correct: (C)

By Hess's law, subtract reaction (2) from reaction (1): −393.5 − (−283.0) = −110.5 kJ.

Q29Using ΔHf° values, what is ΔH°rxn for 2H2(g) + O2(g) → 2H2O(l)? (ΔHf°[H2O(l)] = −285.8 kJ/mol)

(A) −571.6 kJ
(B) −285.8 kJ
(C) +571.6 kJ
(D) −1143 kJ
Show Answer

Correct: (A)

ΔH°rxn = 2(−285.8) − 0 = −571.6 kJ, since elements in standard states have ΔHf° = 0.

Q30The same quantity of heat is added to each of the following samples. Which undergoes the smallest temperature increase?

(A) 50.0 g Cu (c = 0.385 J/g·°C)
(B) 100.0 g Cu (c = 0.385 J/g·°C)
(C) 50.0 g Fe (c = 0.449 J/g·°C)
(D) 50.0 g Al (c = 0.897 J/g·°C)
Show Answer

Correct: (D)

Temperature change is q/(mc); 50.0 g Al has the largest heat capacity (44.9 J/°C), so it warms the least.

Q31Use the average bond enthalpies below to estimate ΔH° for the gas-phase reaction H2(g) + Br2(g) → 2HBr(g). Bond enthalpies (kJ/mol): H−H = 436, Br−Br = 193, H−Br = 366.

(A) +103 kJ
(B) −103 kJ
(C) −206 kJ
(D) +206 kJ
Show Answer

Correct: (B)

ΔH = (bonds broken) − (bonds formed) = (436 + 193) − 2(366) = −103 kJ; the reaction is exothermic because two strong H−Br bonds form.

⚡ Quantum Theory & Electronic Structure

Q32The work function of a certain metal is 3.20 eV. Light of wavelength 300 nm strikes the metal surface. What is the maximum kinetic energy of an ejected electron? (hc = 1240 eV·nm)

(A) 0.13 eV
(B) 0.56 eV
(C) 0.94 eV
(D) 3.20 eV
Show Answer

Correct: (C)

Photon energy = 1240/300 = 4.13 eV; KE = hν − work function = 4.13 − 3.20 = 0.93 eV (photoelectric effect).

Q33Which set of quantum numbers (n, l, ml, ms) is allowed for an electron in an atom?

(A) 2, 2, 0, +1/2
(B) 3, 1, +2, −1/2
(C) 4, 3, −4, +1/2
(D) 3, 2, −1, −1/2
Show Answer

Correct: (D)

Valid sets require l < n, |ml| ≤ l; only (D) satisfies all quantum number rules.

Q34The Fe3+ ion has five unpaired electrons. Which of the following species has the same number of unpaired electrons?

(A) Mn2+
(B) Fe2+
(C) Cr3+
(D) Zn2+
Show Answer

Correct: (A)

Mn2+ is [Ar]3d5 with five unpaired electrons, matching the d5 configuration of Fe3+ (Hund's rule maximizes unpaired electrons in degenerate orbitals).

Q35What is the de Broglie wavelength of an electron traveling at 2.00×10^6 m/s? (h = 6.626×10^−34 J·s; me = 9.109×10^−31 kg)

(A) 1.8×10^−10 m
(B) 3.6×10^−10 m
(C) 7.3×10^−10 m
(D) 1.2×10^−7 m
Show Answer

Correct: (B)

λ = h/mv = 6.626×10^−34 / (9.109×10^−31 × 2.00×10^6) = 3.64×10^−10 m.




⏱ Chemical Kinetics

Q36A reaction proceeds by the mechanism: Step 1: A + B ⇌ C (fast equilibrium); Step 2: C → D (slow). What is the rate law for the overall reaction?

(A) rate = k[A]^2
(B) rate = k[B]
(C) rate = k[A][B]
(D) rate = k[A][B]/[C]
Show Answer

Correct: (C)

The slow step gives rate = k2[C], and the fast pre-equilibrium gives [C] proportional to [A][B], so the overall rate law is first order in each reactant.

Q37For a first-order decomposition, the concentration of reactant falls from 0.80 M to 0.20 M in 240 s. What is the half-life of the reaction?

(A) 60 s
(B) 80 s
(C) 240 s
(D) 120 s
Show Answer

Correct: (D)

Falling from 0.80 to 0.20 M is two half-lives (0.80 → 0.40 → 0.20), so t1/2 = 240/2 = 120 s.

Q38The rate constant for a reaction is 2.0×10^−3 s^−1 at 300 K and 4.0×10^−3 s^−1 at 310 K. What is the activation energy? (R = 8.314 J/mol·K)

(A) 54 kJ/mol
(B) 27 kJ/mol
(C) 108 kJ/mol
(D) 6.2 kJ/mol
Show Answer

Correct: (A)

From the two-point Arrhenius equation, Ea = R·ln(k2/k1)/(1/T1 − 1/T2) = 8.314·ln2/(1/300 − 1/310) = 5.4×10^4 J/mol.

Q39For a reaction that is second order in a single reactant A, which plot gives a straight line?

(A) ln[A] vs. time
(B) 1/[A] vs. time
(C) [A] vs. time
(D) [A]^2 vs. time
Show Answer

Correct: (B)

The integrated second-order rate law is 1/[A]t = kt + 1/[A]0, so 1/[A] vs. t is linear with slope k.

Q40For the reaction 2NO(g) + O2(g) → 2NO2(g), the following initial-rate data were obtained: Exp 1: [NO] = 0.10 M, [O2] = 0.10 M, rate = 0.020 M/s; Exp 2: [NO] = 0.20 M, [O2] = 0.10 M, rate = 0.080 M/s; Exp 3: [NO] = 0.10 M, [O2] = 0.20 M, rate = 0.040 M/s. What is the rate law?

(A) rate = k[NO][O2]
(B) rate = k[NO]^2[O2]^2
(C) rate = k[O2]
(D) rate = k[NO]^2[O2]
Show Answer

Correct: (D)

Doubling [NO] quadruples the rate (second order in NO); doubling [O2] doubles the rate (first order in O2).

Q41Which statement about a catalyst is correct?

(A) It provides an alternative reaction pathway with a lower activation energy and is regenerated at the end.
(B) It shifts the position of equilibrium toward the products.
(C) It increases the enthalpy change of the reaction.
(D) It is consumed stoichiometrically during the reaction.
Show Answer

Correct: (A)

A catalyst lowers Ea by offering a different mechanism but does not change ΔH, K, or appear in the net equation.

⇆ Chemical Equilibrium

Q42For N2(g) + 3H2(g) ⇌ 2NH3(g) at equilibrium, [N2] = 0.10 M, [H2] = 0.20 M, and [NH3] = 0.40 M. What is Kc?

(A) 5.0×10^−3
(B) 2.0×10^2
(C) 40
(D) 100
Show Answer

Correct: (B)

Kc = [NH3]^2/([N2][H2]^3) = (0.40)^2/(0.10 × 0.20^3) = 0.16/8.0×10^−4 = 200.

Q43Consider 2SO2(g) + O2(g) ⇌ 2SO3(g), ΔH° < 0. Which change will increase the equilibrium yield of SO3?

(A) Increasing the volume of the container
(B) Adding an inert gas at constant volume
(C) Decreasing the temperature
(D) Adding a catalyst
Show Answer

Correct: (C)

The reaction is exothermic, so lowering the temperature shifts equilibrium toward products (Le Châtelier's principle); catalysts and inert gas at constant V do not shift K.

Q44The Ksp of the sparingly soluble salt AB3 (which dissociates as AB3(s) ⇌ A3+ + 3B−) is 2.7×10^−9. What is its molar solubility?

(A) 3.2×10^−3 M
(B) 5.2×10^−3 M
(C) 1.0×10^−3 M
(D) 7.3×10^−4 M
Show Answer

Correct: (A)

Ksp = (s)(3s)^3 = 27s^4, so s = (2.7×10^−9/27)^1/4 = (1.0×10^−10)^1/4 = 3.2×10^−3 M.

Q45For the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g), what is the relationship between Kp and Kc?

(A) Kp = Kc
(B) Kp = Kc(RT)^−1
(C) Kp = Kc(RT)^−2
(D) Kp = Kc(RT)
Show Answer

Correct: (D)

Kp = Kc(RT)^Δn with Δn = (1 + 1) − 1 = +1, so Kp = Kc(RT).

Q46For 2A(g) + B(g) ⇌ 3C(g), Kc = 4.0×10^3. At a certain moment, [A] = 0.50 M, [B] = 0.20 M, and [C] = 2.0 M. In which direction will the reaction proceed?

(A) Toward reactants (left)
(B) Toward products (right)
(C) It is already at equilibrium
(D) The reverse reaction is favored because Q > K
Show Answer

Correct: (B)

Q = [C]^3/([A]^2[B]) = 8.0/(0.25 × 0.20) = 160 < Kc, so the system shifts right to reach equilibrium.

Q47What is the equilibrium constant expression for CaCO3(s) ⇌ CaO(s) + CO2(g)?

(A) Kc = [CaO][CO2]/[CaCO3]
(B) Kc = [CaO][CO2]
(C) Kc = [CO2]
(D) Kc = [CaCO3]/([CaO][CO2])
Show Answer

Correct: (C)

Pure solids are omitted from equilibrium expressions, leaving Kc = [CO2] (heterogeneous equilibrium).

🧫 Acids, Bases & Buffers

Q48What is the pH of a 0.10 M solution of a weak acid HA with Ka = 1.8×10^−5?

(A) 1.00
(B) 4.74
(C) 5.00
(D) 2.87
Show Answer

Correct: (D)

[H+] ≈ √(Ka·C) = √(1.8×10^−6) = 1.34×10^−3 M, so pH = 2.87.

Q49The Ka of the ammonium ion (NH4+) is 5.6×10^−10. What is the Kb of ammonia (NH3)?

(A) 1.8×10^−5
(B) 5.6×10^−10
(C) 1.8×10^−9
(D) 5.6×10^−4
Show Answer

Correct: (A)

For a conjugate pair, Ka·Kb = Kw, so Kb = 1.0×10^−14/5.6×10^−10 = 1.8×10^−5.

Q50Which of the following mixtures constitutes a buffer solution?

(A) 0.10 M HCl and 0.10 M NaCl
(B) 0.10 M NaOH and 0.10 M CH3COONa
(C) 0.10 M CH3COOH and 0.10 M CH3COONa
(D) 0.10 M HNO3 and 0.10 M KNO3
Show Answer

Correct: (C)

A buffer requires a weak acid and its conjugate base (or weak base and conjugate acid); only (C) contains such a pair.

Q51In the titration of a weak acid with a strong base, the pH at the equivalence point is

(A) less than 7
(B) greater than 7
(C) exactly 7
(D) equal to the pKa of the acid
Show Answer

Correct: (B)

At the equivalence point only the conjugate base remains, and its hydrolysis produces OH−, making the solution basic.

Q52What is the pH of a buffer containing 0.20 M CH3COOH and 0.10 M CH3COONa? (Ka = 1.8×10^−5)

(A) 5.04
(B) 4.74
(C) 5.35
(D) 4.44
Show Answer

Correct: (D)

By the Henderson–Hasselbalch equation, pH = pKa + log([base]/[acid]) = 4.74 + log(0.10/0.20) = 4.44.

Q53A 0.50 M solution of HF is 4.0% ionized. What is the Ka of HF?

(A) 8.3×10^−4
(B) 3.2×10^−4
(C) 1.6×10^−3
(D) 4.0×10^−2
Show Answer

Correct: (A)

[H+] = 0.50 × 0.040 = 0.020 M; Ka = (0.020)^2/(0.50 − 0.020) = 8.3×10^−4.

🔋 Thermodynamics & Electrochemistry

Q54What is the sign of ΔS° for the reaction 2H2O2(l) → 2H2O(l) + O2(g)?

(A) Negative
(B) Zero
(C) Positive
(D) Cannot be determined from the equation
Show Answer

Correct: (C)

A gas is produced from liquids only, increasing the number of microstates, so entropy increases.

Q55A reaction has ΔH° = +91 kJ/mol and ΔS° = +190 J/mol·K. Above what temperature does the reaction become spontaneous?

(A) Below 210 K
(B) Above 480 K
(C) At all temperatures
(D) At no temperature
Show Answer

Correct: (B)

Spontaneity requires ΔG = ΔH − TΔS < 0; with both terms positive this occurs when T > ΔH/ΔS = 91000/190 ≈ 480 K.

Q56Given Zn2+ + 2e− → Zn, E° = −0.76 V and Cu2+ + 2e− → Cu, E° = +0.34 V, what is E°cell for the spontaneous Zn–Cu galvanic cell?

(A) −1.10 V
(B) +0.42 V
(C) −0.42 V
(D) +1.10 V
Show Answer

Correct: (D)

E°cell = E°cathode − E°anode = (+0.34) − (−0.76) = +1.10 V (Cu2+ is reduced, Zn is oxidized).

Q57For the Zn–Cu galvanic cell (E°cell = 1.10 V) at 25°C with [Zn2+] = 1.0 M and [Cu2+] = 0.010 M, what is the cell potential?

(A) 1.04 V
(B) 1.16 V
(C) 1.10 V
(D) 0.98 V
Show Answer

Correct: (A)

By the Nernst equation, E = E° − (0.0592/2)log([Zn2+]/[Cu2+]) = 1.10 − 0.0296·log(100) = 1.04 V.

Q58A current of 0.500 A is passed through molten CuSO4 for 30.0 minutes. What mass of copper metal is deposited at the cathode? (Cu = 63.55 g/mol)

(A) 0.592 g
(B) 0.148 g
(C) 0.296 g
(D) 1.18 g
Show Answer

Correct: (C)

Charge = 0.500 × 1800 = 900 C = 9.33×10^−3 mol e−; Cu2+ requires 2 e−, giving 4.66×10^−3 mol Cu = 0.296 g (Faraday's law).

☢ Nuclear & Descriptive Chemistry

Q59Plutonium-239 undergoes alpha decay. Which equation correctly represents this nuclear reaction?

(A) ^239Pu → ^239Pu + ^4He
(B) ^239Pu → ^239Np + β
(C) ^239Pu → ^238Pu + n
(D) ^239Pu → ^235U + ^4He
Show Answer

Correct: (D)

Alpha emission reduces the mass number by 4 and the atomic number by 2: ^239(94)Pu → ^235(92)U + ^4(2)He.

Q60Which oxide dissolves in both aqueous sodium hydroxide and aqueous hydrochloric acid?

(A) CO2
(B) Al2O3
(C) MgO
(D) SO2
Show Answer

Correct: (B)

Al2O3 is amphoteric, reacting with both strong acids and strong bases; CO2 and SO2 are acidic oxides, MgO is basic.